Arclength of Parametric Curves

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  • Опубліковано 17 січ 2025

КОМЕНТАРІ • 20

  • @khaledfarrag9754
    @khaledfarrag9754 5 років тому +16

    I think there is something wrong
    in the last equation
    The second term of g'(t)=3t^2-3
    Thank you for your efforts

    • @khaledfarrag9754
      @khaledfarrag9754 5 років тому

      Could you sir make series of types
      of geometry especially the descriptive geometry and affine
      Geometry and analytical geometry

    • @averydrago
      @averydrago 3 роки тому +1

      I dont think there was anything wrong, he just accidentally said 3t cubed

    • @theleviathan3902
      @theleviathan3902 2 роки тому +2

      @averydrago no it should've been the derivative of the y function, he just accidentally put the unaltered y function

  • @TheNSAisWatching
    @TheNSAisWatching 5 років тому +2

    I really enjoy your videos.. you explain concepts very thoroughly.

  • @gobyg-major2057
    @gobyg-major2057 2 роки тому +1

    4:45 actually it’s 3 t square-3*, not 3t cubed -3

  • @balacharya1395
    @balacharya1395 3 роки тому +1

    Would you please make videos on tensor analysis

  • @enyioma8
    @enyioma8 3 роки тому +2

    Yup.... Dr. Bazett is awesome

  • @ordinaryguy4181
    @ordinaryguy4181 5 років тому

    I got too much help from your videos. Thanks for that!

  • @jacobschmitt9983
    @jacobschmitt9983 4 роки тому +1

    at 4:55, why are is x=3? I'm confused on where this came from.

    • @Yzurra
      @Yzurra 4 роки тому

      Based on the graph. There is a point on the curve (3,0) that we can use to find the values of t. The x value of that is 3.

  • @ОрландоОрсо
    @ОрландоОрсо 3 роки тому +1

    I think you did a mistake when calculate arclength. You substitude in formula expressions for f'(t) and g(t), but should substitude expressions for f'(t) and g'(t).
    Correct value for arclength not 8.98. It is 10.7351.

  • @hudachanna4918
    @hudachanna4918 4 роки тому

    Why is t* for x and why is it t** for y? Why are they not the same?

  • @XavierXe
    @XavierXe 4 роки тому

    How is ∆x=f'(t)∆t
    By the way your videos are awesome

    • @OriginalEch3Official
      @OriginalEch3Official 4 роки тому

      x here is dependant of t, so x is really x(t) (aka function), meaning x’ != 0. Δx(t)/Δt=f’(t)

    • @XavierXe
      @XavierXe 4 роки тому +1

      @@OriginalEch3Official lol i now Passed my exam
      Thank you 😊

    • @OriginalEch3Official
      @OriginalEch3Official 4 роки тому +1

      @@XavierXe haha gratz man! I have calc 2 this semester :D