@@fatimaambreen there is given quadratic equation where y=-x² - 6x - 5 vertex form is a*(x-h)²+k -h is value of x and k is the value of y -1 is represented as a Quadratic form is ax²-bx-c The given one has -x² where a is -1
@@F1RSTFACT Yes look you were asked to find f(g((x)) F(x) = blalbla G(x)= blabla The first thing you must do is to plug the g(x) and then f{x} Understood?
I would like to ask another question, in this excercise 24:10 . Why does the equation have roots if it doesn't touch the x-axis? Maybe I'm mixing concepts but I haven't quite figured that out yet
@@AlexisLopez-ev5inthe only way it’s possible is if you introduce imaginary numbers: i = square root of -1 Which would give you the roots : x1 = 2+2i and x2 = 2 -2i
let me explain, when x=0 Y will be equel to 4. So one of our point is (0,4). When y=0, X will be equl to -4/5(or -0.8), so our second point is (-0.8,0). by puting these 2 point on a graph we can draw our lovely little graph, I hope this explanation will help you to understand this topic. In general, in order to be able to draw a linear graph we only need the information of 2 points, and the easiest way to find the coordinate of them is puting 0 to either of variables and finding the other one(because 0 automatically elemant anything next to it)
the equation initially had a negative (-) sign in front of it [-x^2-6x-5] and when he made it into -[x^2+6x+5] (making all the coefficients positive), he factored out the negative one and the equation became -[x^2+6x+5]
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Videos Mentioned
29:33 - Discriminant Guide (ua-cam.com/video/_Yst9VbRR7U/v-deo.html)
31:55 - Matching Rule Guide (ua-cam.com/video/yYeIFsby4tQ/v-deo.html)
Thanks
can we just appreciate how he has a paid course but he still releases these helpful videos for people who can't afford it
29:22 do u know where that -1 came from in the vertex form
@@fatimaambreen there is given quadratic equation where y=-x² - 6x - 5
vertex form is a*(x-h)²+k
-h is value of x
and k is the value of y
-1 is represented as a
Quadratic form is ax²-bx-c
The given one has -x² where a is -1
@@ruslanmusekeev8927 oh thank u now i finally understand it
No kidding
Hey!! In composite functions F(G(x)) should be = 2(-5x+1)+3, NOT -5(2x+3)+1
Exactly ❤
that's what I think
Why can you explain pls !!!!!!!!!!!!!!!!!
Exactly. I thought while he was writing the opposite form of equation.
@@F1RSTFACT
Yes look you were asked to find f(g((x))
F(x) = blalbla
G(x)= blabla
The first thing you must do is to plug the g(x) and then f{x}
Understood?
2:40 Wouldn't that be 2(-5x+1)+3 instead?
I would like to ask another question, in this excercise 24:10 . Why does the equation have roots if it doesn't touch the x-axis? Maybe I'm mixing concepts but I haven't quite figured that out yet
Yeah it’s 2(-5x+1) he did it wrong
@@AlexisLopez-ev5inthe only way it’s possible is if you introduce imaginary numbers: i = square root of -1
Which would give you the roots :
x1 = 2+2i and x2 = 2 -2i
2:45 is misleading! f(g(x)) is incorrect. What you wrote down there is indeed g(f(x)).
30:41 the answer is y=1 and its not on the answer bullets
Thanks i was wondering lol
I was struggling with these topics for a long time. Thank youu for this video
Thanks so much for the videos
Keep up the good work
brooooo i got form 560- 670 brrooo. just now. becauseI i watched 2 of ur videos .TMR is my test Jesuss.
Sameeee. August DSAT tomorrow and I have 630 in math on my last practice test
2:51 isn't it G(F(x) that you did show? F(G(x) is 2(-5x+1)+3= -10x+1. Please help
how come no one else found that error :(
@@ankur9662 I think they did. You can find it in the comments
i thought i was doing it the wrong way ;-;
2:50 bro at least mention the error in the description
2:50 Reverse!! You did G(F(x)) there.
yeah he forget that i was also confused for second aswell.
@@yusufkaya1393 10 years of teaching and he still did that?!!
Do more Math concepts
pls make more math vids i have my dsat in may and i love your vids
Hi John! Is this applicable for DSAT as well?
Absolutely. SAT and DSAT are essentially the same exam testing you on the same thing.
@@JohnSAT Thanks! Your videos are way too helpful
Thank you for the full review
Can you please do full review for advanced?
Please teach me how to plot graph of y=5x+4, by simple observation
let me explain, when x=0 Y will be equel to 4. So one of our point is (0,4). When y=0, X will be equl to -4/5(or -0.8), so our second point is (-0.8,0). by puting these 2 point on a graph we can draw our lovely little graph, I hope this explanation will help you to understand this topic. In general, in order to be able to draw a linear graph we only need the information of 2 points, and the easiest way to find the coordinate of them is puting 0 to either of variables and finding the other one(because 0 automatically elemant anything next to it)
Your videos are very helpful thank u so much for ur hard work👍👍
29:22 do u know where that -1 came from in the vertex form
A new subscriber 🙋🏻♀️
Thank you God bless you 🙏🤗
@JohnSAT
Thank you very much. Your lesson is the best. Just perfect
Thank u sooo much,May God Bless you ❤
12:18 - Lines
Use desmos for systems of equations
2:23 Composite functions you did wrong please student see other video for composite functions
How can I inter ur course
18:22 TS
At point of intersection between two lines, the value of y is the same.
29:22 do u know where that -1 came from in the vertex form
The rule is y=a(x-h)^2+k and in the equation a=-1 so you just plug it in
the equation initially had a negative (-) sign in front of it [-x^2-6x-5] and when he made it into -[x^2+6x+5] (making all the coefficients positive), he factored out the negative one and the equation became -[x^2+6x+5]
thank you so muchhh
you're very welcome!
Hi john, How i can start to prepare for Math SAT like which basics i need start to learn and from which book or website i can study I'm weak in math
Hey! if you want to maximize your math section, I recommend watching this video to understand how to study for the math section ua-cam.com/video/I_Xdy92Tdqw/v-deo.html And follow this study plan: ua-cam.com/video/SjhQL5afilI/v-deo.html
For the basics needed for the SAT, look at the first 5 concepts listed here: www.admissionhackers.com/25concepts
@@JohnSAT Thanks
10 years Experience ! ,
I thought you were about 20 -22 years of age on first look
question 11 : desmos for the digital one ..
YO... Are these also applicable for the Digital SAT?
yep
Make a vedio on linear and exponential growth plzzzz ❤
you have a mistake or you confused with f(g(x))
Who’s taking the digital sat in 4 nov ?
❤❤❤
Hello bro b=2+b is only =2 b is cut not value is 4😂
Plz suggested me an sat English Channel.... And suggests me some topic about english...so that i can easily score Inn english 600
..
w vid
i don't have last name, i am facing problem in collage board account creation plz help me out so that i can take october SAT Exam plz help me brother
W
any MOROCCAN HERE ??
dismos solves everything
What about your brain. What is it doing in your head
@@SanjarAbdullayev-x8c😂😂
you did the opposite at the start f(g(x))