Correction; the car pitches around the pitch center of the car, not the centre of gravity. Look at F1 cars and super soft road cars as 2 extreme cases - F1 cars decelerate a high Gs, inducing more load transfer, but they have significantly less pitch than road cars, due to their suspension design. Also, the CoG itself doesn't move significantly, and in case of an infinitely stiff suspension, it doesn't move at all, but there is still load transfer due to deceleration.
Hello one doubt as told is video car traveling upward(acceleration) so after performing the weight calculation Rear axel weight must be more than the front axel weight right? Unlike the calculation performed in last part front axel weight(1018kg) > Rear Axel ,HOW?(181kg)
Hi, this is a front wheel drive car, so the CoG distance to the front axle is a lot shorter than to the rear axle and the car is breaking, so there is also a load transfer to the front axle. Thanks for your question, let me know if you have any more
Hi there! Lift-off oversteer occurs when the balance of weight shifts from the rear wheels to the front wheels as the car decelerates. This shift in weight distribution reduces the amount of traction available to the rear tires while increasing it for the front tires. The demand for traction exceeds what the rear tires can provide, causing the rear of the car to lose grip and potentially slide outwards.
@@thefastandthenerdy when a car with a 4:6 weight distribution and a 6:4 car brake together, the force moves forward and the front grip improves, so both 4:6 and 6:4 cars can oversteer. Is a 4:6 car more likely to oversteer? I am a student studying automobiles, thank you
@@thefastandthenerdy If you brake a car with a weight distribution of 600kg and 400kg and the load moves forward by more than 100kg, can the actual tire grip be the same as that of a car with a 5:5 weight distribution at rest?
That's correct, both can oversteer when applying the breakes, but assuming all else is equal, the 6:4 will oversteer first as it will now have less load on the rear. When we are thinking about these things we should really look at the load on the tyres and the conditions of the road. Load transfer is more important than just the weight transfer as it takes into account all downward forces. Remember that the friction force is the load multiplied by the coefficient of friction Friction force = mu x Z
Travis it's Has back in Sydney - really enjoyed watching this and honestly really happy that you're putting out these videos!
Hey Has, thanks a lot mate, I hope you are doing well
Nice video bro! New subscriber from Ecuador....
Thanks mate, I'm happy you enjoyed it
Correction; the car pitches around the pitch center of the car, not the centre of gravity. Look at F1 cars and super soft road cars as 2 extreme cases - F1 cars decelerate a high Gs, inducing more load transfer, but they have significantly less pitch than road cars, due to their suspension design. Also, the CoG itself doesn't move significantly, and in case of an infinitely stiff suspension, it doesn't move at all, but there is still load transfer due to deceleration.
Thanks for clarifing mate, I was trying to keep it simple in this video and just introduce basic maths, but I appreicate your comment
how to consider Fo
explain
Hello one doubt as told is video car traveling upward(acceleration) so after performing the weight calculation Rear axel weight must be more than the front axel weight right? Unlike the calculation performed in last part front axel weight(1018kg) > Rear Axel ,HOW?(181kg)
Hi, this is a front wheel drive car, so the CoG distance to the front axle is a lot shorter than to the rear axle and the car is breaking, so there is also a load transfer to the front axle. Thanks for your question, let me know if you have any more
Understeer occurs when the front is heavier If that's the case, lift-off oversteer occurs when the rear is lighter can you explain this teacher?
Hi there! Lift-off oversteer occurs when the balance of weight shifts from the rear wheels to the front wheels as the car decelerates. This shift in weight distribution reduces the amount of traction available to the rear tires while increasing it for the front tires. The demand for traction exceeds what the rear tires can provide, causing the rear of the car to lose grip and potentially slide outwards.
@@thefastandthenerdy when a car with a 4:6 weight distribution and a 6:4 car brake together, the force moves forward and the front grip improves, so both 4:6 and 6:4 cars can oversteer. Is a 4:6 car more likely to oversteer? I am a student studying automobiles, thank you
@@thefastandthenerdy If you brake a car with a weight distribution of 600kg and 400kg and the load moves forward by more than 100kg, can the actual tire grip be the same as that of a car with a 5:5 weight distribution at rest?
That's correct, both can oversteer when applying the breakes, but assuming all else is equal, the 6:4 will oversteer first as it will now have less load on the rear. When we are thinking about these things we should really look at the load on the tyres and the conditions of the road. Load transfer is more important than just the weight transfer as it takes into account all downward forces. Remember that the friction force is the load multiplied by the coefficient of friction Friction force = mu x Z
It could be, it would depend on the coeffiecnt of friction and where you are measuring the grip, front or rear