What is a Joule? An Explanation

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  • Опубліковано 5 вер 2024
  • This video goes over an explanation of the metric unit for work and energy which is the joule. The joule is the derived unit in the metric system for work and energy. Work is done on an object when a force is applied to an object through a distance.
    One joule of work is done on an object when a force of one newton is applied over a distance of one meter. The joule is named after James Prescott Joule who lived from 1818 until 1889. He worked on a principle know as the mechanical equivalent of heat which states that whenever a mechanical force is expended, an exact equivalent of heat is always obtained.
    Subsequent videos will cover the newton and the watt.. The newton is the derived unit in the metric system for force. A force is a push or a pull. One newton is equal to the force that would give a one kilogram mass an acceleration of one meter per second squared. The watt is the metric unit for power. Power describes how fast work is done. One watt of power is exerted when one joule of work is done in one second.
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КОМЕНТАРІ • 504

  • @mrmcafeeboat2887
    @mrmcafeeboat2887 4 роки тому +44

    I love you are explanation I have doubts around 4 years about joule I watch your video my doubt was clear in excellent way thank u for making this video and I love all you are video

  • @gabusprimus1243
    @gabusprimus1243 7 місяців тому +2

    OMG, i just got all the knowledge of jouls in a 9 minute video, thats insane, u teach sooo well!

  • @Intensivetangerine
    @Intensivetangerine 6 місяців тому +1

    i recently got put in 8th grade mid school year and its been a hard time understanding physics since i didnt start from the beginning in my class (everyone was way ahead of me in physics) but ever since ive found this guy on youtube i have been learning more and more, the more i watch his videos ,trully a blessing

  • @mariansinclair9036
    @mariansinclair9036 Рік тому +1

    Now, I have a clue. I am a layperson to anything science but, at the time of watching this video, I understood what a J/joule was. Part of this info will stick with this 70 something woman. Thank you!

    • @stepbystepscience
      @stepbystepscience  Рік тому +1

      Glad to hear this, you are never too old to keep learning!

  • @trevorpope1913
    @trevorpope1913 9 місяців тому +3

    Thank you, this clear explanation makes the understanding easy.

  • @timeisapathwalkingtounderstand

    Listening and learning here in New York City 2023 12:37 am Wednesday, March 15th watching and I should be sleeping ,because I have school tomorrow thank you for the video I appreciate it.

  • @billburke-miskell8460
    @billburke-miskell8460 11 місяців тому +1

    Excellent explanation for those with gray matter challenged...

  • @lipisaha5565
    @lipisaha5565 3 роки тому +1

    You are awesome teacher
    I have understood properly and you voice is really like a dream

  • @AndreCarneiroSantiago
    @AndreCarneiroSantiago 5 років тому +1

    I wish you give an example out in space. How do I calculate work when g is not a thing? And, on the definition of joules, they don't talk about time or mass, just force, and meter. Is there any difference applying 1 N over 1 m on 10 kg object or a 1 kg object, doesn't the time that I spend applying the 1-newton force over the meter matter at all?

  • @SatonsClutch
    @SatonsClutch 3 місяці тому +1

    Absolutely phenomenal explanation. Thanks!

  • @malcolmboyley2334
    @malcolmboyley2334 5 років тому +5

    Thank you so much for these videos which are so clear and concise and easy to understand.

  • @JulioCesar-hh9wq
    @JulioCesar-hh9wq 3 роки тому +1

    my mind is about to explode, thanks I've never had a better explanation about this

  • @wizkid9050
    @wizkid9050 3 роки тому +2

    That practical explanation was just lit... u lited it up

  • @jorgedimarco66
    @jorgedimarco66 3 роки тому +3

    ' Thank you teacher 'Your explanation Is very clear for me Congratulations!!! From Buenos Aires Argentina.

    • @stepbystepscience
      @stepbystepscience  3 роки тому +2

      Glad to hear that! You are very welcome and thank for the comment.

  • @rameshchandrakasan7585
    @rameshchandrakasan7585 3 місяці тому +1

    Bold, confident in explaining, good sir

  • @sergiuq2good4u
    @sergiuq2good4u 4 роки тому +4

    This is the first video I watched on your channel, and through the explanation I was always thinking: "Okay, I know how 30 Celsius feels, how does one Joule feel than??". I was impressed that you explained it eventually and now, I really understand. Thank you very much!

  • @Moviehall-fh8zu
    @Moviehall-fh8zu Рік тому +1

    I am indian sir you are great teacher in the world's

    • @stepbystepscience
      @stepbystepscience  Рік тому

      Very nice of you, thanks so much and greetings from Berlin.

  • @jessebrown7957
    @jessebrown7957 4 роки тому +5

    Bro Thank you so much 😭
    I've been wrecking my brain with this cause I'm always overthinking stuff and the helps me feel balanced again

  • @teefreeze50
    @teefreeze50 5 років тому +15

    Thanks! I wanna become a physicist, well its my dream, and i am really good at maths, but i dont know why but i suck at physics.

    • @stepbystepscience
      @stepbystepscience  5 років тому +6

      Don't give up! One day it will click. Thanks for the comment.

    • @rampagekb007
      @rampagekb007 3 роки тому +1

      Yes I am also good at chemistry and maths but I want to become a physicist.😌😌😌🤔🤔🤔🤔

  • @Marina-bn4we
    @Marina-bn4we 2 роки тому +6

    this was super helpful, you explained it simply and i could keep up with what was happening throughout the whole video :)

  • @heiea6443
    @heiea6443 3 роки тому +1

    you're a life saver, my teacher couldn't

  • @TappedCeiling46
    @TappedCeiling46 3 роки тому +3

    It's cool that you still reply to comments from old videos

  • @ksumar
    @ksumar 3 роки тому +3

    Excellent step by step guide on joules. Sir, I salute you 👍.
    Seasonal regards 🎅

  • @sorenwintherlundbys
    @sorenwintherlundbys 5 місяців тому +1

    Beautifully explained!

  • @drsavagecodm2666
    @drsavagecodm2666 3 роки тому +2

    Fantastic explanation

  • @zaherbarri5354
    @zaherbarri5354 3 роки тому +1

    Very nice. Easy to follow and understand

  • @nadenitza
    @nadenitza 4 роки тому +4

    Is the warmth and heating of your body representing the "equivalent of heat obtained", after mechanical force is spent (doing a pull up)?

  • @flacaracorbului
    @flacaracorbului 2 роки тому +1

    You teaching is awesome

  • @dannybly7284
    @dannybly7284 2 роки тому +1

    Very good explanation. Vivid bold and blunt.

  • @ORMSIRK
    @ORMSIRK 4 роки тому +1

    David Mc G - Excellent explanation

  • @nicolecastro2684
    @nicolecastro2684 3 роки тому +2

    thanks sir...this is very helpful..

  • @EmreErdogan99
    @EmreErdogan99 4 роки тому +1

    I want to ask something. When you are lifting 100 gram you are not applying 1 newton. You need to apply more than 1 newton for it to move up. Due to this when we consider ourselves, aren't we doing more work to raise it in the air?

    • @stepbystepscience
      @stepbystepscience  4 роки тому

      If you are raising the object at a constant velocity then you have to apply one newton of force.

    • @EmreErdogan99
      @EmreErdogan99 4 роки тому

      @@stepbystepscience yes it seems logical but how about the initial movement?
      I think definition should be " 1 joule is the energy that we spent for an object to keep its speed constant at 1 meter per second for moving up"
      Would this be true? And secondly what is the exact energy we spent before reaching 1m/s and going the first meter ?

  • @yellowlght
    @yellowlght 2 роки тому +1

    It's not meter it's meter squared over second squared. Meaning a meter per meter...just as second squared s^2 is referred to as a second per second courtesy of wikipedia. When using the formula for calculating a Newton N = kg * m/s^2 ...the term s^2 stands for second per second. This s^2 term when used in calculating a newton stands for constant acceleration in other words a mass of 1 kg undergoing a constant acceleration of 1 meter per second would be accelerating at 2 meters per second a second later and 3 meters per second 3 seconds later and so on - so the question then is what does the m^2 stand for when calculating joules

  • @avirai47
    @avirai47 4 роки тому +1

    thanks for teaching us with understanding way

  • @bailey2879
    @bailey2879 4 роки тому +2

    This was so helpful

  • @moosahussain4164
    @moosahussain4164 3 роки тому +2

    Keep up the good work

  • @dough-moh
    @dough-moh 4 роки тому +1

    Thanks brotha!!! I’mma definitely pass my asvab

    • @stepbystepscience
      @stepbystepscience  4 роки тому +2

      Glad I could help and I hope the asvab test goes well.

  • @youngsterxv3
    @youngsterxv3 3 роки тому +1

    ty for explaining. very educational

  • @deanconis736
    @deanconis736 Рік тому +1

    Thank You. It's been a while since reviewed these. Your presentation is very good.

  • @SchotteJ
    @SchotteJ 3 роки тому +1

    I thought it requires you to exert 1N of force already to hold it still, off the ground? So would lifting the object away from the ground not require more force, causing the work required to raise it 1m to be greater than 1J (depending on the acceleration how much Work you actually put in it)?
    So, to put it in numbers, if the acceleration (a) of Earth's gravity is 9.81 m/s² and the mass (m) of the object is 0.102 kg, Earth is exerting 1 N of force (f). So the exact equal and opposite force will hold it still in the air. So if you were to lift it you would have to accelerate it from 9.81 m/s² to for example 9.82 m/s² to be able to even lift it, causing the force to be greater, thus the amount of work over 1 m also would be greater. Actually 102 grams against 9.81 m/s² acceleration is already slightly over 1 N (1.00062 N to be precise), but accelerating it at 9.82 m/s², would make it even more, at 1.00164 N and, over 1 m, would therefore be 1.00164 Nm, or Joule of Work.
    Am I doing this right?
    Edit:
    So, if I'm doing this right, then accelerating an object upward at 0.01 m/s² (which would actually be an acceleration of 9.82 m/s², if you add in the gravity) would be the average acceleration if you move the object 1 m over 13.643 seconds (0.01m = 1 cm, 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 cm = 91 cm (because for every second you accelerate 1 cm per second, so every subsequent second you move 1 cm more) and because we have 9 cm to go and will go at about 14 meters per second, we will need 9 : 14 = 0.642857, so approximately 0.643 seconds for the last 9 cm).
    And by that reason, if moving an object of 102 g, or 0.102 kg up at 0.01 m/s², which would be an acceleration of 9.82 m/s² if you add in gravity, is 1.00164 Joule of work, then to exert 1 Joule of work with the same acceleration, the weight would have to be 102 grams x (1 N : 1.00164 N) = 102 g x 0.998363 = 101.833 grams, or 0.101833 kg.
    Or easier: 1 Joule divided by the acceleration 1 J : 9.82 m/s² = 0.101833 kg of mass.

    • @SchotteJ
      @SchotteJ 3 роки тому

      So, say you were to do a pull up of 60 cm (0.6 meters) over 1 second, that would be an acceleration of 0.6 m/s², plus the force of gravity, which is another 9.81 m/s², which would make your total acceleration 10.41 m/s². Then, multiply that by the mass in kg for the force, so in this case 95 kg x 10.41 m/s² = 988.95 N. And because you're doing that over a distance of 0.6 meters, you multiply it by 0.6 for Newtons per meter (Nm or Joule), so you'd actually be doing 988.95 N x 0.6 m = 593.37 Nm (or Joule) of Work.

  • @arotv6544
    @arotv6544 2 роки тому +2

    Thank for this video

  • @Carlos-do2vh
    @Carlos-do2vh 3 роки тому +1

    saved my life, thx

  • @Plimothrock
    @Plimothrock Рік тому

    Thank You for your common sense explanation-I wish I knew you when I was in high school !

  • @gosula.amaralingeswararao8698
    @gosula.amaralingeswararao8698 2 роки тому +1

    Sir ur explanation is good tq sir ji

  • @syedsamihaider4759
    @syedsamihaider4759 Рік тому +1

    Nice video thank keep producing such basic easier understanding videos

  • @trollobite1629
    @trollobite1629 2 роки тому +1

    Joule's contraption is an ingenious work of art.

  • @tejolisboa
    @tejolisboa 3 роки тому +1

    Cristal clear!

  • @bbrai581
    @bbrai581 Рік тому +1

    Awesome lecture

  • @AnilKumar-uz4hp
    @AnilKumar-uz4hp 3 роки тому +1

    Thanku so much Sir
    Best explanation

  • @WaggonerB11
    @WaggonerB11 Рік тому +1

    I had a dream of housing units in the future. I took a minute to look at the power meter (today's meters are in kilowatt-hour). This meter of the future was in Joules. I want to say Joule-hour. It was a J followed by a backward lower case r.

  • @debashishharichandan5648
    @debashishharichandan5648 Рік тому +1

    Great learning. Thanks a lot

  • @Dyslexic-Artist-Theory-on-Time
    @Dyslexic-Artist-Theory-on-Time 6 років тому +5

    Positive comment, very good info!!!

  • @VergelOtto
    @VergelOtto 4 місяці тому +1

    Like the explanation thanks.

  • @focusonthefemale656
    @focusonthefemale656 4 роки тому

    I have a Q that's been bugging me. A satellite can't hover over a non-zero latitude without doing work through its a thruster to keep it from drifting toward the equator. But technically one could stick a pole up into space and stop it from drifting toward the equator. As I sit here at my non-zero latitude part of the g that I feel is actually acceleration toward the equator, not gravity. I lean away from the equator, and the surface of the water in my cup is not normal to the direction of true gravity. If I just sit here supported by the floor, I burn no calories to stop drifting toward the equator. But if I get in a helicopter, some of the joules the helicopter expends go toward keeping the craft from drifting toward the equator and are not spent fighting the true g. So which is it? Does it take joules to stop a mass from drifting toward the equator or not? The standard answer seems to be "it depends" based on whether the mass is propped up by a solid object is in orbit or hovering on a gas. But the Mickelson-Morley experiment showed a small often-ignored fluctuation in the speed of light as though the apparatus were being accelerated as a function of latitude, if I remember correctly. So, is the ground doing work on our feet? Or not? Certainly gas particles bump up against certain places in a container harder than others, don't they? E.g. air bumps more joules into the top east side of the southern wall and less into the bottom south side of the eastern wall, such that the heat in the air is essentially in orbit, while the air itself has work done on it during collisions to correct its course away from its orbital path. Right. I'm told I have major conceptual errors but my in-head visual-spatial models make sense to me. Where have I gone wrong? I'm stumped. Thanks.
    -Ryan

  • @__ICT__1288
    @__ICT__1288 4 роки тому +5

    thanks a lot, it actually helps :D. It helps me in a lesson preparation

  • @chrissmith7259
    @chrissmith7259 3 роки тому +1

    Thanks a nice comment given.

  • @justinlloyd625
    @justinlloyd625 2 роки тому +1

    Tremendous video! Very clear and easy to understand. Appreciate you sharing!

  • @BrandonCuringtonOfficial
    @BrandonCuringtonOfficial 5 років тому +1

    wait so... if the object is on wheels it would mean that it would take less force to push, so does that mean that it would take less joules to move an object with wheels as opposed to an object flat on the ground?

    • @stepbystepscience
      @stepbystepscience  5 років тому

      Yes, it would require less work because the force would be less.

  • @grigor_karagozian6931
    @grigor_karagozian6931 4 місяці тому

    I do not know how to ask you this ,but when you go back and fort between newton and joule I get confused can you explain in a way that anyone at any age could understand.

  • @Jock21000
    @Jock21000 2 роки тому +1

    thanks for the video!

  • @great_India3344
    @great_India3344 3 роки тому +1

    Very good video sir

  • @kceyz
    @kceyz 3 роки тому +1

    Well done! We like knowing the why and how etc etc.

  • @Rickard_Martensson
    @Rickard_Martensson 4 роки тому +2

    Was looking for a good explanation for a group of students im gonna teach. This was exactly what i was looking for, thank you!

  • @astroid9087
    @astroid9087 2 роки тому +1

    👏 . I never realized I didn't know what joule is till I tried explaining it to my nephew. Great explanation 👌 👍

  • @levibrooks7853
    @levibrooks7853 4 роки тому +4

    You are an amazing teacher, thank you so much!

  • @georgenichles2083
    @georgenichles2083 3 роки тому +1

    brilliantlyexplained

  • @dictgravestone8430
    @dictgravestone8430 4 роки тому

    thank you thank you thank you this helped me so much in my modules cause my teacher didnt explain it well thank you

  • @ichduj
    @ichduj 4 роки тому

    i just bought a 20 joules electric fencer. i have 3, 1 joule each. i am a farmer. sheep, cattle, goats, hogs. with my miles of fence (5 strand 12.5 ga ht wire and poly wire), and plenty of weed load, i hope the fence is 20x more psychologically embarrassing than the 1 joule fencers i love. understandably, the dry season doesn't help the critters find earth. i still don't have a clue what a joule is. but hope it means punch for the buck! i paid over $1000 for the fencer.

  • @natashamararia8019
    @natashamararia8019 3 роки тому +1

    good explained

  • @ajaykumarsrivastav4955
    @ajaykumarsrivastav4955 4 роки тому +2

    Very good

  • @ganonrosario6627
    @ganonrosario6627 Місяць тому +1

    Thank you!

  • @ferdouskabir9259
    @ferdouskabir9259 4 роки тому +2

    just, this is great

  • @ninobettencorti6701
    @ninobettencorti6701 4 роки тому +1

    Finally, I've got it. Thanks man

  • @jhonabebe3894
    @jhonabebe3894 3 роки тому +1

    You are the best. You are straight to the point and clear. Thank you.

  • @raghavendrav7914
    @raghavendrav7914 4 роки тому +1

    Well explained

  • @MrNeox101
    @MrNeox101 3 роки тому +1

    Thanks this helped alot

  • @fatmafaisal4911
    @fatmafaisal4911 2 роки тому +1

    great video

  • @saransaran2752
    @saransaran2752 3 роки тому +1

    If hold 100g in my hand I will experience 1N because of resisting the 1N given by gravity .....if I just wanted to raise that 100g to 1m I need a thrust that should be greater than 1N so is I am applying more than 1N of force through 1m......pls crct me if I am wrong.....

    • @stepbystepscience
      @stepbystepscience  3 роки тому

      If you are holding the 100 g at rest and want to starting it moving (accelerate it) then yes you will have to apply a force (not a thrust) of greater than 1N. But if you move it at a constant velocity then the force needed will be 1 N. Does that help?

  • @Noobener
    @Noobener 11 місяців тому +1

    What about the time it takes to lift the object ?

    • @stepbystepscience
      @stepbystepscience  11 місяців тому +1

      That is probably a different video which I have not made yet.

  • @vipin5821
    @vipin5821 3 роки тому +1

    Nice presentation. Good information. But questions are remaining at 2020

    • @stepbystepscience
      @stepbystepscience  3 роки тому +1

      Thanks, let me know if you have questions about the video.

    • @vipin5821
      @vipin5821 3 роки тому

      @@stepbystepscience
      Could you answer me, my All stupid questions. About force, joules, calories, Energy gravity mass distance and the main thing is c^2. etc...

  • @EddyWoon
    @EddyWoon 3 роки тому +1

    Yes to the metric system. I was watching some other video about energy but unfortunately all of its written content was in full caps lock and it uses the unit of CALORIE. As there are 2 different measurements for calorie (apparently differentiated by the casing of the "c") I truly wished that it had used the unit of Joules instead.

  • @grigor_karagozian6931
    @grigor_karagozian6931 4 місяці тому

    so if you lift an object for a metre it =1nm what if you put it back down like lifting a dumbel

  • @elipsem1008
    @elipsem1008 4 роки тому +2

    On the pullup problem why was the acceleration 9.81

    • @stepbystepscience
      @stepbystepscience  4 роки тому

      Because you are working against gravity and acceleration due to gravity is 9.81 m/s2.

    • @elipsem1008
      @elipsem1008 4 роки тому

      @@stepbystepscience I get that that would be the acceleration downwards but if you going up the acceleration wouldnt be like that would it?

    • @elipsem1008
      @elipsem1008 4 роки тому

      @@stepbystepscience because I dont think many people can do a pull up that fast because nine meters faster per second is pretty fast

  • @demeloalex
    @demeloalex 3 роки тому +1

    Great! Thank you!
    🙏🙏🙏

  • @VinDcator
    @VinDcator 9 місяців тому +1

    You solved the mystery!

  • @Ishtarocha
    @Ishtarocha 4 роки тому +5

    You're a wonderful teacher!! Thank you, it enlightened so many doubts I had... 😁

  • @Walksey
    @Walksey 4 роки тому +1

    Nice and simple, good one cobra

  • @Dhakshith1189
    @Dhakshith1189 3 роки тому +1

    Thank You so much!!!

  • @christinerain6320
    @christinerain6320 4 роки тому +1

    Very nice,a little more info on the equivalent derived units of the joule will be of help thx...🙃

  • @peaklandpond2850
    @peaklandpond2850 4 роки тому +1

    Excellent!

  • @dawnfaulkner3299
    @dawnfaulkner3299 2 роки тому +1

    thank you for this it helped

  • @gaurabde9189
    @gaurabde9189 3 роки тому +1

    You have cleared all my doubts. Thank you very much.

    • @stepbystepscience
      @stepbystepscience  3 роки тому

      You are most welcome

    • @gaurabde9189
      @gaurabde9189 3 роки тому

      @@stepbystepscience Thank you for replying me in this old video. Some youtubers don't respond at all

  • @avidrationalist7281
    @avidrationalist7281 3 роки тому

    where did you suddenly get that 9.81 m//s^2 value???

  • @43yugshetty22
    @43yugshetty22 4 роки тому +2

    Thank you sir

  • @sunitaahiwale4117
    @sunitaahiwale4117 3 роки тому +1

    Thanks for helping

  • @nabil-cv1iz
    @nabil-cv1iz Рік тому +1

    to take 0.102 g and lift it through 1 meter isn't necessarily 1 joul, we should know by which force we are lifting the 0.102g.

    • @stepbystepscience
      @stepbystepscience  Рік тому +1

      The force needed to lift 0.102 g is 1 newton...F = ma = 0.102 g x 9.81 m/s2 = 1 N

    • @nabil-cv1iz
      @nabil-cv1iz Рік тому

      I think if we apply 1N to lift it up there's one another Newton applied by gravitation, if we want to lift it we should apply more than 1N.

  • @jahsehgaming5199
    @jahsehgaming5199 2 роки тому +1

    Thanks helps a lot

  • @Seif97ify
    @Seif97ify 4 роки тому +3

    What does ''work'' mean in this context?

    • @stepbystepscience
      @stepbystepscience  4 роки тому

      In physics work is done when you apply a force through a distance. W = force x distance

  • @elpollolocoman119
    @elpollolocoman119 2 місяці тому +1

    Thank you.

  • @jonathanwilliams7899
    @jonathanwilliams7899 Рік тому +1

    THANK YOU!!!!!!!!!!!!!