I just found these videos. That is truly my loss! As an "older" college student, I have struggled with "simple" physics. Combining that with a teacher who lacks the spark and excitement of teaching and I find myself scouring UA-cam for videos to help me learn. Your videos are FANTASTIC, I can't thank you enough for your well prepared and thought out explanations without over complicating. These videos draw me in, and reignite my curiosity! Again, thank you!!!!
Thank you, covid has made it hard to go to school and im glad that i can take education into my own hands. This video has helped me alot. Am teaching myself chemistry. was in school for it but....covid....
I just started Chemistry honors this year in 8th grade. A 6,000kg box has the volume of 8m^3. The Density is 750kg/8m^3, right? If it is, what percent will be below the surface?
Since it is a solid object, even with non uniform density all you have to do is calculate the mass to determine how much of it will be below the surface.
@@MichelvanBiezen sweet I’m looking at a buoy with a ballast material.. I was second guessing the density calculation.. the uniformity will matter when you start doing listing and exterior forces with moments.. thanks for confirming my thoughts!
Great video. Do you have one explaining how to calculate if the object is not solid? What if the object is made of material that is heavier than water but is hollow (has air in it) so it floats? Like a boat….
what if the densities are same of the object and the liquid? According to your video the object will sink but it is said that the object will sink only half.
Does partially submerged and floating has a difference I'm confused cuz Archimedes priciple says upthrust of a partially submerged object= weight of the liquid displaced but law of flotation says upthrst =weight of the object
In an old exam paper tgat I am going through right now, the density of the object is higher than that of the water, yet it is said to float. Now I am supposed to calculate the height of the submerged part, but scince the density of the object is greater, the height of the answer is greater than the given height of the block. Please assist.
I have a question. When you substitute the given density of the object do you substitute it by the density of the material or the density of the material with weight ?
In principle, yes, this works for spheres when you are asked for the fraction of the volume being above the surface. But it requires some additional calculations to determine where the water line will be.
You don’t need the gravity g on your computations since g is cancelled out, what is important is the density and volume of the objects, using g on your computations it only proves that there is no gravity, it’s density that is all matters!
Hi there michael. I have a question to ask. What if the shape of the submerged object, is irregular ? For example, the shape at the surface is fddifferent from the shape of the submerged body ? Can i still find the immersion depth using the simplified ratio as you shown ? wehre X = h(po/pl)
@@MichelvanBiezen yeah i saw that too but i can't find something there to solve the problem i am solving. thanks anyways, your vid still helps me a lot :>>
Michel, much thanks to all that you give us. small Q. if the object was a cube (all sides=to each other) would the final eq simply be X=(Density of object)(side of cube)/(Density of liquid)? Thanks in advance.
I don't understand why the buoyancy force's density is the liquid's density and the volume is only the submerged volume? I mean, why is it not the object's density and the volume is not the whole object's volume?
The buoyancy force (BF) is produced by the object displacing liquid. Only the portion of the object below the "water line" pushes away liquid. The BF = weight of the displaced liquid
@@MichelvanBiezen That's great! Actually sir I fell in love with physics and want to study it conceptually. I started watching your phenomenal lectures. Can you please suggest me a book?
A belong to a region where education is in pathetic condition. My teachers are not able to explain physics concepts properly. Fortunately youtube got my back.
Like please someone tell me i really don’t understand. Like why is this bouyancy force directed upward? Like I understand that at the bottom of (lets say) a submerged rectangular rock has more pressure and more force than the top of the rock but why is it directed “up” and not “down” like the top of the rock. And if you cut off all the way to the top of the rock then what happens if their is no y axis? And just an x-axis at that point there doesnt exist a top or bottom. Like what then is the force still fucking down? Or does the top force suddenly point up again. Like please i cant understand why this force is pointing up and not down. Like I understand that you can test it and see it for yourself that it is indeed upwards but why? Why the fuck is it upwards? Does everyone just say its up because its tested to be true or does someone actually have an answer?
Close but no cigar. You didn't factor in the air which is displaced by the object above the water.This is an additional upward force equal to the density of the air times the said volume. it isn't much but it is enough to make a balloon float.
Hello. when multiplying the density of air by the volume, is this referring to the volume of the object located above the water line? Thanks for your help.
Well, mathematicaly usefull, but it lacks some deeper explanation of bouyancy in my opinion. The type of understanding that gives the mathematical one trivialy follow cause it is not what is important here. What does it mean in real physical world. Don't give me solution, give me some food for thought. Can you put yourself in a point of view of ignorant school boy and than explain what it is. Math is concencvence of understanding not the understanding it self. My opinion. Thnx
I just found these videos. That is truly my loss! As an "older" college student, I have struggled with "simple" physics. Combining that with a teacher who lacks the spark and excitement of teaching and I find myself scouring UA-cam for videos to help me learn. Your videos are FANTASTIC, I can't thank you enough for your well prepared and thought out explanations without over complicating. These videos draw me in, and reignite my curiosity! Again, thank you!!!!
That is great! Thanks for sharing.
I can not show enough gratitude for your videos, you are saving my grades!
You already have. Thank you.
Student:Expressing gratitude
Sir: Commenting like a boss😎😎
@@shrutijoshi2274 he is already a boss 😎😎😎😎😎😎😎
I am a 1st year med student and your videos are top notch .....to understand the whole lecture in a few minutes
Thank you. All the best with your journey through college and med school.
@@MichelvanBiezen thank you soo much
I remember watching your videos in my first year of engineering. Your explanations helped me a lot.
Life saving lecture!
Tomorrow is my Fluid mid paper!
Can somebody please give this man an Oscar!
U saved my fluid topic
..god bless u
Excellent. From what teacher to another...hat's off to you.
Thank you. Much appreciated.
Thank you, covid has made it hard to go to school and im glad that i can take education into my own hands. This video has helped me alot. Am teaching myself chemistry. was in school for it but....covid....
I'm so glad!
For really your great scientist making such a course applicable.
Thank you. Glad you found our videos. 🙂
Thank you so much for your help. I was stuck on this topic for weeks
Glad it helped!
Building a floating dock and not wanting to goof around averaging calculations, brought me here. Thanks for this valuable information.
Thank you sir! this helps me a lot in my engineering journey :)
Tomorrow im going to sit for Physics mechanics examination.Glad to learn from your video.Thank you so much
Good luck on your exam.
Michel van Biezen thank you so much😊
You’re the best in the game van biez keep doing you
oh wow........this video has made me understand the concept around this chapter.......thank you so much .....
Failed my university physics, new year, time to retake this module. I'm starting early before semester start, give me B+!
This is a old video but it's perfect and best❤️❤️❤️
Glad you found our videos and that you find them helpful. 🙂
THANK YOU, SIR! WELL EXPLAINED!
You are welcome!
Thanks Mr.Michel Van Bienz
You are welcome.
u are great teacher
I just started Chemistry honors this year in 8th grade. A 6,000kg box has the volume of 8m^3. The Density is 750kg/8m^3, right? If it is, what percent will be below the surface?
Does this work for non uniform density objects
Since it is a solid object, even with non uniform density all you have to do is calculate the mass to determine how much of it will be below the surface.
@@MichelvanBiezen sweet I’m looking at a buoy with a ballast material.. I was second guessing the density calculation.. the uniformity will matter when you start doing listing and exterior forces with moments.. thanks for confirming my thoughts!
For a buoy, they tend to attach a heavy object at the bottom to keep it more stable.
Thanks, but how do I get the ratio (y/x)
Plug in the values to calculate x. Then subtract x from h to get y. Then divide y by x
Thank You so much it helps me to understand this topic.
Great video. Do you have one explaining how to calculate if the object is not solid? What if the object is made of material that is heavier than water but is hollow (has air in it) so it floats? Like a boat….
The principle is the same and you would solve it the same way
what if the densities are same of the object and the liquid? According to your video the object will sink but it is said that the object will sink only half.
If the density of the object is the same as the density of the liquid, the object would be completely submerged and be on the verge of sinking.
Mind. Blown.
thank so much i'm really greatful to you🙏
You're most welcome
Sir what will be the height of wooden block submerged in water, if the total height of a block is 3 cm
The fraction will be the same.
Nice 👍 sir but I'm not understood R and x in taking while the volumes
how do you solve for y?
Does partially submerged and floating has a difference
I'm confused cuz Archimedes priciple says upthrust of a partially submerged object= weight of the liquid displaced but law of flotation says upthrst =weight of the object
In an old exam paper tgat I am going through right now, the density of the object is higher than that of the water, yet it is said to float. Now I am supposed to calculate the height of the submerged part, but scince the density of the object is greater, the height of the answer is greater than the given height of the block. Please assist.
Objects that are more dense than water don't float in water.
Michel van Biezen Jeah I am aware of that. It was propably a flaw in the exam paper. Anyways, thank you for answering me. :) It is appreciated.
A= 7h +(1/2)(h/2)(2)(h)?
since there is 2 triangles so it might be times 2?
The equations in the video are correct. (I don't see which triangles you are referring to?)
@@MichelvanBiezen ohhh ..sorryy I thought this is the video that I watched. Btw your channel really helps with the understanding the concept.
No problem. If you have a question on another video, you can pose the question in a comment there. 🙂
I have a question. When you substitute the given density of the object do you substitute it by the density of the material or the density of the material with weight ?
the objects mass includes all weight/payloads
Thank you so much!
You're welcome! Glad you found it helpful. 🙂
I wish you were my teacher at college.
I have a question. How can we account for buoyant force of air in the ratios given at the end?
You would have to add the buoyancy force of the air to get the total buoyancy force.
Whether this equation is applicable in case of sphere
In principle, yes, this works for spheres when you are asked for the fraction of the volume being above the surface. But it requires some additional calculations to determine where the water line will be.
@@MichelvanBiezen Thankyou
Thank you sir,
Do more videos with practical examples sir
Sanjay r u help me for buyoncy force
You don’t need the gravity g on your computations since g is cancelled out, what is important is the density and volume of the objects, using g on your computations it only proves that there is no gravity, it’s density that is all matters!
Hi there michael. I have a question to ask. What if the shape of the submerged object, is irregular ? For example, the shape at the surface is fddifferent from the shape of the submerged body ? Can i still find the immersion depth using the simplified ratio as you shown ? wehre X = h(po/pl)
With an irregular shape you will need to use the volume ratio rather than the depth to height ratio
Michel van Biezen Do you have a video explaining how to calculate with irregular shape ??
It would be the exact same method except x would become the V below the surface and h would be the total volume of the object.
thank you for the explanation Michael ! God bless you !
Very helpful
Do you go over bernouillis equation and pascals principle anywhere?
You can find those videos here: PHYSICS 34 FLUID DYNAMICS and here: PHYSICS 33 FLUID STATICS
@@MichelvanBiezen you are amazing, i see you on here replying comments and helping others when they have questions. bless you
Are you located on the US?
Yes, we live in the Los Angeles area.
Well done
Well the deeper you go in water the buoyant force will be the same
Right 🤷🏻♂️?
Only after the object is completely submerged.
Wonderful
Thank you
hello, do you have some links about problems using this equation? thanks!
We have many more examples on the buoyancy force in the playlists on fluid statics.
@@MichelvanBiezen yeah i saw that too but i can't find something there to solve the problem i am solving. thanks anyways, your vid still helps me a lot :>>
Just, thank you sir !
It should be (h-y) instead of h. Since we are taking Weight of object submerged. Whole height h is not submerged.
The video is correct, and the solution method is correct in the video. Thanks for checking.
Genius. Thank you.
You're welcome!
the fact that even my teacher send me link to this video i-
Thank you!
Shouldn't we generalize it as displaced fluid? I thought gases also exhibit a buoyant force?
Yes, they do. But that is ignored here because the buoyancy forces from displacing gas are so much smaller than those from displacing liquid
@@MichelvanBiezen Thank you so much for your reply and your videos!
Yeah, for a cuboid that is perfectly horizontal in the liquid it's simple, but how to find it for a cuboid that is rotated in the liquid?
Michel, much thanks to all that you give us. small Q. if the object was a cube (all sides=to each other) would the final eq simply be X=(Density of object)(side of cube)/(Density of liquid)?
Thanks in advance.
Note that L does not appear in the final equation, thus it makes no difference as to the shape of the surface.
I don't understand why the buoyancy force's density is the liquid's density and the volume is only the submerged volume? I mean, why is it not the object's density and the volume is not the whole object's volume?
The buoyancy force (BF) is produced by the object displacing liquid. Only the portion of the object below the "water line" pushes away liquid. The BF = weight of the displaced liquid
@@MichelvanBiezen Ah now I understand. Thank you.
Ty
Very nice
From which book are you teaching sir?
Please reply.
I use different books for my different classes. Many of these videos are from my own notes.
@@MichelvanBiezen That's great! Actually sir I fell in love with physics and want to study it conceptually. I started watching your phenomenal lectures. Can you please suggest me a book?
A belong to a region where education is in pathetic condition. My teachers are not able to explain physics concepts properly. Fortunately youtube got my back.
nice❤🎉
Thanks 🤗
Hi Professor, are you interested to create some videos about Fluids Mechanics? I'll be willing to pay for the course. Thank you
There is no need to pay. It is part of our plan, but we need the time, which we don't have enough of at this time.
@@MichelvanBiezen . thank you for all the hard work. I understand you dont have time this is why I wanted to pay.
Bata very clear, karrr
Glad you like it.
Great sir
Thanks!
Welcome!
Like please someone tell me i really don’t understand.
Like why is this bouyancy force directed upward? Like I understand that at the bottom of (lets say) a submerged rectangular rock has more pressure and more force than the top of the rock but why is it directed “up” and not “down” like the top of the rock. And if you cut off all the way to the top of the rock then what happens if their is no y axis? And just an x-axis at that point there doesnt exist a top or bottom. Like what then is the force still fucking down? Or does the top force suddenly point up again. Like please i cant understand why this force is pointing up and not down.
Like I understand that you can test it and see it for yourself that it is indeed upwards but why? Why the fuck is it upwards? Does everyone just say its up because its tested to be true or does someone actually have an answer?
god bless you
❤️❤️❤️❤️
Close but no cigar. You didn't factor in the air which is displaced by the object above the water.This is an additional upward force equal to the density of the air times the said volume. it isn't much but it is enough to make a balloon float.
Yes, we ignored the buoyancy of the air. (Not needed in this example)
Hello. when multiplying the density of air by the volume, is this referring to the volume of the object located above the water line? Thanks for your help.
what you wrighting on the board is clearly visible.
unswempu bruu
Tomorrow is my exam
Good luck.
Any JEE aspirant ✌️
Well, mathematicaly usefull, but it lacks some deeper explanation of bouyancy in my opinion. The type of understanding that gives the mathematical one trivialy follow cause it is not what is important here.
What does it mean in real physical world. Don't give me solution, give me some food for thought.
Can you put yourself in a point of view of ignorant school boy and than explain what it is. Math is concencvence of understanding not the understanding it self.
My opinion. Thnx
Yes, we are planning on putting out a series of videos that will explain the basic principles of physics in a non-mathematical fashion.
@@MichelvanBiezen ok! Thnx!
It sounds like a good idea! ✌️
Bouyancy force is not reality..It is a hypothetical vector quantity to simplify the actual force acting on the submerged object
I don't like. how to like math?