@@ajdk2385 see we have to solve v=ir where v is voltage with dimensions M¹L²T-³A-¹ AND I is current with dimensions A¹ so we have to find R formula will be R=V÷I so after just by placing dimensions we just have to move A¹ from denominator to numerator we get M¹L²T-³A-²
Homework - 1. V = [ML²T-³A-¹] 2. C = [A²T4L-²M-¹] 3. R = [ML²T-³A-²] 4. [M¹L²T-²] = [M¹L²T-² L.H.S = R.H.S DIMENSIONALLY CORRECT 5. 1 JOULES = 10^7 ERGS 6. 1 PASCAL = 10 CGS PRESSURE 7. P = [M(h g rho)] Superb session suri sir✨💖💖 No words for ur great explanation 😊 By the way jitna time homework krne me nhi laga usse Jyada usse type krne me lag gya😅😅..
SIR I HAVE THIS DOUBTH PLZ TELL A DIMENSIONALLY CONSISTENT RELATION FOR THE VOLUME (V) OF A LIQUID OF VISCOSITY FLOWING PER SEC. THROUGH A CUBE OF RADIUS(R) AND LENGTH(L) AND HAVING A PRESURE DIFF.(P) ACROSS ITS END IS
![Units and Dimensions - [Part 3/3] | Umang 11 | Class 11 | Suri Sir | @VedantuMath](http://i.ytimg.com/vi/F1se_dWS0Jk/mqdefault.jpg)
![Units and Dimensions - [Part 3/3] | Umang 11 | Class 11 | Suri Sir | @VedantuMath](/img/tr.png)
Homework answers :
1) Dimensions of V = [ ML²T-³A-¹ ]
2) Dimensions of C = [ M-¹L-²T⁴A² ]
3) Dimensions of R = [ML²T-³A-²]
4) F =mv²/r
LHS: F = [MLT-²]
RHS: mv²/r = [ML²T-²]/[L] = [MLT-²]
LHS=RHS, hence, it is dimensionally correct.
5) 1Joules = y ergs
1 [M1L²1T-²1] = y[M2L²2T-²2]
y = (M1/M2)¹ (L1/L2)² (T1/T2)-²
y = (1000g/1g)¹ (100cm/1cm)² (1s/1s)-²
y = 10³ × 10⁴ = 10⁷
1 joules = 10⁷ ergs
6) 1 Pascal = z cgs pressure
1[M1L-¹1T-²1] = z [M2L-¹2T-²2]
z = (M1/M2)¹ (L1/L2)-¹ (T1/T2)-²
z = (1000g/1g)¹ (100cm/1cm)-¹ (1s/1s)-²
z = 10
1 Pascal = 10 cgs pressure
7) P = k(h g rho)
P = k [L]^x [LT-²]^y [ML-³]^z
[ML-¹T-²] = k [M]^z [ L]^x+y-3z [T]^-2y
[z = 1],
-2 = -2y => [y =1]
-1 = x+y-3z => -1 = x+1-3 => -1 = x-2 => [x =1]
[ P = k ( h g rho) ]
Session was Amazing 🔥
Thank you 🙂
ALL ANSWERS ARE CORRECT AND INDEED , THE SESSION WAS AMAZING
3) DImension of R = M L2 T-4 A-2 right?
@@ajdk2385no
@@yuvrajsen1800 why
@@ajdk2385 see we have to solve v=ir where v is voltage with dimensions M¹L²T-³A-¹ AND I is current with dimensions A¹ so we have to find R formula will be R=V÷I so after just by placing dimensions we just have to move A¹ from denominator to numerator we get M¹L²T-³A-²
HOMEWORK
1)AT 20:48
a) V=M1 L2 T-3 A-1
b) C=M-1 L-2 A2 T4
c) R=M1 L2 T-3 A-2
2)AT 32:00
LHS
=> M1 L1 T-2
RHS
=> (M1 L2 T-2)/L1
=> M1 L1 T-2
HENCE PROVED
3)AT 46:00
1)Q=n1u1=n2u2
=> 1 (M/M)1 (L/L)2 (T/T)-2 = y
=> 1(1000g/1g)1 (100cm/1cm)2 (1sec/1sec)-2 =y
=> 1 (1000)(10000)=y
=> 10 raised to the power 7 =y
AT 46:14
2)Q=n1u1=n2u2
=> 1 (M/M)1 (L/L)-1 (T/T)-2 =z
=> 1 (1000g/1g)(1cm/100cm)(1sec/1sec)-2=z
=> 10=z
4) P is proportional to (h)x (g)y (rho)z
=> P= k((h)x (g)y (rho)z) (k = dimensionless quantity)
M1 L-1 T-2 = (L)x+y-3z (T)-2y (M)z
Comparing both sides
(M)z= M1
=> z=1
(T)-2y=(T)-2
=> y=1
(L)x+y-3z=(L)-1
=> x+1-3=-1
=> x=2-1
=> x=1
Hence the equation formed is
P=k((h)(g)(rho))
wow
wow
wow
Hats off bacche 🙂
Can you tell me how T is -2y in 4que 🥲
@@BhautikShastra Thank you sir
Sir please bring sessions more faster
Yes sir please
Yes sir
Session Start from- 9:00 this time for previous homework.
New start from - 22:00
Homework -
1. V = [ML²T-³A-¹]
2. C = [A²T4L-²M-¹]
3. R = [ML²T-³A-²]
4. [M¹L²T-²] = [M¹L²T-²
L.H.S = R.H.S
DIMENSIONALLY CORRECT
5. 1 JOULES = 10^7 ERGS
6. 1 PASCAL = 10 CGS PRESSURE
7. P = [M(h g rho)]
Superb session suri sir✨💖💖
No words for ur great explanation 😊
By the way jitna time homework krne me nhi laga usse Jyada usse type krne me lag gya😅😅..
👌👌nice session sir
force = mv^2 / r is dimensionally correct
amazinggg session sirr thank you mogambo
34:0 yes dimenshonaly correct
Could someone suggest some synonyms for Awesome ??
Need them to specify the session.
amazing,wonderful,astonishing
Flashy
SIR I HAVE THIS DOUBTH PLZ TELL
A DIMENSIONALLY CONSISTENT RELATION FOR THE VOLUME (V) OF A LIQUID OF VISCOSITY FLOWING PER SEC. THROUGH A CUBE OF RADIUS(R) AND LENGTH(L) AND HAVING A PRESURE DIFF.(P) ACROSS ITS END IS
Sir awesome session
Don't mind, I'm telling you one thing that don't follow this teacher for your physics.
@@jyotirmoysaha9401 why? if there's a particular reason please tell.
@@abhinavdash1886 you will know about it just wait a little.
@@jyotirmoysaha9401 we can't follow without a reason, give a reason
Yes don't disrespect a teacher loke this
6:20 is the funny part of the section🤣🤣🤣🤣🤣
And nice section sir🙂🙂👍🏻✌🏻
Watch the likes of akr sessions and suri sir sessions . This will tell us who teach more better physics
Thanku sir.....
Yo 🤘
Update the notes please 🙏
Is the Vquiz working???
No
Sir is this ncert physics?
CBSE/JEE/NEET
Amazing session sir ❤️
Thanku sir
35:29
Sir principle of homeginity
I was missing akr and his efforts which he used to give during teaching 😔😔😔
Yah bro
Sir V quiz work ny kr ra
PDFs
Do I need app to used DPP
I can't use it since they don't send the OTP on my no. T-T
Sir aap konse engineer ho
+1
very nice session sir enjoyed a lot