Finding Square Root using Binary Search | LeetCode | Hindi | Problem Solving | Shashwat
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- Опубліковано 27 сер 2024
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Problem Statement:
Given a non-negative integer x, compute and return the square root of x.
Since the return type is an integer, the decimal digits are truncated, and only the integer part of the result is returned.
Note: You are not allowed to use any built-in exponent function or operator, such as pow(x, 0.5) or x ** 0.5.
Problem Link:
leetcode.com/p...
Solution Snippet:
github.com/Tiw...
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This is a very old video, for better sound and camera quality DSA videos, learn from the below playlist!
Java Plus DSA ( Java + DSA + Problem Solving )
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bhai tumhari explanations next level rehti hai, better than some so called Big UA-camrs
Thanks 😃❤
Very well explained.
never knew this wrapping concept... thank youuu!
You can watch java dsa course. I have tried to cover all the basics plus problem solving.
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In case you want to learn only binary Search then you can find videos below.
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@@shashwat_tiwari_st I'm actually coding in C++!
first time watching your video and i love your explanation and i am also subsriber
Great💯
Thanks sir
sir we are not storing the mid*mid we are only comparing it with x then also why it is overflowing ... I think overflow occurs when we store a value? please explain it
couldn't we make the condition start
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