13.3: Arc Length and Curvature (2/2)

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  • Опубліковано 22 жов 2024

КОМЕНТАРІ • 13

  • @ashlee122
    @ashlee122 3 роки тому +11

    This might be a little late, but incredible help for my midterm. One thing I noticed is at 22:05 timestamp the second parameter of T'(t) is wrong: (-2t^2 + sqrt(2))/(t^2 + 1)^2 instead I believe it should have been sqrt(2) * (-t^2 + 1) / (t^2 + 1)^2 given that the derivative would simplify to (sqrt(2) * t^2 + sqrt(2) - 2sqrt(2) *t^2)/(t^2 + 1)^2

  • @butx1555
    @butx1555 2 роки тому +4

    This teacher is the best honestly

    • @butx1555
      @butx1555 2 роки тому +3

      Coming back after 2 months of posting this comment, I can finally say I am officially done with my calc 3 final. Thank you so much, I really mean it

  • @hemadlawar8350
    @hemadlawar8350 2 роки тому +1

    you explain subjects awesomely.. well done bravo dear lady

  • @Birderdimvar677
    @Birderdimvar677 2 роки тому +2

    Legendary,thx for ur work

  • @johnlie8586
    @johnlie8586 4 роки тому +3

    Hi
    How can we show tangent unit victor and unit normal victor are othognal?
    Many thanks

    • @rashiraghulan9027
      @rashiraghulan9027 4 роки тому +5

      you can do the dot product of both vectors and if it is equal to 0 they are orthogonal

    • @bhavesh.adhikari
      @bhavesh.adhikari 2 роки тому

      start with || T(t) || = 1

  • @anekrajbhandari7526
    @anekrajbhandari7526 2 роки тому

    31:47 I dont understand how we got r vector (t) :(, would really appreciate if I could get some explanation to it

  • @9LimaAlpha7
    @9LimaAlpha7 2 роки тому +6

    at 13:30 , u've gotta show ur workings and explain clearly how you got the "5". cuz I had a hard time calculating it! and u cant just assume the people watching are as good and as quick as you finding ll r' ll = 5 .

  • @keanaleong7745
    @keanaleong7745 3 роки тому +1

    The value for 2/5^3/2) is incorrect, its not 0.018 but 0.1788