Solving A Quartic Equation | Problem 217

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❤️ This is Problem 217 on this channel!!! ❤️
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[@geraldsmith6225]

Its always nice to see multiple methods.

[@scottleung9587]

Nice!

[@aekben7312]

I like the second method,it is faster
The solution of the problem :4 real solutions and 2 doubles roots complex solutions
Real S:{(1-2^1/2),(1+2^1/2),(-1-2^1/2),(-1+2^1/2)}
Complex S :{(i),(-i))}.

[@zab_]

i would prob use z - 1/z = 2iSinθ

[@matthewfeig5624]

That's only true if z has magnitude 1.

[@sowndolphin5386]

whats your nationality