Falling Objects - Conservation of Energy
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- Опубліковано 11 вер 2024
- This is a short video on the conservation of energy. Explaining that the potential energy at the top of the fall is equal to the kinetic energy at the bottom of the fall, therefor we can find its velocity. Something I forgot to mention was that the only reason the potential energy is zero at the bottom is because at 0m we are considering that our reference point. and of course 0x9.81x10 = 0
For a live example, visit: physmatvisuals...
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Thank you sir ❤️
Thanks dude/sir aapreciate it.
Sir potential energy is always equal to kinetic energy at middle of height
Yes, that would be correct! Until you introduce external factors like drag, but that becomes a totally different problem
nicely explained...tq
Thank you bro
thanks bro
How to find the power if there is no time provided?
Power= Force multiplied by velocity
Sir it means while dropped a object
The mass weight is neglected?
There is no important of mass???
At 1:20 you can see that potential energy and kinetic energy does depend on mass, but because we assume that all of the potential energy gets converted into kinetic energy, then the mass "cancels" out and does not matter. Keep in mind, this does not account for drag (air friction) which would exist in the real world. This can be used for approximations as the loss of energy due to drag can be negligible depending on the distance and option that is falling (eg 10m vs 10km or dropping a ball vs a feather)
To add, there are some great videos on the internet of a feather and a ball falling at the same rate in a vacuum (drag removed).
What if you are given two masses attached to a frictionless pulley and they are at rest and after being released and they drop at a h=2.0m can you consider the masses or ignore them
Do you have a specific question problem? I could possibly make another video for that specific problem. Typically, with pulley problems it is important to realize that the force along the entire cable is constant. I also do believe that the mass of the two masses will matter in that case.
if you use x = 1/2 gt^2 formula from motion in one dimension then v = t ? isn't it wrong ?
Not sure I follow, how do you get that v = t? I have a similar equation derived to be gh = 1/2 v^2, but that would equate to h = (1/2) * (v ^ 2) / g, which is not the same structure as x = 1/2 gt^2
@@physmat3058 sorry my bad....
No problem! Glad you asked
good video
How to find the Hight tho
How can u find the speed.
Nicely explained but can we use 3rd eqn of motion
V*2 = U*2 + 2as
Where u = 0 and a = g
Yes, we can, that ends up being exactly the same though, this video essentially derives that equation. Because you will end up with v^2 = 2as AKA v^2 = 2gh where a=g and s=h. Cheers.
Show Movmentum as loss of energy or fraction of the energy so we found total loss of every impact so we become God by mathematical equation📈 series😇😇😇😇
There is no kinetic energy in a moving mass there is force Mv squared kinetic energy is the energy of consistent work from a consistent force regards Graham Flowers
A quick Google search yields: "Kinetic energy is the energy an object has because of its motion."
I'm not really sure what you are trying to say, but I would say that gravity is the force that is work on the object.
Can you elaborate on "there is no kinetic energy in a moving mass"?
@@physmat3058 A mass moving at 50 mph all of the mass is moving at 50 mph fact if kinetic energy is half mass velocity squared then what is in the other half regards Graham Flowers
The half is simply a constant in the equation to calculate kinetic energy. You can look up the derivation of the equation on Google, but this seems to be a nice and simple derivation: byjus.com/physics/derivation-of-kinetic-energy/
@@physmat3058 the mass does not change only velocity and force can change regards Graham Flowers
nicely explained...tq
nicely explained...tq
nicely explained...tq