CONJUGATE METHOD for solving limits (KristaKingMath)

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  • Опубліковано 2 жов 2024
  • ► My Limits & Continuity course: www.kristaking...
    The conjugate of any binomial term a+b is just the same binomial, but with the sign flipped in the middle. So if the original binomial is a+b, then its conjugate is a-b. If the original binomial is a-b, then its conjugate is a+b.
    It makes sense then that the conjugate method for solving limits involves multiplying both the numerator and denominator of a rational function by the conjugate of either its numerator or denominator.
    If we're going to use this method, then we have to identify either the numerator or denominator of the original fraction as a binomial term. Then we'll find the conjugate of this binomial and, to avoid changing the value of the original function, make sure to multiply both the numerator and denominator by the same conjugate, so that in effect we're multiplying by 1.
    This method is usually use when the binomial term includes a square root, because multiplying by the conjugate will cancel the square root and make it easier for us to solve for the limit.
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КОМЕНТАРІ • 77

  • @spencertate935
    @spencertate935 4 роки тому +33

    Im taking calculus online without having taken a precalc class and I did not even know what a conjugate was. This video helped me so much, thank you! Was explained quickly and simply

  • @halffull6745
    @halffull6745 8 років тому +24

    you are a life saver, thank you very much. i really appreciate you from the deep of my heart.

    • @kristakingmath
      @kristakingmath  8 років тому +1

      +half full I'm so happy to be able to help!

    • @1008-p4x
      @1008-p4x 3 роки тому

      @@kristakingmath same

  • @cariboux2
    @cariboux2 3 роки тому +15

    Wow! I love your pedagogical approach of explaining each step as you go. So many tutorials do not do this - assuming one is already familiar with each constituent part. Most of the time that is correct, but when it isn't, oh boy you're in trouble! Great tutorial! Thanks.

    • @kristakingmath
      @kristakingmath  2 роки тому +1

      You're very welcome, Brent! I'm so glad the step-by-step detail was helpful! :)

    • @twitchcoolbob66
      @twitchcoolbob66 2 роки тому

      @@kristakingmath still confused on how we get (sqr)2 + 2/(sqr)2 + 2

  • @anoushkab1079
    @anoushkab1079 4 роки тому +6

    THANK YOU SO MUCH MY FINAL IS TOMORROW AND I REALLY NEEDED THIS

  • @TheLilLebs
    @TheLilLebs 6 років тому +4

    Wow! What an absolutely amazing video on the conjugate method. Your explanations are perfect. Speed is just right. Great job

  • @OReily08080
    @OReily08080 4 роки тому

    Bless you, I’ve been looking for this for so long

  • @haya4042
    @haya4042 4 роки тому +1

    this is soooo helpfull im doing an exam tomorrow ill update!

  • @Ensign_Cthulhu
    @Ensign_Cthulhu 8 років тому +1

    I know why you chose to do it this way; however, this is actually a problem for which factorisation _does_ work; x - 4 = (sqrt x + 2)(sqrt x - 2).

  • @zaraiprahim2166
    @zaraiprahim2166 3 роки тому

    thnkz Teacher
    But last Step how To make
    Radical 4+2=2+2
    I was thought it will be Radical 4+2 =Radical 6🤔

  • @kennedynganga4292
    @kennedynganga4292 2 роки тому

    You're using the same explanation like my university lecturer but truth be told I got nothing in those days

  • @bincentperez9037
    @bincentperez9037 4 роки тому

    Thank you for helping me from this video💖

  • @thisistherealnasa9074
    @thisistherealnasa9074 2 роки тому

    at 1:11 you say that you cannot factor which is wrong. you can actually factor the numerator using the differences of squares method, meaning that the numerator would become (sqrtx - 2)(sqrtx + 2). You could then divide because you have the same value in the numerator and denominator, which ultimately leads you with (sqrtx + 2). For those who are just trying to learn the conjugate method however, what was explained in the video does work.

  • @alexanderdevilla6099
    @alexanderdevilla6099 7 років тому +6

    Thank you so much! It was super informative. I was wondering tho, if both the numerator and the denominator have a radical, whose conjugate do I use?

    • @specjade8613
      @specjade8613 3 роки тому

      try to factor terms out, or try algebraic long division

  • @yagnabhatt11
    @yagnabhatt11 4 роки тому

    Mam this problem can be directly solved by " L-Hospital "

  • @pearl-padrinowinniel196
    @pearl-padrinowinniel196 Рік тому

    Thanks this was a very helpfull video☺

  • @jan-willemreens9010
    @jan-willemreens9010 Рік тому

    ...Good day Krista, An alternative way to solve your limit is by treating the numerator x - 4 as a difference of squares: x - 4 = (sqrt(x) - 2)(sqrt(x) + 2), then the limit becomes: lim(x-->4)(sqrt(x) + 2) = 4... I'm sure this is not new to you... Take care, Jan-W

  • @siddharthpokhriyal8051
    @siddharthpokhriyal8051 5 років тому +1

    Thanks Krista King for explaining in such a fantastic manner

  • @edw2
    @edw2 24 дні тому

    Very helpful ☺️. Thank you

  • @jericoluisanonuevo5611
    @jericoluisanonuevo5611 3 роки тому

    thanks

  • @NS-qc3bv
    @NS-qc3bv 2 роки тому

    Hotter than listening to khan academy

  • @axelk.8275
    @axelk.8275 Рік тому

    You made this so simple to understand, even giving little examples of why you did certain operations at certain times. I could never understand conjugates but you make it so freaking easy, thanks so much, God bless your soul

  • @younggenna1712
    @younggenna1712 8 років тому +1

    what if I don't get the same factors in both the numerator and the denominator?

    • @kristakingmath
      @kristakingmath  8 років тому

      +Unruly King Then conjugate method probably wasn't the method to use. You might want to try factoring instead.

    • @younggenna1712
      @younggenna1712 8 років тому

      +CalculusExpert.com I also tried that but it didn't work.

  • @RaffaelloLorenzusSayde
    @RaffaelloLorenzusSayde 2 роки тому

    Is multiplying by conjugates only for when radicals are present? Thanks 👍

  • @bayarbotany3550
    @bayarbotany3550 4 роки тому

    Why didnt i know about this channel until now!!!, You are amazing!! So simple and straight to the point, thabk you very much.

  • @mistadanny2844
    @mistadanny2844 3 роки тому

    May i know why the value of square root of 4 we take the positive value only which is 2? What about - 2?

  • @Followerofchrist2091
    @Followerofchrist2091 3 роки тому

    Couldnt you just use L’Hopitals rule on this?

  • @danielbigtiger
    @danielbigtiger Рік тому

    Very helpful for me.

  • @kelvincaban5724
    @kelvincaban5724 7 років тому

    ua-cam.com/video/AyJsHC4OYCM/v-deo.htmlm25s conjugate method starts here

  • @bernardm9487
    @bernardm9487 2 роки тому

    Thank you angel.

  • @addisuyetayew1217
    @addisuyetayew1217 6 років тому

    Thanks for good look for you.
    Question :- for limit and continuty about Ebsolom and delta can you give me example and explain?

  • @veryhealthy9962
    @veryhealthy9962 3 роки тому

    I finally understand what on earth conjugate is and its purpose from the final parts of the video.

  • @fmyrico
    @fmyrico 2 роки тому

    Good video

  • @sunjayroy312
    @sunjayroy312 9 років тому

    Why does multiplying by a conjugate solve the problem as opposed to say multiplying by some other arbitrary fraction (=1), that doesn't change the identity?

    • @Stickyxgo
      @Stickyxgo 9 років тому

      Sun Jay It only works with the conjugate if you get the same factors in both denomerator and numerator that cancel. Using any other fraction (=1) in this case wouldn't accomplish that.

    • @sunjayroy312
      @sunjayroy312 9 років тому

      got it, thanks!

  • @sohaibahmed226
    @sohaibahmed226 6 років тому

    So conjugate just means opposite sign

  • @bindaasbn4366
    @bindaasbn4366 4 роки тому

    Thank you very much ma'm

  • @jamesplazgames233
    @jamesplazgames233 4 місяці тому

    thanks for help on finals

    • @kristakingmath
      @kristakingmath  4 місяці тому

      You’re welcome, I’m happy to help!! Hope finals went great!! ❤️❤️

  • @adnanjimale7377
    @adnanjimale7377 4 роки тому

    Hi, I like how you explain this question and thanks

  • @sidiikabdijabbarmohamedbar4169
    @sidiikabdijabbarmohamedbar4169 5 років тому

    thank you very much......❤🙏

  • @ryanhernandez1890
    @ryanhernandez1890 7 років тому +6

    Exam in an hour, you are a god

  • @alikhidzam3749
    @alikhidzam3749 3 роки тому

    Thanks!!!

  • @fish-eZ
    @fish-eZ 8 місяців тому

    you the goat

  • @jfeast5469
    @jfeast5469 4 роки тому

    Thanks for the help! Great video!

    • @kristakingmath
      @kristakingmath  4 роки тому

      You're welcome, J! I'm so glad it helped! :D

  • @ashkanghanbarifam4513
    @ashkanghanbarifam4513 2 роки тому

    Your channel is a gemstone

  • @mohamedjaasir1250
    @mohamedjaasir1250 6 років тому

    Very helpful!

  • @chaseholcomb22
    @chaseholcomb22 3 роки тому

    Thank you so much Krista!

  • @faithhannahmarichan8014
    @faithhannahmarichan8014 5 років тому

    What about
    Limit √x-4/x-4
    x->4

    • @sojulia1990
      @sojulia1990 5 років тому

      You need to use l'hôpital's rule

    • @sojulia1990
      @sojulia1990 5 років тому

      You need to use l'hôpital's rule

  • @zoeingridtupaz6578
    @zoeingridtupaz6578 3 роки тому

    TYSM!!!

  • @dysf_liquid1307
    @dysf_liquid1307 Рік тому

    Literally amazing. Explained something I’ve been stuck on for days and you actually explained each step without using mental math in 6 minutes. Bless you 🙏🏼

  • @maajidmohamed2212
    @maajidmohamed2212 4 роки тому

    in this vidio i underestood what i haven"t undroostood for many times thank you

    • @kristakingmath
      @kristakingmath  4 роки тому

      You're welcome, Maajid, I'm so glad it made sense! :)

  • @andreenriquez4817
    @andreenriquez4817 5 років тому

    Thank u