Number System UPSC CSAT | CSAT Maths Syllabus Questions | CSAT Maths Question and Answers PDF EduTap
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- Опубліковано 28 вер 2024
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Answer is 50
Everyone gets till 100 divided by 20 ...4...2 .......next step is to check divisibility rule of 2 then u ll get -1*1*1*-1*1...multiply it with 5*5*2*1 = 50
@Rajesh_FF_ytzIn the first step, we are writing the number for multiplication in the final step as many times as we are canceling the number. 5 cancels the numbers twice, so 5 has to be written twice followed by 2 which cancels once. So, 5×5×2. After simplifying , In the final step we are getting the remainder 1 so this 1 is to be multiplied with 5×5×2. Therefore 5×5×2×1=50. If you still didn't get it google the question.
Bhai mujhe samajh mein nahi aa raha hai 😢 please Thora samajha dijiye na please
Good morning sir
Answer is option A -> 50 because 100 and 75 are divided by 25,then 4 and 62 are divided by 2 and the remaining equation is divided by 2,jab poora bacha hua equation ko 2 se divide karenge remainder 1 hoga. So total remainder = 25*2*1 = 50
Thanks bhai
thanks for the answer
Bahut he shandar prayaas
Thanks
Amazing lectures.... addicted to your way of teaching sir
Please continue the series
Nowhere on UA-cam can anyone find such series.
👏👏👏
Answer 50, I like the way you are teaching sir, like a slow poison, you are injecting concepts from simple to complex without even realising.
How is the ans 50
@@Ratsy-h9gd THE CONCEPT TO MULTIPLY UNIT DIGIT AND THEN MULTIPLE BY 100😊
excellent lecture sir and the answer is 50(option A).
Thank you sir!
How
Sir aap bhut achcha padhate hai aur aap jo pyqs kr wate hai mai unhe solve bhi kr leti hu aur mujhe ab confidence bhi aane lga hai ..aap ka lecture lene ke baad mai bhut excited rheti hu maths padhne ke liye .. thank you so much sir .
Answer is 50 great video please continue covering all the topics of CSAT Quant Thank you
Mast lag rahi sir series
Best ever any other csat classes❤🎉thnku so much sir
Thank you so much sir, this series is very very very helpful for us.
Sir I want to thank you from the bottom of my heart .May Allah keep you safe and happy .❤
Explanation method is excellent 👌👌 thanku so much
Sir we are very lucky that u are teaching us. The effort you are giving on us is wonderful. Please bless us so that we can pay off all your effort in exam and can say Thank You after we return from the exam hall
A. 50
Thank you sir!
Obsessed with your valuable lecture
Better than any CSAT class I have ever attended.
We are liking you too
Thank you so much😊❤ sir you 🌹❤🙏are very talented teacher👩🏫 and best teacher👩🏫 in this world because you gave me a wonderful✨😍 sessions in free🆓 of cost.
Answer of Question 3 is 50 ....option no. a
Thank you so much sir for these amazing tricks and your amazing session
Ans is 50
Class is amazing and easily understandable🎉🎉 thank you sir🥰🥰
It's my first duty to like nd comment for ur efforts after click ur video ❤❤...thanks a lot sir
Thanku so much sir for giving us such priceless content for free
Mujhe bahut regret hota hai ki kyun Mai aapke classes ke bare main pehle nahi jaana .. mei 3 din se aapke classes sun Rahi hu sir mujhe Mera concepts itna clear kabhi nahi mila... Ye class 5 mahine purane hai aur mujhe ab patah chala par koi baat nahi I'm late but not too late ....
Classes ke liye Dil se bahut dhanyawad sir ji
Pranam 🙏
answer is 50 . thanks for your efforts sir
🎉it's tooogood......... 🎉🎉🎉thanku so much sir.....🎉🎉🎉
SIR IN THE VIDEO UH ARE ADDING DIVISOR BACK TO THE REMINEDER(WHICH IS IN NEGATIVE) BUT IN SOME QN UH ARE NOT DOING IT WHEN WE ARE GETTING NEGATIVE REMAINDER(AT 13:57)
Thank u sir for such a interesting session
The ans for hw question is (a)50
At 16:10 aapne bola 4 ko divide krenge 5 se to remainder -1 aaega .but 5x1= 5 or 4-5 = -1 to -1 ko b to 5 me add karna padega na previous video me bataya tha aapne divisibility rule me ?? Please explain
Thanks for increasing confidence in csat
thank q sir for ur valuable teaching
1) Ans = 50 (option A)
2) Really liked the course and the material, the way of teaching and the initiative. A heartfelt gratitude to EduTap team. May God bless you all. Kudos.
really really helpful sirji .....plz aap cds ke liye vi maths padao
I have been enrolled in well known but the way of your teaching is totally commendable
My confidence is building up watching your lectures. Thank you for your very effective and student friendly teaching. 🙏
Thank you Sir 🙏
Way of teaching method is extra-ordinary....continouous for those aspirant who unable to afford coaching fees.
50 remainder 🎉 thank-you sir Hindi medium se hi but mujhe aapki class bhut acchi lgi kyuki bhut hi esay way smjhya h aapne ❤
The answer is option a
Thank you so much sir for your kind teaching ....your lectures are genuinely appreciative❤
Nice Class Sir.
Ans 50
Sir lacture can be extended more time can be given on conceptual clarity so we can build our base and solve pyq easily
answer is 50 sir and also ur teaching is amazing sir. one request sir kindly share some pdf of questions for practice
Sir agr aisi hi koi series 2026 k liye start kr de to bahut bahut kripa hogi 🙏🏻🙏🏻
Too good explanation sir !!!
Q3. Ans 50
Thank you so much sir!
Babut hi Baidya hai sir . Keep this up. This is true democratisation of the UPSC preparation.
Answer for HW question is 50
And this is the best csat course.. I have come across
This is the best csat class I have ever known. Thank you so much sir for this easy made conceptual clarity on every topic 🙏
Homework answer 50... thanku sir.. I want to ask you sir ,from where ,I can practice such upsc level questions ...
Very helpful lectures
Thank you so much for your support🎉
thank you so much sir..............
Outstanding teaching sir
Best explanation ever... Even explaining minor and trivial things too...
very helpful the way sir is explaining and corelate with pyq is just worthy. tank you sir.
Thank you sirrr
Finally understood the remainder concept.better than any paid coaching material.
Excellent teaching🎉🎉
सारे youtube csat के teacher एक तरफ और आप एक तरफ शानदार गुरुजी बोहोत अच्छा लगा ❤
Jabardast lectures....
Bht achhhi lgti h class aur sath hi concept bht achhe se clear ho jate h
Answer is 50 thank you sir its bery very helpfull for a student like me who is weak in maths ✨️👍
12:55 Sir 12×16/15 wali example mein aapne jb 4×16/5 ko simplify kiya to 4 ko 4 hi mana.. Pr 13:35 wali example mein aapne 4 ko (-1) mana... Aisa kyu sir please explain kriyee
Thank you sir for this great lecture ❤🎉
Thank you sir 🙏 very good series
Sir option a= 50 is the answer.
It's amazing thank you so much for your efforts and pranaam aapko.
12×19×28÷15
Sir aapny 28 ko 25 kr k -3 remainder liya what if we take 28 as 30 tab to 2 aayaga.aur ager 2 ko 3 se multiply kry to 6 aayaga overall remainder.. If i am not wrong.
Answer is 50 and the series is just amazing. Please continue it sir. Thank you 😊
Sir god bless you for coming in to our lives 🙏🏻and saving us from fear of CSAT 🙏🏻🙏🏻
Amazing lectures ❤❤
Ans-50
Very good work sir..conceptual clarity 🙏🏻
Thanku so much sir ji this video very nice
Hello Sir,
Can't thank you enough for coming out with such wonderful csat series free of cost especially for Quantitative aptitude which haunts most of the aspirants. Your efforts are really laudable.
Could you please explain how the answer to Homework question came to 50 by using the Remainder method that you taught?
Thanks so much for thinking about us now a days even politician can't afford to give this much free services to aspirants or a jobless
Answer-50
Amazing lectures, thankyou sir
Can you explain how
Too good thanks for this series it is the best ever whole u tube
Tumhi Khupach bhari shikavta sir 😍tumhi shikavlel lagech samajat 😍🥰thank you so much sir 🙏🚩 Ans:- (50)
50 remainder. 😊
Thankyou sir! Sessions are useful & easy to understand
Thanks sir, moving on to next lecture
Really appreciate the effort🤍
Thanks for this series
Sir please continue this series 🙏
Thank u so much sir for these amazing lectures! 🙏
Answer - 50
Very good series, thankyou so much.
This is the best video till date I watched on remainder theorem
good classes
Great done questn tq sir
11:20 sir 4 ko 7 se divide krne pe 3 remainder bachega na ki 4
This is the best lecture ..I really enjoy it very much 😊😊
Ans - 50
Great lecture🎉
bawal hai sir....... better than many paid courses...
Sir can u explain how 1001 is divisible by 15 and remainder is 1 sir and also 1003 remainder 3 .. i couldn't understand..I'm from tamilnadu
Just too good. Csat simplified to next level❤🎉
Helpful session sir
Answer is 50
Thank you for the such a knowledgeable series
It is a wonderful session and many people cost for this types of classes.
Answer=50
Thank you sir...
Awesome series sir 😊
answer : 50
Thanks a lot sir for these classes
You are the best
very nice series sir
Ans - 50
Thank you sir for making csat a little simpler and less daunting.💙
Can you send a solution ? please