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Sir at 15:48 Xn+1-Xn > 0 if Xn > Xn-1 ........ HOW DOES THIS PROVE THAT THE SEQUENCE IS MONOTONICALLY INCREASING ???
at 5:48 1/2 and next terms will be less than 0 hence it is a decreasing seq ?
Wow what an explanation sir
Very helpful thank you so much sir
Very nice 👍
sir what if we assume y1 > x1 the then sequence increasing will decrease an decreasing will increase ??
Still correct... No issue, purpose is to discuss, only monotonic nature... Whether increasing or decreasing.
@@DrHarishGarg that was exactly my doubt, you teach very well!
5:28 during last method numerator will be 16 not 7 please correct it sir
Thankue sir
Thank q sir
an=(3n+1/5n+7) , an+1= (3n+4/5n+8)But you wrote (3n+4/5n+12) how can it possible?
your an+1 is wrong... 3(n+1)+1/5(n+1)+7 = (3n+4)/(5n+12)... Hope it clear to you
@@DrHarishGarg thank you 🙃 sir
sir request hai hindi mein aur clear explanation milegi switch to hindi
Sir at 15:48 Xn+1-Xn > 0 if Xn > Xn-1 ........ HOW DOES THIS PROVE THAT THE SEQUENCE IS MONOTONICALLY INCREASING ???
at 5:48 1/2 and next terms will be less than 0 hence it is a decreasing seq ?
Wow what an explanation sir
Very helpful thank you so much sir
Very nice 👍
sir what if we assume y1 > x1 the then sequence increasing will decrease an decreasing will increase ??
Still correct... No issue, purpose is to discuss, only monotonic nature... Whether increasing or decreasing.
@@DrHarishGarg that was exactly my doubt, you teach very well!
5:28 during last method numerator will be 16 not 7 please correct it sir
Thankue sir
Thank q sir
an=(3n+1/5n+7) , an+1= (3n+4/5n+8)
But you wrote (3n+4/5n+12) how can it possible?
your an+1 is wrong... 3(n+1)+1/5(n+1)+7 = (3n+4)/(5n+12)... Hope it clear to you
@@DrHarishGarg thank you 🙃 sir
sir request hai hindi mein aur clear explanation milegi switch to hindi