A good trick to know the +/- sign in the formula: draw an arrow from the observer to the source of the sound. When the source moves opposite to this arrow you get v(sound)-v(source) and when the source moves in the direction of the arrow you get v(sound)+v(source). Same with the observer: if the observer moves opposite to the arrow you get v(sound) - v(observer). To be clear; v(sound)-v(observer) is just a part of the formula, the formula is (like in the video) f(observer) = f(source) * (v(sound) +/- v(observer)) / (v(sound) +/- v(source))
I have a question, I thought the equation was f(observer)=f(source) (v(sound) +/- v(observer)) / (v(sound) +/- v(source)) why did he switch the source and observer around. Im basing it off my text book.
Hallo sir Am little bit confused so in the question the observer is stationary and the source is moving towards the observer so that means we are using Case 1 of( Vf/V-Vo) so why did you use case 5 to find the answer in the first question?
can you explain to me, please, in a video if you want, why if the doppler effect refers to sound the age of the universe it is calculated by observing the light? because: 1. the light is not sound 2. the light dose not depend on acceleration or the velocity of the emiter or reciver --- if you will make a video plese responde to this quastion here allso in my coment so the youtube will anounce me and I will see your video --- thank you!
For anyone who may read this comment, 20 is on the numerator because 20 m/s is the velocity of the eagle observing. 15 m/s is the velocity of the eagle emitting the sound (source). It's all in the subscripts.
I am so proud of you that you continued to make this video during an earthquake.
simplest and most concise explanation of the Doppler Effect I have ever come across, including textbooks, teachers, and all of youtube
A good trick to know the +/- sign in the formula: draw an arrow from the observer to the source of the sound. When the source moves opposite to this arrow you get v(sound)-v(source) and when the source moves in the direction of the arrow you get v(sound)+v(source). Same with the observer: if the observer moves opposite to the arrow you get v(sound) - v(observer).
To be clear; v(sound)-v(observer) is just a part of the formula, the formula is (like in the video) f(observer) = f(source) * (v(sound) +/- v(observer)) / (v(sound) +/- v(source))
thank you so much! It takes me a lot of time for confusing which one is +/- sign
I have a Physics midterm tomorrow and you just saved me. thank you!
This video taught me the Doppler effect. Thank you
thank you so much this was so helpful! it helped me with my exam
Thanks for helping me with learning about the Doppler Effect.
Thanks you helped me with my exam
U r the physics tiger. Very helpful video thank you so much
Thank you! This video helped a lot!
Epic dude..... thanks now I clearly understood the concept 😁😁
Thank u so much. tom morning is my exam nd im watching this at 1.00am 🙏🙏
Super helpful video! Thank you
Thanks for this video sir 🙏
I have a question, I thought the equation was f(observer)=f(source) (v(sound) +/- v(observer)) / (v(sound) +/- v(source)) why did he switch the source and observer around. Im basing it off my text book.
Hallo sir
Am little bit confused so in the question the observer is stationary and the source is moving towards the observer so that means we are using Case 1 of( Vf/V-Vo) so why did you use case 5 to find the answer in the first question?
What math did you do to get that 878 Hz sir? Thank you in advance😇
Can we use relative motion in the egale question
can you explain to me, please, in a video if you want, why if the doppler effect refers to sound the age of the universe it is calculated by observing the light? because: 1. the light is not sound 2. the light dose not depend on acceleration or the velocity of the emiter or reciver --- if you will make a video plese responde to this quastion here allso in my coment so the youtube will anounce me and I will see your video --- thank you!
good video, but on last problem shouldnt it be 15m/s over 20m/s not the other way around? and also shouldnt the answer be rounded up to 3561 Hz?
I was thinking the same thing.
No, the process is correct. He calculated the answer wrong (or said it wrong). It should be 3556 Hz.
For anyone who may read this comment, 20 is on the numerator because 20 m/s is the velocity of the eagle observing. 15 m/s is the velocity of the eagle emitting the sound (source). It's all in the subscripts.
+Matthew Enriquez nope bro is corct
prasanna franklin Wait what? I never said he was wrong.
thank u very much.....really helpful
how did that become 878??
Safety factor?
U can search the entire UA-cam...but the formula isnt the precise one..
Try to solve this:
What happens when the air current speed is also there
Vry nice sir
Thanks man
Thx doc
great i like what am seeing this wow