Just to add, the other simpler (imo) method of solving this question is to let b = cross product of the two normals and a = point on the line obtained from setting x,y or z = 0 then solving for the remaining two variables
I know its not revalvent to you anymore but as a reference to others. YES. if you take the cross product of 2 normal vectors you will get a direction which is perpendicular to to both plane normal which is just PARALLELL to them. once you have the direction all you need is a point and bobs ur uncle :)
is there no way of finding a common point for the two and then just using the vector product of the normal vectors for the direction of the line? thanks
You are basically doing that here by converting to cartesian form and letting x = lamda and finding a general point in terms of lamda. You could then set lamda to a numerical value say 1 then get the values of y and z. Then go on to do the vector product of the normals but it will turn out to be a vector in the same ratio as the one in the example 2i+7j+3k. Another method yes but I feel that it is slightly longer. Best way is to try it and see what you think.
Can I use another method involving cross product and finding a point common to both planes?? I did that and i got a very different answer which is r=(4 0 0)+λ(-2 -7 -3). Is this answer correct?
lol you car hear birds chirping in the back
This man saves lives
Exams in 10days hahahha
How did it go?
A brilliant explanation; thank you!
Thank you!!! This was a huge help :)
Just to add, the other simpler (imo) method of solving this question is to let b = cross product of the two normals and a = point on the line obtained from setting x,y or z = 0 then solving for the remaining two variables
Amazing and helpful videos, love watching them. U gonna help me pass my exams in next 1-2 hours. Thx
excellent!
Thank you again Poka!
Yes Sir thank you very very much!
if for example i have -y+14/3.5 then what will happen pls awnser
maybe i shouldn't have chosen further maths
Appreciate the videos.
incredibly useful video
Thank you this is amazing! You are great!
Thanks for watching. Pleased it helped.
Hi sir , can you find the direction vector of the line using vector product of two normal vector of the planes .since they both plane intersect
I know its not revalvent to you anymore but as a reference to others. YES. if you take the cross product of 2 normal vectors you will get a direction which is perpendicular to to both plane normal which is just PARALLELL to them. once you have the direction all you need is a point and bobs ur uncle :)
is there no way of finding a common point for the two and then just using the vector product of the normal vectors for the direction of the line? thanks
You are basically doing that here by converting to cartesian form and letting x = lamda and finding a general point in terms of lamda. You could then set lamda to a numerical value say 1 then get the values of y and z. Then go on to do the vector product of the normals but it will turn out to be a vector in the same ratio as the one in the example 2i+7j+3k. Another method yes but I feel that it is slightly longer. Best way is to try it and see what you think.
If you were to let y = lambda, you would get a completely different answer? Is this also valid?
it just appears to be different but after rearranging itll be the same as what he calculated
Hi, Is the answer r=(4i)+ t(2i+5j+3k) got using Gaussian elimination also valid sir?
Love your videos, so awesome. :)
Yes
Please do the ones you haven't finished yet. The rest of vectors i mean. Exams are coming up and i have major problems in that part :'(
Can I use another method involving cross product and finding a point common to both planes?? I did that and i got a very different answer which is r=(4 0 0)+λ(-2 -7 -3). Is this answer correct?
u prob dont need this since u prob already graduated lmao but it looks wrong
ah my brain hurts..thanks btw
looooll same here but i understand it
❤
marza
By the time you do your calculations we will be dead 💀
Math is hell 😭