Network Theorems | Part 3 | Important GATE Questions | Network Theory

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  • Опубліковано 18 лис 2024

КОМЕНТАРІ • 87

  • @neelmadhav5529
    @neelmadhav5529 6 років тому +12

    that common collector amplifier was great. i never thought that. it brought smile on my face.

  • @sheetaldiwakar3905
    @sheetaldiwakar3905 5 років тому

    Sir apne concepts network theorem ke itne ache se clear kiye the pichle parts me ,ki iss question ka solution ,apka solution dekhne se pehle nikal payi .thank you so much sir ,m loving networks now. hatsssofff to u sir.

  • @soumya9070
    @soumya9070 6 років тому +6

    Sir, I have already solved Q2 in the transistor method earlier as i am appearing in gate for 2nd time this year. Thanks for explaining the way of thinking to others. :)

  • @tejuingale2661
    @tejuingale2661 6 років тому

    sir maine jab diagram ussi time me bolli sir ne ye qn to analog me lena chahiye tha baad me soln pe gayi to samja ki this tyoe of network can also ask in gate...n day by day mujhe bahaut hi network pasand aane laga hai bcz of u sir thank u..!#respect

  • @prabuddhbharat2934
    @prabuddhbharat2934 6 років тому

    I study in Made Easy then I watch umesh Sir's video....just because his way of teaching is awesome.....hope this helps me in GATE and ESE 2019

  • @vishalbharti7319
    @vishalbharti7319 6 років тому

    sir maine iss que ko her baar sahi kiya ...likin kabhi aaisa nahi socha tha ki ye analog ke concept se bhi ho sakta hai......thankyou sir

  • @neeleshpandey9517
    @neeleshpandey9517 6 років тому +2

    Qa padhate ho ap really. maza hi aa jata hai. ekdum hamare tarike se sochna sikhate ho. yahi to chaie hume. this is the exact thing i was struggling. Respect.

  • @rajnandani6916
    @rajnandani6916 6 років тому +2

    Thankyou soo soo much sir.......meri sari concept clear hogyi.....tysm...UMESH SIR & GATE ACADEMY...

  • @nishigandhapingale
    @nishigandhapingale 6 років тому

    On your special day...i want to say something Sir...You are not only genious you are the god father for us....
    happy Birthday Sir...
    May god bless you ,,
    please keep blessing us,we need it.
    Thank u sir

  • @manishasaini2079
    @manishasaini2079 6 років тому +1

    sir u always provide a new concept with interesting learning .thankuu so much sir .concepts build up stronger only bcoz of u ..

  • @really_himanshu
    @really_himanshu 4 роки тому +2

    That common collector part wass OP🔥

  • @rRohit269
    @rRohit269 6 років тому +1

    Last question of thevenin network is solved using Analog...brilliant sir!!!

  • @sanjaydewangan1925
    @sanjaydewangan1925 6 років тому

    Q.2 ka second solution analog vala awesome tha, maine aisa kabhi ni socha tha , Thank you so much sir

  • @kmajevadia1437
    @kmajevadia1437 6 років тому

    Sir mene socha tha but mene analog concept se try nahi kiya
    But sir great ...Commun Controll amplifier.

  • @manojpawar2121
    @manojpawar2121 6 років тому

    thank you very much sir..... for such a wonderful explanation.... i have never thought in a way of common collector mode

  • @bond6730
    @bond6730 6 років тому

    Thank u sir you showed a new way of perception..... I haven't thinked in that way

  • @ranjankeshri826
    @ranjankeshri826 6 років тому

    Yes sir i also think in this way as i have recent watched all your live classrooms videos as well as questions video of analog

  • @atulmoundekar3868
    @atulmoundekar3868 6 років тому

    Sir..Mahool sir..
    Excellent Job.. Truly loving

  • @komalsrivastava973
    @komalsrivastava973 6 років тому +1

    Sir, I actually solved in the way of analog circuit... Thanks for the motivation sir!! 😊😊

  • @abhishekmohan2594
    @abhishekmohan2594 4 роки тому +2

    I thought of applying kcl but didn't know where to apply.

  • @mjdip09
    @mjdip09 6 років тому

    Sir mne aise sochatha, but itni easy hogi gate ka qsn to mein phirse think Karne laggya....

  • @rahulkumarmishra3051
    @rahulkumarmishra3051 6 років тому

    I have lack of word to describe your way of explanation

  • @ravikantshukla6188
    @ravikantshukla6188 6 років тому

    yes sir, i first solved using ac analysis. and got ans. within 15 sec.

  • @pratiksolanki4739
    @pratiksolanki4739 5 років тому

    mein jab amplifier k question solve kr rha tha aapki book se tab aisa figure aaya tha aur usme ye figure dekh k laga k ye kahi dekha dekha lag rha hai fir yaad aaya haan ye network ka b question tha,.....

  • @anujsrivastava4587
    @anujsrivastava4587 6 років тому

    Awesome, u change our way of thinking #respect

  • @deepakdamodaran4444
    @deepakdamodaran4444 6 років тому

    Awesome lecture sir

  • @sintukrbarnwal3509
    @sintukrbarnwal3509 6 років тому

    I dont think this idea.. This is a new concept. Thank u sir

  • @subhendumondal4946
    @subhendumondal4946 6 років тому

    haaa sir maine yasa pahele se socha tha...ar circuit vi paralell e model kiya...10kohm and RL parallel hain...current source ke sath...or 99ib dekhke hi khayal yata he bita(IB) KI

  • @shyamgupta9786
    @shyamgupta9786 6 років тому

    Very helpful thanks so much sir

  • @souravojha3137
    @souravojha3137 6 років тому

    That's why I just love GA!!

  • @maheshpatil9898
    @maheshpatil9898 6 років тому

    thank you so much Sir please sir complete operational amplifiers lectures series

  • @sabiyanaikwadi641
    @sabiyanaikwadi641 4 роки тому

    even without doing any of the above steps we can just directly find out the voltage across current source which is equal to voltage across 100 ohm resistor ......
    current through 100 ohm res is 100ib
    therefore voltage across it will be 100*100ib=10000ib volts
    since current source is in parallel therefore voltage across current source is also 10000ib .
    therefore resistance of current source = v / i = (10*10^3 ib ) / 99 ib = 101.01 ohms
    now find the equivalent resistance ... thats it ...
    just another method that I tried

  • @shwetabharti7168
    @shwetabharti7168 6 років тому

    sirji, if we assume direction of current -Ib (in resister) flow opposite in Q-2 then Rth:- get(-ve50ohm) sirji, Resister is absorbing element only +ve value SO, my Q from U which sign convension use IN ANS get right result

  • @shwetabharti7168
    @shwetabharti7168 6 років тому

    sorry SIRJI, in my Q missing some point correct both current (resister current Ib & dependent current source) direction change & B-value slightly increse 99 to 102 then Rth get (-ve 10kohm) actully when i seen this Q & its ans then Q come in my mind independent source not present in this Q then ANSWER of Rth -ve value ( ur testseries solution this concept i see SO, i asked from U). otherwise assume any thing for -ve value but behind Q asked this concept . this concept valid particular Q or always when independent source not present in ckt or depend ON direction of dependent source given in Q.

  • @veeranayak357
    @veeranayak357 4 роки тому

    Superbbbbb sir

  • @devanshnamdeo5914
    @devanshnamdeo5914 6 років тому

    Great Sir

  • @SmilePlease-08
    @SmilePlease-08 6 років тому

    Thank you sir you are brilliant

  • @deveshsrivastava3709
    @deveshsrivastava3709 6 років тому

    Sir plz upload some more videos on EDC- Pn junction capacitance , mos capacitor

  • @nikhilverma2518
    @nikhilverma2518 5 років тому

    No sir , after ur explanation i got it

  • @divyapriyadarshni1433
    @divyapriyadarshni1433 5 років тому +1

    Sir why can't we apply KVL in the 1st loop with Ib current across 9k& 1k and 100Ib current across 100? Ib= 0?

    • @rockdhyani5705
      @rockdhyani5705 5 років тому

      i know its very late but if someone else is also thinking like this then please note- in this type of approach you are assuming current from terminal 1 (across which thevenin theorem is to be found ) to be zero which actually is not.... hope you got your answer

  • @jitendrasharma6406
    @jitendrasharma6406 6 років тому

    Very very thank you sir

  • @prathamsharma4735
    @prathamsharma4735 6 років тому

    sir i solved second question with the common emitter approach😀

  • @priyankachaudhari4073
    @priyankachaudhari4073 4 роки тому

    Can we use this formula, Zeq= Vth/Isc

  • @MaharashtrianCuisineandFun.
    @MaharashtrianCuisineandFun. 6 років тому

    Thank you sir.

  • @jayvardhan9054
    @jayvardhan9054 6 років тому +1

    I thought that this circuit will behave as an amplifier but didn't reach to the result

  • @ozaaditya2929
    @ozaaditya2929 6 років тому +4

    yaa sir...hybrid model jesa dekh rahatha....first thinking aayithi...but formula bhul gya tha..

  • @PuneethD
    @PuneethD 6 років тому

    thanks

  • @vedalabharath7307
    @vedalabharath7307 6 років тому

    i also got the same thought CE configuration

  • @shivamverma3964
    @shivamverma3964 6 років тому

    3 phase ckt me doubt hai,pls make video if possible.....

  • @harishbabukethavath8064
    @harishbabukethavath8064 6 років тому

    Sir pls provide power systems for eee students.....plz plz sir

  • @padminikaranam5464
    @padminikaranam5464 5 років тому

    option a is correct ans

  • @MrRUPESH306
    @MrRUPESH306 6 років тому

    THANKS SIR

  • @sachhaldas8513
    @sachhaldas8513 6 років тому

    can't we apply KVL in the left branch of the ckt?

  • @deepakseervi7741
    @deepakseervi7741 6 років тому

    sir ,in ques. 2 can we solve by using 1amp. current source in bw terminal a,b.

  • @rajpal3714
    @rajpal3714 6 років тому +1

    Sir please provide video on mos capacitor

    • @vishalmishra7568
      @vishalmishra7568 6 років тому +1

      RAJ PAL saale nptel se dekh le....Sir ko pareshaan kyu karta hai

  • @sanjanamultani4627
    @sanjanamultani4627 6 років тому

    Yes sir... . Mene.. Analog s solve krn ka idea aya tha

  • @pushpbijyal
    @pushpbijyal 6 років тому

    Haan sirr

  • @realityengineer98
    @realityengineer98 4 роки тому

    sir 20:18 min pe jo question hai uska answer 5k ohm aa rha hai if u converted 100ohm into 0.1ohm.

    • @S-K-Kishore
      @S-K-Kishore 4 роки тому

      100 ohm = 0.1 k ohm
      Not 0.1 ohm.

  • @tusharsharma7530
    @tusharsharma7530 5 років тому

    Sir please open ur branch in roorkee or in uttrakhamd state

  • @abhisheksoni746
    @abhisheksoni746 6 років тому

    Sir opamp ka last quetion jisko ap apna fav quetion bol rahe the usi quetion ko laplace se solve karne me correct answer nhi aa raha hai pls dicuss it thanks in advance

  • @padminikaranam5464
    @padminikaranam5464 5 років тому

    ans option c

  • @himanshurai5470
    @himanshurai5470 5 років тому

    sir i have thought that it is a cc amplifier.

  • @jayshreemali4717
    @jayshreemali4717 6 років тому

    SIR mene koi coching join nhi kiya h muj tensn ho rha hai gate k ly kyuki mne self preperation k h plz motivate

  • @akashdeepstarlord1143
    @akashdeepstarlord1143 6 років тому

    2nd question Ko Bina kcl ke bas kvl se zyada fast solve ho Sakta hai

  • @waytoofficer2646
    @waytoofficer2646 6 років тому

    Sir 2nd questions ma if hum 1v dc source la kar solve karta hu tu 100 ohm answer aata ha....
    Please sir ....

  • @amanshaikh3645
    @amanshaikh3645 5 років тому

    I thought it was a transistor. But did not get the configuration.

  • @gangsofengineers4588
    @gangsofengineers4588 6 років тому

    Sir in second question Ib=v/10000. Why answer is wrong I take 99Ib=v/0=infinite please sir

    • @TARGET_TI
      @TARGET_TI 6 років тому +1

      Alok Electrical Classes why you take internal resistance zero... As it is not given ..so don't try to assume it ideal source

  • @maazmansoor6389
    @maazmansoor6389 3 роки тому

    Mai aisa tho nai socha Lekin absey kabhi nai bulunga

  • @rajhanskumar5092
    @rajhanskumar5092 6 років тому +1

    Sir phle har subject ka topic wise theory or concept upload kar do..fir uske baad gate se related questions practice btana

  • @anjummariyah3503
    @anjummariyah3503 6 років тому

    its written part 3....shouldn't it be part 1?

  • @niteshkumar-fi8ux
    @niteshkumar-fi8ux 6 років тому

    me nai socha tha kuki transistor type qn nai bnta

  • @electricalaeje325
    @electricalaeje325 6 років тому

    3 phase power calculation par ek video

  • @manphoolmeena5763
    @manphoolmeena5763 5 років тому

    Nhi,but ye jaroor socha tha ki 1k &9k alag alag kyo diya h.

  • @SaurabhKumar-rt6pm
    @SaurabhKumar-rt6pm 6 років тому

    dhasu vdl rule for ac

  • @rajhanskumar5092
    @rajhanskumar5092 6 років тому

    Bina concept ka direct question thora samajhna muskil hai..

  • @prabhanshudubey3258
    @prabhanshudubey3258 6 років тому

    Han meine resistance reflection rule laga Kar kiya tha

  • @Stoicbanda
    @Stoicbanda 6 років тому

    Sir apko MIT me hona chahiye .. Head of department

  • @PoojaSahu-pg8jn
    @PoojaSahu-pg8jn 4 роки тому

    Thanks sir 😊

  • @jitendrasharma6406
    @jitendrasharma6406 6 років тому

    Very very thank you sir