Since the inductor of the primary side and the second side is wounded on the same core, the charge stored in the core by primary side inductor when MOSFET was in On state will be transferred to the load when it's turned off (since it's open circuit in primary, it will not have any path to discharge energy )and it depends on the turns ratio design . Energy is transferred to load when MOSFET is off, hence we call this converter as Flyback. I hope this answers your question. I have said this thing for enough time on phone to you. Now go and finish your project🙂😂
@@vinayakpb6012 this is not a place for jokes Mr.Vinayak P B.. When had you called me.. and to finish my project a guy with same name as yours isn't working well enough..
@@vinayakpb6012 it is understood that how power is transferring during turn off period. But what about the energy stored in primary during same turn off time period of switch ? And how the stored energy collapsed without any closed path. This the doubt. Plz try to give ans if you are capable. Don't elaborate this question.
@@vishwasv7019 I think during turn on period, there is no current flow through the in secondary winding due to reverse bias of diode but it can store energy and discharge during turnoff time by reversing it's polarity act as a source. But I have also doubt that during turn off time there is no path for current flow. So there would be a voltage stress across the switch. For this problm a snubber circuit across the primary may used but I don't sure.
@@jeebannayak8449 When the MOSFET is On (T-on period) energy is pumped into the core of coupled inductor (and at this time we know that diode will be reverse biased and no transfer of energy to secondary, cap would supplying to load). This same energy built up in core during T-on would be transferred to secondary/load during T-off period of MOSFET. At T-off period there'll be no discharge at primary (as mentioned in question). Most of the time active clamp is used to achieve ZVS of MOSFET thus no Voltage stress:-)
Sir , At instants dTs and (1-d)Ts there are sudden rise and fall in currents in diode, but inductor does not allow sudden changes in current, then how can it be possible???
You sir, are doing a very good job. 10/10
What is this software,you are using to explain this topology.
when the mosfet is off, how does the inductor on the primary side discharge.. I mean through which path??
Since the inductor of the primary side and the second side is wounded on the same core, the charge stored in the core by primary side inductor when MOSFET was in On state will be transferred to the load when it's turned off (since it's open circuit in primary, it will not have any path to discharge energy )and it depends on the turns ratio design .
Energy is transferred to load when MOSFET is off, hence we call this converter as Flyback.
I hope this answers your question.
I have said this thing for enough time on phone to you.
Now go and finish your project🙂😂
@@vinayakpb6012 this is not a place for jokes Mr.Vinayak P B.. When had you called me.. and to finish my project a guy with same name as yours isn't working well enough..
@@vinayakpb6012 it is understood that how power is transferring during turn off period. But what about the energy stored in primary during same turn off time period of switch ? And how the stored energy collapsed without any closed path. This the doubt. Plz try to give ans if you are capable. Don't elaborate this question.
@@vishwasv7019 I think during turn on period, there is no current flow through the in secondary winding due to reverse bias of diode but it can store energy and discharge during turnoff time by reversing it's polarity act as a source.
But I have also doubt that during turn off time there is no path for current flow. So there would be a voltage stress across the switch. For this problm a snubber circuit across the primary may used but I don't sure.
@@jeebannayak8449 When the MOSFET is On (T-on period) energy is pumped into the core of coupled inductor (and at this time we know that diode will be reverse biased and no transfer of energy to secondary, cap would supplying to load). This same energy built up in core during T-on would be transferred to secondary/load during T-off period of MOSFET. At T-off period there'll be no discharge at primary (as mentioned in question).
Most of the time active clamp is used to achieve ZVS of MOSFET thus no Voltage stress:-)
Finaly i find my solution in this video thank you sir
cool video
can mosfets be used as switching transistor
kalybos mico yeah off course
Sir ,
At instants dTs and (1-d)Ts there are sudden rise and fall in currents in diode, but inductor does not allow sudden changes in current, then how can it be possible???
IISc couldn't manage to have a good microphone for these lectures.
Karthave sthuthiyayirikkatte
Where can i find the mentioned .m files?
Hi Gyus,
Watch lecture on Op-Amp
#PowerElectronicsAPracticalApproach
ua-cam.com/video/HadbIy5dveI/v-deo.html
how to download those m files?
where can i find the m.files?
Hi Gyus,
Watch lecture on Op-Amp
#PowerElectronicsAPracticalApproach
ua-cam.com/video/HadbIy5dveI/v-deo.html
How to download those m file