Elastic and Inelastic Collisions
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- Опубліковано 28 вер 2024
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094 - Elastic and Inelastic Collisions
In this video Paul Andersen compares and contrasts elastic and inelastic collisions. In all collisions the linear momentum will be conserved. In an elastic collision the kinetic energy of the objects will also be maintained. Several examples and demonstrations are included.
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Title: String Theory
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For those didn't got the total momentum conservation. Suppose there is a guy walking and you go running straight to him after the collision your velocity and that guy's velocity will get distributed among you both which will be different from the velocity before collision. Hope this helped :)
Conservation of momentum fails to hold if Lorentz Transformation is applied to inelastic collision. In other world, there is no conservation in any inertial reference frame other than Center Of Mass frame.
vixra.org/abs/1802.0054
This is why Lorentz Transformation is not for physics. It is only mathematics.
So, to answer your question "was this helpful" I will say, you made more sense in 6 minutes than an hour of my college physics 211 class at Portland State. My professor tries to make himself look smart or something because he talks about deriving the velocity by taking the integral of some nonsense and often times give overly complicated example equations but doesn't give us time enough to write them down then doesn't show how he gets to the final equation and after an hour and a half I have no idea what he rambled on about and no clue what was the important take away equation.
So I turn to UA-cam. I have found so many awesome professors here, you are one of them I am now adding to my list. Thank you so much for this clear and easy to understand explanation. I not only have a better understanding of the difference between elastic and inelastic but I also have actual equations that I can use to answer questions now.
Thank you for posting this and I hope you have other stuff I can use. I see one over in my right panel that is a playlist of your videos and the thumbnail looks like one of the things I need next. So glad I found your videos.
How did your physics college course go?
Thank you for your videos. My physics teacher confuses me so much but I understand everything now :D
same!!
welcome jasmine
same
saved my life the night before a physics exam :)))
SAME
HA, ME TOO!
how'd it go on your exam? :b
Same here
today is my exam and this was the only thing I couldn't understand thanks to you. now I understoo this whole topic
Thank you so much for helping me understand these things! I hope you're all right during this pandemic. Take care and may God bless you 💖
Hi! In class, we've seen that linear momentum is only conserved in isolated systems that is to say systems on which the forces that are exerted cancel each other. But here for falling objects you apply the same rule even though they are in free fall and should therefore not be considered as isolated. plus, when you first dropped the ball on the floor and it didn't rebound the linear momentum of the system became zero, what happened?
When can we say that linear momentum is conserved?
And why did the two carts stick to one another in the inelastic collision example?
best physics teacher and easy to understand
VERY HELPFUL I CANT WAIT TO SHARE IT IN MY CLASS THANKYOU
thank you this makes momentum more clear
keep making videos like this one love it
Therefore I cannot understand how a collision between a ball and the floor are charcterized by a conservation of momentum.
same!! did you get the answer? please i need help too
Dude, i bet your life is hell since the matrix came out :D
Sir I'm confused about inelastic collision, as we say momentum is conserved but K.Energy is not conserved in inelastic collision. Question is why K.E is not conserved while linear momentum is conserved, as mathematically, both depend upon the same variables i,e mass and velocity
hey! not too sure about whether or not you still need it but when we talk about momentum we're really talking about linear momentum. according to the formula p = m*v, the velocity has to be acting in the same direction as the change in momentum. for the calculation of k.e, where the energy is converted into internal energy, that is not taken into account for obvious reasons. hope that helps!
thanks! I've got a controlled assessment on this tommorow this video is very helpful
Thank you so so so much Mr. Anderson!
Thank you so much! You explained everything I needed to know.
l understand all the things about collision from this video .....ty sir
5:10 sorry if this is a stupid question but is this not assuming that the kinetic energy isn't lost to other forms of energy? How would momentum be maintained/how would you use that same momentum equation if you take heat into consideration
Did you find the answer? I'm wondering the same thing. The only way for KE to be lost is by a loss of velocity, since velocity is the energy. So if KE is lost then mv, which equals momentum, must also be lost.
ZigSputnik
Hi! Yes, I think.
After thinking it over and watching other videos, It is my understanding that yes, momentum is always conserved- thermal energy speeds up particles and so on, but when it comes to the equation, your P and P' is referring to states right before and right as a collision occurs.
Considering this, if you were given the initial velocity with which you throw a ball, the ball WOULD lose energy to heat/sound/whatever, so you wouldn't use that initial velocity in a momentum equation to find out the ball's velocity after a collision. Instead, you would need to know the ball's velocity right before it makes contact with another object. The momentum the ball had at that point is what is being maintained between the ball and the other object
hank green is that you?
he is!--i think.
Hydraefall i think he just looks alike
lel
Kristian Nah. I like Hank but Prof. B. talks more slowly and really breaks it down. Hank gives a general overview of stuff.
Lol 😂
IT HELPED ME ALOT!
THANKS
god i wish my teacher could explain things half as well as you
thank you very much! it was so much helpful
Too much helpful for me thank you so much
Bless you.
wah great video thanks
Is it possible to predict the collision is elastic or inelastic before the collision?
THANK YOU!☺
Your videos are the best. thank you so much
When are you going to upload a new video?
It was helpful for me!:-)
Conservation of momentum fails to hold if Lorentz Transformation is applied to inelastic collision. In other world, there is no conservation in any inertial reference frame other than Center Of Mass frame.
vixra.org/abs/1802.0054
This is why Lorentz Transformation is not for physics. It is only mathematics.
Thank you!!
Why didn't you do explosion? I need that too :(
lel look another video up
Alright then
I need some
help to understand
more so Still
i Am not
BROOO FISTAAAA
Nice
heyy, what about the collision of a ball that falls down on a floor ? Does the momentum conservation still happen ?
+Aulia Muhardi Arifin Yes, conservation of momentum still occurs. The reason momentum does not appear to be conserved when a ball hits the floor rather than say, the ball hitting another ball, and both balls end up moving, is because the ball transfers all of its momentum into the floor a.k.a. the Earth, and the Earth is so massive that the momentum of the ball basically has no effect on such an immense mass. I hope I didn't further confuse you.
Conservation of momentum fails to hold if Lorentz Transformation is applied to inelastic collision. In other world, there is no conservation in any inertial reference frame other than Center Of Mass frame.
vixra.org/abs/1802.0054
This is why Lorentz Transformation is not for physics. It is only mathematics.
A car made of purely of diamonds collides with a wall made purely of diamonds.
Elastic
That's helpful
I have a question.
How did you calculate each car's speed after elastic collision???
Please let me know
+eddy shin It was given in the simulation screen.
nice vdo
Good effort, but too fast too jump around quick change between topics, too busy illustrations dstracting attention, we don't need too see the narrator's face to get the message (also distracting). See Derek Owens or Calculus Expert for best method video instruction.
uhm have u considered the fact that maybe ur just a slow learner. Its more interactive if he talks because his facial expression adds value. If you get distracted thats ur own problem. Also i think its a bit to slow, but i dont bitch about it, i just watch the video at 2x speed and all is good ...if u have a problem just stick a peice of paper on the pc screen to block his face :)
+Cloud Dino And here's a piece of advice for you: you are an obnoxious twerp who comes across like a conceited little sh#t who'd be doing the world a favor by going to Dale Carnegie instead of cultivating his sh#thead geek persona.
hettygreene lol uhm do u have a life?
+Cloud Dino
Ummm... are you an obnoxious little twerp?
no i talk sense and you just flame like a senseless asswipe :)
0:06 cocaine:)
Funny I just noticed I was already subscribed to you, must have lost you in my bookmarks somewhere. I blame youtube for hiding you from me.
thank you so much! you've made my notes simpler to understand!
Easy to understand I learned a lot from watching your videos, really helps understanding the basics. I wish you were my professor
So helpful...just help before my Exams
Thank You so much that was much helpful!!
ISNT IT THAT THE velocity OF THE 2KG CART SHOULD HAVE A NEGATIVE VALUE because it opposing the 1 kg. cart??
Physics exam in 30 minutes, this saved my life🤯🤕
TY SO MUCH!! THIS IS WHAT I WAS LOOKING FOR.
thank you! i have a presentation on saturday 😅 andi can't seem to understand it because my workbook doesn't provide any examples about inelastic collision :((
You're videos are very helpful! Thanks!
Very nicely explained!
Great teacher......ur teaching is awesome.....just amazing....thank u very much...sir.
صراحة كثيير حلوة طريقة شرحك واضحة و شاملة من كل الجهات
really i loved way your explanation clear and comprehensive from all sides
It's a nice example
Superb explanation! Thanks!
On the final example the initial KE was 16.5J and the final KE was 13.5J.
Am I the only one who is deeply disturbed by the fact that nature has decided to *always* “conserve" mv but not one half mv squared! WHY?
i have my weekly test tomorrow and this video has saved me.
Let's say you have a 1 kg mass moving to the right at 20 m/s that collides with a stationary 2 kg mass and bounces off to move to the left at 10 m/s with the 2 kg mass moving to the right at 5 m/2. The time of collision is the same for both masses, but the net force is different since the impulse or change in momentum on the 2 kg mass is 10 kg*m/s and the impulse or change in momentum on the 1 kg mass is -30 kg*m/s. How does this figure or how is momentum conserved with the momentum lost by the 1 kg mass not being equal with the momentum gained by the 2 kg mass? How can the net forces be different?
I wish videos like this would lose the talking head self promoter in the corner, competing for viewers attention and distracting from the content. See math videos by Krista King (Calculus Expert) to see "how it's done".
VEHICLE IS A EXAMPLE WHICH COMES UNDER BOTH PHYSICS AND CHEMISTRY
AS THE MOTION OF VEHICLE IS PHYSICS AND THE FUEL REQUIRED FOR RUNNING VEHICLE IS CHEMISTRY
Yes, that was very helpful. Thank you. 😊
What if friction is also there between the wheel and the road? Is KE conserved?
Thank you sir for this 📚knowledge
you are a god. holy worship you
20 sept 2024 1:21
where does the energy go in inelastic collisions?
edit: what kind of internal energy, I ain't getting a clear intuition
Thermal, sound, deformation in the shape
it was super helpful thx
Thank you sir! :)
man, this was 7 years ago
I hate solving these god
Thanks sir I am from india
Thank u very much
Thank You sir
Great video!!
Mr. Anderson!
Need assistance to determine amount of force created by 3 vehicle collision. Vehicles have different masses, two in motion at different rates of speed and one at rest while sitting at stop light. variables include asphalt surface, brakes partially applied (deaccelerating) then fully applied upon impact (vehicle #2). Vehicle #1 is traveling at ~35 mph impacting vehicle #2, which is deaccelerating ~10mph, the combined vehicles 1&2 collide with vehicle #3 which is at rest with brakes fully applied. vehicle #2 fully applied brakes upon vehiclee #1 impact determined by skid marks (~5 feet) prior to impact with vehicle #3 at rest.
vehicle #3 is thrust forward ~15 feet into the intersection upon impact (skid marks on an asphalt surface). vehicle 1&2 came to rest at point of impact with vehicle 3. How much force was required to move vehicle #3 ~15 feet with the resistance tires and brakes applied, how much energy is transferred from vehicle 1, to vehicle 2 and finally to vehicle 3? How much comined energy is released through vehicle 3 (where does the energy go)? What is the G force experience in vehicle 3? Note: Drivers for vehicle 1 & 2 sustained minimal injury while vehicle 3 driver sustained major injuries. Trying to determine mathmatcally why?
THANK YOU!
Thanks sir
Nice video
nicee sr
Thanks
thank u
gooooood
Thank
Anyone can help me with this question I had on a test?
Not sure how they'd word it but it was along the lines of: What is the highest (either) elastic/inelastic at its highest when a football player throws the football.
Thanks
wow you are soooo easy to understand!!! where have you been all mylife??? #greatteachersstillexist!
That's okay until here. But I wonder how can ı find V1final and V2final separately
how do we know if both the object will bounce to the same direction or the opposite direction after the collide?
I don't understand! in the first exemple for the inelastic colision, the momentum is not conserved.
Thanks for that @Bozeman Science
observation- chemists are better at explaining physics stuff than a physicist
i dont understand anything in my physics class. watch your video once. i understand. thank you so much
wait so even if the final total momentum is more than the initial total momentum, it still counts as momentum being conserved?
:)
😮
Everyone's saying this is so helpful why i understood 1% of this thing
the last collision you made was completely inelastic,not inelastic