Polynomial rings 1

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  • Опубліковано 19 жов 2024

КОМЕНТАРІ • 13

  • @aditya9898
    @aditya9898 4 роки тому +2

    sir hats off to you

  • @sarthakgupta1165
    @sarthakgupta1165 5 років тому +2

    @21:20 What does he mean when he says that "R can be identified with the subring of R[x] consisting of constant polynomials." Please explain.

    • @ashishtiwari562
      @ashishtiwari562 4 роки тому +1

      Take a subset of S[x] of R[x] consisting of only constant polynomials, then S[x] will consists of nothing but elements of R..so R can be identified with Subring of R[x] containing constant polynomials
      Constant polynomials means zero degree polynomials which consists of only coefficients of R with no x

    • @ashishtiwari562
      @ashishtiwari562 4 роки тому

      The statement is equal to saying “R is a subring of R[x]

    • @dipsacedemy
      @dipsacedemy 3 роки тому +1

      @Ajey Chahal no boss , isomorphism is different thing and there is no isomorphism between ring of real no. And ring of polynomial over real.

  • @samrat3901
    @samrat3901 2 роки тому +2

    Notes mil sakte hai kya iske pdf?

  • @WORKOFART
    @WORKOFART 3 роки тому +1

    Super class

  • @sarthakgupta1165
    @sarthakgupta1165 5 років тому

    @30:21 It is remainder, not reminder.

  • @MahmoudSY-f3s
    @MahmoudSY-f3s 3 роки тому

    Thanks Sir

  • @amitpandey6628
    @amitpandey6628 4 роки тому

    Thanku so much sir

  • @gianlucacococcia2384
    @gianlucacococcia2384 3 роки тому

    Divido f per g. Siccome f uguale a G per q più r allora deve essere ch ese faccio la differenza deve essere zero. E so che il termine di grado massimo lo divido per quello di grado massimo di g. E poi moltiplica per g poiché sto costruendo il q tale che q per g più r e uguale a f