thank you, this is really useful. Revising for my maths final and this is one area I've always struggled with, but after you explained it makes so much more sense!
I'm late but 2x^3-4x-8 = 2(x^3-2x-4) x^2-x = x(x-1) Take the 2 out 2 × integral of (x^3-2x-4)/x(x-1)(x^2+4) 2 Is is a root of x^3-2x-4, when dividing x^3-2x-4 by x-2 we have the factorization (x-2)(x^2+2x+2) So, 2 × integral of (x-2)(x^2+2x+2)/x(x-1)(x^2+4) Well, I tried to simplify to eliminate some term but I didn't see a way, so lets to partial fractions (x-2)(x^2+2x+2)/x(x-1)(x^2+4) = A/x + B/(x-1) + (Cx+D)/(x^2+4) Well, this is the way
Thank you for the video. A plus C is needed after the integration is performed. For example, when you integrate d theta, you have theta, this is incorrect. The correct solution is theta plus a Constant. Please correct these errors in the video.
u almost forgot the "+ c!" you ARE human 😂
thank you, this is really useful. Revising for my maths final and this is one area I've always struggled with, but after you explained it makes so much more sense!
You are the best ever i saw in math world .i wish can met you one day
It's so helpfull
in problem 3 shouldnt you have multiplied the x= asinx by 2 to get what 2x is equal to? thank you'
These are good, thanks.
Wow, super nice
Thank you sir
totally agree!!!
0:00 i⁴
my calc 2 professor took the whole hour and 40 minutes to explain this lmao
Can u solve this if solve you are real mathmatician integration 0 to ∞ [ u^(s-1) ]/[ e^(u) + y ] ^(2) du 🥺
Nice job
18:50 that moment of realization when u accidentally erased it was too funny
That intro is so funny
Man the way you explain this stuff is insane thanks its really helpful !!!
8:10 damn i was lost there i was like how can csc^2 become cot but i forgot this was integration not derivative
I don't know how well you know how to teach other aspect of math..but when it comes to math.. i give it to you🎉🎉😊😊
I'm a burnt out cal 2 student and it is wholly disturbing how you simplify this!
just joined your new channel ......
quality and free calculus for all....
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doing three problems like this is helpful for me having attention span issues
Did anyone else notice the ambulance at around 17 minutes?
wow your videos are very great nice well explained thank u sir🙂
Just wondering, where did you get your "ultimate calc 2 integrals" poster?
It’s my merch. You can check it out in the description 😃
I can’t buy your merch because it says me that my email address is not valid.😕
Keep your good work!
I love your videos
Pls can u help me this question?
The integration of 2x cube minus 4x minus 8 over (x square minus x)(x square plus 4) dx or
2x³-4x-8/(x²-x)(x²+4)dx
I'm late but
2x^3-4x-8 = 2(x^3-2x-4)
x^2-x = x(x-1)
Take the 2 out
2 × integral of (x^3-2x-4)/x(x-1)(x^2+4)
2 Is is a root of x^3-2x-4, when dividing x^3-2x-4 by x-2 we have the factorization
(x-2)(x^2+2x+2)
So, 2 × integral of (x-2)(x^2+2x+2)/x(x-1)(x^2+4)
Well, I tried to simplify to eliminate some term but I didn't see a way, so lets to partial fractions
(x-2)(x^2+2x+2)/x(x-1)(x^2+4) = A/x + B/(x-1) + (Cx+D)/(x^2+4)
Well, this is the way
Quick question. If I was in your class and used x = acos(theta) and no errors would you be mad or give full points
Full points.
🤩🤩🤩😍😍😍
Good
Great Video!!!
Thank you for the video. A plus C is needed after the integration is performed. For example, when you integrate d theta, you have theta, this is incorrect. The correct solution is theta plus a Constant. Please correct these errors in the video.
Good one
How do you upload videos on your so many channels regularly? I know you are a math wizard because you use teleportation spell at start of your videos.
Can u solve this if solve you are real mathmatician integration 0 to ∞ [ u^(s-1) ]/[ e^(u) + y ] ^(2) du 🥺
If u solve my problem then I coolbe with u I am also mathmatician I have a theroy to solve Riemann hypothesis 😑
Respected sir what's your religion pls reply me. I am mostly watching your video which is very helpful for us may Allah long live you.❤❤❤