Block Diagram Reduction (Solved Example 1)
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- Опубліковано 6 лют 2025
- Control Systems: Block Diagram Reduction (Solved Example 1)
Topics discussed:
1. Solved Example based on the calculation of the overall transfer function of a control system, given in the form of Block Diagram Representation, using the Block Diagram Reduction rules.
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Thanks for consistently imparting knowledge to us, I just have a little concern about the numerator of the transfer function, I think it should be G1G2G3 instead of G2G3H2
I think so too..
yes I think so as well
yes @@shiro5410
yes g1g2g3 was correct, they went wrong there
It wasn't a mistake. It's just a way to see we all following his lessons properly! 😁😉
Surprisingly all most everyone noticed that mistake (it should be G1G2G3 in numerator)😅
Love your way of teaching sir❤😊
Thank you for the example problem sir. But I have concern about your final answer sir. That would be G1G2G3/1+G2G3H2+G1G2H1
thats true and that is what i got when i was doing it
true
Yeah man
this true of course
Thank you for this lecture. I only have one question. Shouldn't it be G1G2G3 in the numerator of the final answer and not G2G3H2? Thank you sir!
Same doubt bro, thankyou for asking for me too
It is G1G2G3 because the element H2 has been cancelled out once we take the lcm, maybe it was a typing mistake.
Same doubt.
But may be typing mistake .
I was solved this question by Masons gain formula
Same question.. Also.
Yes. It will be G1G2G3 in the numerator
I think there is a mistake while calculating the transfer function in the last step.
It should be G1G2G3/1+H2G2G3+H1G1G2.....
Please look after my answer... If I am calculating wrong please respond🙏🏻
Just done the calculus as well and ended up finding the same as yourself
You are correct...G1G2G3 it is in the Numerator
yes you are right, i got the same too and when I saw his answer I was confused lol
Yup...clearing the same doubt
Yes you are correct, I did a calculation mistake. It should be G1G2G3 in the numerator in the final answer.
Sir at 6:32 the overall function should be (G1G2G3)/(1+G2G3H2+G1G2H1)
hi can I get a copy of your solution how did you get it?
you are right bro..........same here.
G1 is missing right?
How do you still have G2 and H2 in denominator when they got cancelled out?
@@Wehn. same question
**(G1 / (1 + G1 × H1))**
Where:
**G1 = (G1 × G2 × G3) / (1 + G2 × G3 × H2)**
And
**H1 = H1 / G3**
### Step 1: Substitute the value of G1 into the main expression.
Substitute **G1 = (G1 × G2 × G3) / (1 + G2 × G3 × H2)** into the main expression:
(G1 / (1 + G1 × H1)) = ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / (1 + ((G1 × G2 × G3) / (1 + G2 × G3 × H2)) × (H1 / G3))
### Step 2: Simplify the second term in the denominator.
Simplify **((G1 × G2 × G3) / (1 + G2 × G3 × H2)) × (H1 / G3)**. The **G3**'s cancel out:
(G1 × G2 × H1) / (1 + G2 × G3 × H2)
### Step 3: Substitute this simplified term back into the main expression.
Now the expression becomes:
((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / (1 + (G1 × G2 × H1) / (1 + G2 × G3 × H2))
### Step 4: Simplify the denominator.
The denominator becomes:
1 + (G1 × G2 × H1) / (1 + G2 × G3 × H2)
Write **1** as **(1 + G2 × G3 × H2) / (1 + G2 × G3 × H2)**:
(1 + (G2 × G3 × H2) + (G1 × G2 × H1)) / (1 + G2 × G3 × H2)
### Step 5: Substitute this back into the main expression.
The expression now becomes:
((G1 × G2 × G3) / (1 + G2 × G3 × H2)) / ((1 + (G2 × G3 × H2) + (G1 × G2 × H1)) / (1 + G2 × G3 × H2))
### Step 6: Simplify the overall fraction.
Since both the numerator and denominator have the common term **(1 + G2 × G3 × H2)**, they cancel out:
(G1 × G2 × G3) / ((1 + G2 × G3 × H2) + (G1 × G2 × H1))
### Final Answer:
(G1 × G2 × G3) / ((1 + G2 × G3 × H2) + (G1 × G2 × H1))
G1G2G3/(1+H2G2G3+H1G1G2 ) SAME HERE I THINK THIS IS THE RIGHT ANSWER, SIR
Same here
Same here
u r correct
Same here
Thank you very much sir, I have an exam in 1 hour and this was a very good explanation.
How simply u have explained the concept!!!! Thank y'sm♥️🥹
6:13
Block diagram reduction? More like "Astounding knowledge instruction!" Thanks again for making and sharing all of these wonderful videos.
same doubt
@@karimma7moud-q6k I’m just curious. What was your doubt specifically?
Thank you for this series
thank you paul enriquez for the link! i hope you pass the pre-final exams!
An easier approach is to shift the last pick up point behind G3. And then first solve the negative feedback with H2 term and finally with H1 term. This way it is much easier to solve. Anyways the answer has G1G2G3 in numerator as everyone else pointed out.
That's Awesome!
Can I shift it to the left?
@JF59122 yes you can! You'll then be multiplying the gain G3 with H2
@@atifsultan_mech Hi, will the final answer then be G1G2G3/1+G2H2+G1G2G3H1? Or did I mess up?
@abrokestudentsboringlife5806 The numerator is correct. However, please double check the denominator
after calculating myself i come in the conclusion , on 6:16 you have little mistake you see the ans is G1G2G3/1+H2G2G3+H1G1G2 and your ans has h2 instead of g3 , and i am wrong pls replay me
Final answer is G1G2G3/1+G2G3H2+G1G2H1✅✅
Please why did you skip the LCM step at step 4. I don't know how to do it.
Pls upload complete lecture. Thank and God bless u sir
Nice I finally get it
Thank you
Sir @2:28 why is it H1/G3 and not for a negative feedback system?
Thanks for this video
Complete this playlist asap
thanks Sir❤
Thank you so much!
There is a problem in the last step answer should be (G1G2G33)/ (1+G2G3H2+G1G2H1)
Very good style of explanation
Correct answer is G1G2G3/ 1+ G2G3H2+G1G2H1
Sir, please update the playlist with further topics
Sir please upload electrical machine and electrical measurement and instrumentation
sir..pls post all video
Can u plzz.. Complete the full portion
Sir..pls complete the topics...
on point discussion. keep it up!
The final answer will be ( C/R = G1G2G3/1+G1G2H1)
Yeah, Just like all the people have pointed it out, the final transfer function in this example is not correct. It should be G1G2G3/(1 + G2G3H2 + G1G2H1). The playlist is good but advanced topics are not included.
I think it cannont be solved forever 😢
When next video of data structures will come?
There is an mistake in transfer function in this video,where in numerator in case of H2 there will be G1
Final Answer should be G1.G2.G3/ 1+G1.G2.H1
Finally.
Same here.
sir when will the further lecture come.........and is there any time period for further videos
as your lecture make easy to understand control engg
Sir please upload these videos quickly we desparately need this
I'm just curious; did he upload the videos quickly enough so that you and your classmates could use them before your exams?
Sir, how many videos are there for the full course?
Ya Its a typing mistake.
Its = G1G2G3/1+G2G3H2+G1G2H1
Why don't you actually show the math in solving or combing the blocks. That would make this video much more helpful
its not just him all the other channels on control system don't show the work its so annoying I had to waste so much time trying to understand how to do it dumb channels I swear
@@unclejordi they do it on purpose to make you train on solving the right answer although here the professor made a small mistake in the final result .
Sir,please solve more and more examples on this topick🙏
When u will be back🤧😭
i can not figure out how to simplify that fraction it is way to complicated
Sir please check the answer
numerator should be g1g2g3 not any h2 in nuemertor , its a simple mistake in ur solution .
*Last m it should be G1G2G3 instead of G2G3H2*
🔥👍
last calculation is wrong please correct
Numerator value is wrong
what happnend to your voice
In negetive feedback G/1-GH y G/1+GH???
I'm pretty sure the formula for the transfer function of a closed loop with unity negative feedback is G/(1+GH), and that for a closed loop with unity positive feedback is G/(1-GH). He discussed these formulas a fair amount in earlier videos.
The numerator should be g1g2g3 , be careful while making video, as your single mistake wastes out lot of time
But I think Final ans is Wrong
ok
Answer is incorrect bruh "-"
31 December 2022
There is G1 missing in the final answer.
Thank you
the answer is wrong
mali mani sir
thanks Sir🙏❤
thank you sir