Anees Hayat, Thanks for your comment. Please find the answer of your question given below: HCL - 37% v/v. Specific gravity: 1.19 g/ml 37ml/100 ml or 370 ml/1000 ml x 1.19 g/ml = 440.3 g/L HCL Molecular weight = 36.5 Molarity: 440.3 grams /36.5 grams = 12.06 M or ~12M ==================== Compounding 1 liter of 0.1N Solution ==================== M1V1 = M2V2 (0.1)(1000) = (12) (x) x = (0.1) (1000) / 12 x = 8.3 ml ***Therefore add 0.83 ml of 37% HCL to 100ml of Distilled Water to create a 0.1N HCL solution.
I do estimation of protein by kjeldhal method using spirulina powder sample. It's doesn't result meet the acceptance criteria. Basically spirulina have 60% protein. But my result wasn't come acceptance criteria . that my result was came uneven. can you please tell about the corrective action. what should I take correct action? what are the errors came while I do estimation of protein ?
Thank you for such a detailed demonstration. Could you please help me in taking the factor value in which my sample is a whey based beverage containing tomatoes, banana and other oilseeds as ingredients..? Major constituent is whey..
Hi Sir, While making boric acid solution, It is not dissolving and the color is white instead transparent. I am using 99.7% boric acid powder.. kindly guide.
Raju Ahmmed, Thank you for your comment. Unfortunately we dont have any tutorial of Biuret Method. In future, we will develop the method. Stay with us.
For the composition of catalyst you said 36g for example.. It's not the actual value used in the reference..?? It's just for the example..?? Or all the measurements are strictly followed by the ACOC reference..?? Kindly reply..
How about other reports that describe catalyst preparation thus: 9 parts of potassium sulphate (K2SO4) anhydrous, with 1 part of copper sulphate (CuSO4)?
Excuse me, I'm actually wondering, does the preparation of solutions and reagents have official methods like the official methods of analysis by (aoac,iso ets..) and does it come in the same decument of analysis method or it's separate Btw I'm talking in general
Stock bottle of 37% HCL. Determination of molarity of 37% HCL V/V 37 ml of solute/100 ml of solution. HCL - 37% v/v. Specific gravity: 1.19 g/ml 37ml/100 ml or 370 ml/1000 ml x 1.19 g/ml = 440.3 g/L HCL Molecular weight = 36.5 Molarity: 440.3 grams /36.5 grams = 12.06 M or ~12M ==================== Compounding 100ml of 0.1N Solution ==================== M1V1 = M2V2 (0.1)(1000) = (12) (x) x = (0.1) (100) / 12 x = 0.83 ml Therefore add 0.83 ml of 37% HCL to 100ml of DW to create a 0.1N HCL solution.
Sir I do experiment as Per your Procedure I got reading 24.ml But when I take blank reading it show only o.1 ml reading. So reading difference increases. how do its percentage as per your formula
Sir, I take 2 gm Sample+2 gm catalyst mixture+20 ml H2SO4 +2 hr digestion After that I prepare 100 ml Sample Solution.10 ml Sample is use from this Solution in kj flask+50ml 40% NaOH+50 ml distill water from this 100 ml distillate were titrate with .1N HCl I got reading :24 ml After that my Problem is not Solve.Percentage get high.
@@ranganathgolhar1063 Your result is invalid. Burette reading 24 is not possible. Did you collect your distallate in 30ml of 4% boric acid solution? Which sample did you test?
thank you; it's useful you help me a lot ( from Algeria)
Tarfaoui Louiza, you are most welcome. Stay with us.
Very informative video. In making 0.1N HCl solution how come to know that 0.83ml hcl will be used?
Anees Hayat, Thanks for your comment. Please find the answer of your question given below:
HCL - 37% v/v. Specific gravity: 1.19 g/ml
37ml/100 ml or 370 ml/1000 ml x 1.19 g/ml = 440.3 g/L
HCL Molecular weight = 36.5
Molarity:
440.3 grams /36.5 grams = 12.06 M or ~12M
====================
Compounding 1 liter of 0.1N Solution
====================
M1V1 = M2V2
(0.1)(1000) = (12) (x)
x = (0.1) (1000) / 12
x = 8.3 ml
***Therefore add 0.83 ml of 37% HCL to 100ml of Distilled Water to create a 0.1N HCL solution.
@@MicroChemsExperiments thank u so much
@@aneeshayat2178 you are most welcome
Sir , thank you for making this video, it has enhanced my understanding! Can you suggest me a good textbook for this subject to refer?
Sorry we can't suggest a text book. Plzz take help from google. But you can purchage AOAC manual book.
I do estimation of protein by kjeldhal method using spirulina powder sample. It's doesn't result meet the acceptance criteria. Basically spirulina have 60% protein. But my result wasn't come acceptance criteria . that my result was came uneven. can you please tell about the corrective action. what should I take correct action? what are the errors came while I do estimation of protein ?
The value of factor 57 is constant for all type feed or changeable.
Plz Reply
Thank you for such a detailed demonstration. Could you please help me in taking the factor value in which my sample is a whey based beverage containing tomatoes, banana and other oilseeds as ingredients..? Major constituent is whey..
It is a milk product. So use 6.38 as the protein factor
@@MicroChemsExperiments Alright, Thank you!
Hi Sir,
While making boric acid solution, It is not dissolving and the color is white instead transparent. I am using 99.7% boric acid powder.. kindly guide.
Excellent!
Thanks
Hi, sir. I wanted to know how the final burette reading is higher than the first burette reading
Please learn about burette at your lab
sir, can we use sodium sulphate instead of potassium sulphate??
No
very informative. Do you have any tutorials of the Biuret method for protein determination?
Raju Ahmmed, Thank you for your comment.
Unfortunately we dont have any tutorial of Biuret Method.
In future, we will develop the method. Stay with us.
very informative...Thankew sir..
sir can we use Sulphuric acid instead of HCL in titration
No. You have to use HCl.
hello sir
How prepare the methyl red indicator??
Just dissolve 1g in 100ml ethanol
If i don't have methanol can i use ethyl alcohol to preparation the indicator ?
Thank you so much
You're most welcome
For the composition of catalyst you said 36g for example.. It's not the actual value used in the reference..?? It's just for the example..?? Or all the measurements are strictly followed by the ACOC reference..??
Kindly reply..
36g is the actual value. Prepare catalyst exactly as done in this video
@@MicroChemsExperiments Okay thank you so much.. I'm doing this experiment exactly the same.. It's really helpful..
Sir, thank you for this video I have a question what if you don’t have selenium Dioxide but the other two reagents will the catalyst work the same?
No. You must need three reagents to be used.
Hello sir ..
Sir where is the use of methyl red indicator?
Do we need to add this in boric acid during distillation?
Methyl red indicator is used during titration after distillation in the part 1
@@MicroChemsExperiments Thank you sir
How about other reports that describe catalyst preparation thus:
9 parts of potassium sulphate (K2SO4) anhydrous, with 1 part of copper
sulphate (CuSO4)?
Different analysts modified this method in different ways. Thats why there is slight difference in the catalyst preparation
Is it possible to replace selenium dioxide with another catalyst such as titanium dioxide?
No. You should use Selenium dioxide
Excuse me, I'm actually wondering, does the preparation of solutions and reagents have official methods like the official methods of analysis by (aoac,iso ets..) and does it come in the same decument of analysis method or it's separate
Btw I'm talking in general
Slightly modified from AOAC method but internally validated in our lab which gives accurate results
@@MicroChemsExperiments i didn't get it
you cant use sodium hydroxide to standardized hydrochloric acid because sodium hydroxide is a deliquescent material
Ok
Hi can you please explain why we used 0.83 ml HCl?
Stock bottle of 37% HCL.
Determination of molarity of 37% HCL V/V
37 ml of solute/100 ml of solution.
HCL - 37% v/v. Specific gravity: 1.19 g/ml
37ml/100 ml or 370 ml/1000 ml x 1.19 g/ml = 440.3 g/L
HCL Molecular weight = 36.5
Molarity:
440.3 grams /36.5 grams = 12.06 M or ~12M
====================
Compounding 100ml of 0.1N Solution
====================
M1V1 = M2V2
(0.1)(1000) = (12) (x)
x = (0.1) (100) / 12
x = 0.83 ml
Therefore add 0.83 ml of 37% HCL to 100ml of DW to create a 0.1N HCL solution.
Is this applicable for cheese sample also?
Yes.
What is the meaning of initial reading of HCl :35.6
It means initial burette reading. Plzz follow the mark on burette scale.
Sir I do experiment as Per your Procedure I got reading 24.ml
But when I take blank reading it show only o.1 ml reading.
So reading difference increases. how do its percentage as per your formula
It was not clear to me. Plzz write and explain in details. I didn't do any blank titration. So where did you find blank reading?
Sir,
I take 2 gm Sample+2 gm catalyst mixture+20 ml H2SO4
+2 hr digestion
After that I prepare 100 ml Sample Solution.10 ml Sample is use from this Solution in kj flask+50ml 40% NaOH+50 ml distill water from this 100 ml distillate were titrate with .1N HCl I got reading :24 ml
After that my Problem is not Solve.Percentage get high.
@@ranganathgolhar1063 Your result is invalid. Burette reading 24 is not possible.
Did you collect your distallate in 30ml of 4% boric acid solution?
Which sample did you test?
Muy chapucero en el manejo de la balanza y pipetas.
Yes. It is
hello sir. where is part tree?
Part three is not needed. For protein analysis, Part 1 & 2 is enough