What is the Load Factor?
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- Опубліковано 28 вер 2024
- The load factor is a ratio of the lift of an aircraft to its weight. Every manoeuvre causes a change in the load factor. Find out how it works in this video.
Ooops. The curve on the graph shown in the video should intersect 60º at 2G.
Thanks for watching!
#flightclub #loadfactor
The first rule of flight club: You dont talk about flight club.
Damn, you beat me to it. 😂😂😂
😂🎉
love this video!! studying for my CFI currently and this was so helpful for a brief yet thorough explanation
Same here preparing for my CFI AOC this week and love this explanation !
Whoever is making these vids , YOU ARE A TRULY LEGEND 👏🏼👏🏼👏🏼👏🏼👏🏼
flight-club is making these videos
This is so helpful. I'm struggling with teaching these basic aerodynamics while on my CFI course. Thank you so much!!
I don't understand why my PoF instructor for ATPL can't just explain it this simply. I get it now.
I'm not connected to the aviation, but i like your videos. Very simple and nice to hear, the narrator is good
Thank you very much!
Whoever is doing the narration on this channel might like to look into doing an ASMR or hypnosis channel as well, they would probably gain another 500K subscribers, they have a really special voice.
I wasn’t hugely interested in avionics but the explanations presented here are really clear, so I’ve subscribed to add to my brain clutter 😬
I disagree I like this voice she is very to understand and the motion is perfect
@@jmkarmitz THE HARRY BROWN PROJECT
But does she have to play the piano at the same time?
Amazing video ! Thank you
Thank you too!
I could not love more this video...thank you
You are so kind
This is so much easier to Understand the Loadfactor. Now I m know why the Katana Eclips decrease the Flightlevel in Left or Right Turn.
Thanks❤ you really doing great job
Thanks and welcome
It's still 1G, the plane is just upside down. You're basically sitting on the roof at that point. But the forces that the plane and you are feeling is 1G.
My Answer.
The attitude of the plane or its angle of attack will determine its inverted level flying, due to the shape of the wing airfoil. The G force would be the same as straight and level.
🛩️🇦🇺
Amazing 👍
in inverted flight profile the load factor becomes -1G ( for steady inverted flight)
@flightclubonline
can you explain the logic of +G and -Gs? As I understand the +G is the downward force you feel when you are climbing at a high rate, and vice-versa, the -G (negative G) is when you are descending faster, correct?
@flightclubonline
No. G forces are related to acceleration not to vertical speed.
Going upward in an elevator in a tall building you will feel heavier as the elevator accelerates. At steady upward speed you feel normal, and lighter as it decelerates near the required floor.
Excellent!
Many thanks!
How about knife edge? explain that...
During inverted flight the load factor is of negative value, negative G forces..
1/cos(180) = -1G, right?
Is it -1G because the negative sign serves as a direction for the lift vector as vectors consist of both magnitude and direction? Thus if it is rotated the lift vector is the same except for the negative sign showing its direction.
absolutely
I think the load factor when its upside done will be a -1G
Flying upside down gives a load factor of 1 g doesnt it?
I believe that holy ghost can solve all the problems. in jesus name
No scientific physics can solves this
Excellent clip; If I may, we should get more familiar with the correct kilograms unit "mass" and let loose "weight" (Newtons).
Better to deal with newtons to equate forces
@@hannahjohnson9413 You are correct, but than we are - in the clip - talking about 10 or 20 Newton of weight and not 1 or two kilograms of weight.
Wait, I saw planes doing 90 degree of bank and still maintaining altitude.... it was at an air show
Airshow planes are exempt from the laws of fizzicks.
Just kidding. I think what you saw is called Knife-Edge Flight. The factors opposing gravity are the bottom side of the fuselage and the vertical component of thrust.
Fuselage and partially engine creates lift force. Almost everything can create aerodynamic lift force - one exception is a ball. That's why paper planes also can fly.
Won't drop like a brick, take into account how it's still movin' around fast in the air, and I guess you can try playing with the rudder to keep the nose above horizon.
@sith lord acrobatic airplane pilot used rudder(vertical stabilizer) at 90 degree bank to maintained altitude, they will step on right rudder for 90 degree left bank to keep/maintained airplane altitude...
Yo guys, do you guys know any good books based on flight training like this? It'd be cool have one!
1/cos 90= infinity?
-1G cause your bank angle is 180º, and if you do the formula that's your result
The load factor decreases to a -1g.
the weight will fall off,.......... so negative I. (k.) G
Load factor is 2 G
load factor is still 1g
-1 G
I'm following ATPL classes with CAE CBT and i can guarantee that your videos with your beautiful diagrams, smooth and clear voice are better By FAR ! ( specially for a none native speaker)
Wow, thank you!
Amazing video ! Thank you
The first rule of flight club is you do not talk about flight club. The second rule of flight club is you DO NOT DO A RYANAIR LANDING!!! 😂😂😂😂
Great explanations and obviously real professionals are working on these videos!
Would much appreciate this format for Mass&Balance ATPL
Great suggestion!
now i understand top gun maverick mission's intensity
1G relative to the ground
-1G relative to the plane
My explanation:
The pilot is experiencing a force upwards - feeling -1G, but when you zoom out of the plane he's just experiencing 1G when he's upside down.
Newton's 3rd law
"For every force in nature there is an opposite reaction"
Load factor during upside down straight and level flight will be -1G
why? seems to be quite intuitive right answer but I am not sure
180 degree? not full 360?
@@jokerbelac2917 that would just be normal flight my guy
Google says -1G 😅
wouldnt -1G be when falling?
Great video.
It leaves one with a question.
If Fcf=Lift horizontal component, the two forces are in balance.
What turns the airplane around?
There is not a force called centrifugal,it just a feeling ( so many people get confused with that)
The aircraft turns because of the horizontal lift component
Correct, only the centripetal force is a force as such
Hallman and the tape machines?
OMG. Centrifugal force doesn't exist!
- 1 G
fantastic explaination
Glad you liked it
A good question for your students: what is LF in 90° AoB level?
Look at the graph at 3:57 and you got the answer
Infinite ? But 90° bank angle is possible… I guess. So that is a good riddle.
Level flight mathematically impossible at 90 degrees of bank
@@margauxj-broussel9186 U can turn the plane to 90 degrees but it will descend. Impossible to hold in level flight at 90 degrees when there is no lift
@@OnnekasMies The Harry Brown Project
Incorrect with sufficient speed and aircraft can roll through 90 degree angle of bank and maintain level flight, it’s called aerobatics
It's turning too much ,too fast. Forget about weight.
Didactical video 👍👍
I would say it is relative to the position of the scale, if the scale stays right side up it would be 1G but if the scale turns upside down with the aeroplane then it would be -1G, that is if the 1kg weight was attached to the scale.
Its still plus one G of force. the pilot would feel the force on their lap belt instead of their backside on the seat. The scale may not register the same depending on how its set up.
Is this... "p" factor? Oh and neg one gravity.. I think.. Really like these quick vids..
Awesome video! Subscribed!
Great 🔥👍
Nice
Thanks
Without flight-club I wouldn' be able to pass my ATPL
At 3:29, a free body diagram of the airplane is showing an equal and opposite force to the horizontal component of lift known as the "centrifugal force". This force DOES NOT EXIST. Centrifugal force is an illusion brought on by the inertia of your body wanting to travel in the path prior to the airplane turning. It is an easy way to combine centripetal force and inertia, rather than teaching pilots what is actually happening when in a turn. Furthermore, if the centrifugal force was equal and opposite to the horizontal component of lift as shown in the video, the airplane would not turn.
It will be -1 because of cos 180 degrees😎😎😎
Super
Thanks
They’re asking for you to leave a comment because they genuinely don’t know
Please make video about navigation, your explanation is trully gold
I’m a big fan of these videos too.. however I wanted to let you in on a really good nav video found the other day.. it’s U.K. based so some of the resources used may differ if your from someplace else but nevertheless, it teaches you all you need to know about nav..
ua-cam.com/video/9W7dJT7Yjkk/v-deo.html
❤good explaination
-1
Thanks so much for your great videos! 😃
You are so welcome!
best to the point but thorough explanation. ! thank you so much for putting these up !
Glad you like them!
Centrifugal force does not exist 🤦🏻♂️ don't explain physics if you don't understand it... As you explained, the total forces combined will be 0 and thus the plane should remain at its current speed and direction, but the plane is turning.
Fair point. We removed the part about centrifugal force from the video. Thanks for your feedback.
Might sound like a dumb question... but if 2xLift is equal and opposite to the Apparent Weight, should you not feel any force at all? Since the net force is zero. Thanks for these videos
Force is a vector quantity. The magnitude might be the same but the direction keeps changing as you continually change direction in a circle.
It's just what you're feeling. It isn't a rea, force. you're squished into your seat and the diagonal component is where you think is down
Well, first of all the weight we feel isn’t the weight we work with in practice.
The weight [certainly] is the force of gravity exerted on us. But how do we feel this weight? It is by the reaction force that the ground/chair/bed exerts on us. And from the requirements of static equilibrium, there will still be zero net force when you are sitting on a chair [as the chair exerts you back the same amount of force by which the earth pulls you, it cancels and the net effect remains zero] but you will surely feel your weight [I.e. you won't feel weightless]. This is because [as I said earlier] how we perceive our weight. We perceive [it] by the reaction force that is exerted on us.
So when you are on a level flight in an airplane, all the forces acting on you as well as on the airplane are zero but [still] you feel the compression or the pressure of yourself [ I.e. your weight] as how you feel when sitting on a chair on the ground.
This whole idea becomes clear if one understands the frame of reference [i.e. inertial & non-inertial].
Thank you..
You're welcome
There is nothing called centrifugal force... Newtons third law , the action and the reaction act on two different bodies and not on the same body otherwise t he net force will be zero.The action is from aircraft acts on the air mass and the reaction from air mass acts on aircraft
Thank you ! The physics isn't properly phrased. To avoid any confusion, it should be better not to use the notion of centrifugal force. The weight in the plane is accelerating toward the center of a cercle, therefore the resulting force is directed toward the center too. The forces the weight is experiencing are its weight (oriented downward) and the reaction of its support in the plane, oriented perpendicular to the plane. As the gravity acts the same way on any mass, what you feel (at your bottom, when you are sitting on a chair, for example) is only this reaction of the support on which you are sitting.
The load factor is a measure of this reaction in units of the gravitational force.
As soon as she mentioned centrifugal force I cringed 😖...
Straight and level, upside down, you’ll experience -1g. But to stay level the lift factor will have to -1, too. Which also implies negative AoA and, presumably, different performance envelope.
Flying upside-down means that the wings are no longer generating upward lift, causing the aeroplane to dive, which must be recovered by the pilots.
Load Factor is 1/cos(Bank Angle). Ex. - If Bank Angle is 60 degrees, Load Factor is 2.0.
An inverted plane would have some lift capability, there is an edge. The angle of attack would be different inverted, Idk how to calculated it. but if the particular airplane is not made to be fly upside down then I would not be safe. More thrust would give the airplane more potential to stay at level flight.
Took me awhile to find this channel, apparently no one talks about it. 🤔
In the upside down scenario the load factor will remain the same since the lift still equal and opposite to the weight
But the shape of the wing is upside down so it doesn't produce the normal lift... Unless is an aerobatic plane when the shape of the wing is the same bottom and top but I don't think that this scenario uses an aerobatic plane...
@@TheDrAkira in case of asymetric airfoils You can gain more speed and more pitch angle to maintain level flight.
Question @4:08 loadfactor at upside down or 180 degree bank is calculated using formula on 3:40....and cos 180 degree is - 1 so 1 divided by - 1 should be - 1 or - 1G flight..... Maybe that's why by inverted flight pilot should push control column
Yes, down elevator to maintain level flight.
In a straight-level flight upside down, Load Factor should be "-1".
Can we get a video that answers the question posed at the end of this video that explains the answer?
Kg is a unit of mass, not weight. If you want weight, use Pounds or Newtons. For units of acceleration, use G's.