To get the study materials (Notes, video lecture, previous years, semesters question papers) Join Our Community : lastmomenttuitions.com/lmt-community/ Basic Electrical Engineering (BEE) Full Course - bit.ly/2VPQlyW Python Bootcamp for Beginners - bit.ly/33x4tkO
Hlw.. Bhaiya.. Thanks for these videos.. My mid sem is from 9 march.. going through your videos.. Can you please tell me if I watch this playlist and go through PYQ and sir's notes will I be able to solve & pass in exams..?
say dat v r neglecting significance of current source by open ckt. for voltage source v r short ckt by that v can neglect its significance while v r applying super mesh r super node respectively
Nhi brother Mai bhi janta hu ki current ki direction clockwise hai par current plus se enter hokar minus par end hota hai to -90 hi aayega mujhe bhi bahut confusion tha par mene book me dekha to doubt clear ho gya.
Solution of the last problem: Equations are: 50i1 +0i2 +0i3 = 10 0i1 + i2 - i3 = 10 3i1 - 4i2 -12i3 = 0 Upon solving we get: i1 = 1.52 A i2 = 7.78 A i3 = -2.21 A As i2 is greater than i3 We do i2 - i3 => 7.78 - (-2.21) A => 9.99 A Hence 10 A current is flowing through the 50 ohm resistor.
To get the study materials (Notes, video lecture, previous years, semesters question papers) Join Our Community : lastmomenttuitions.com/lmt-community/
Basic Electrical Engineering (BEE) Full Course - bit.ly/2VPQlyW
Python Bootcamp for Beginners - bit.ly/33x4tkO
Bhai iske notes kisi ko mile kya
Rtu k grp par koi notes nhi hai
Use +90 in place of -90 in equation 1
Yes it should be +90
Yeah
- multiply kar lo aap
Galat nhi likhenge to comment kaise kroge
Correct hi hai... Current positive to negative jaa raha hai to minus hi hoga
I1= -1.46
I2= 7.22
I3=-2.77
Current flowing is i2-i3= 7.22+2.77=10
Yess
Lpu
@@WirelessBhai haha
@@AnkushKumar-qg2ei?
@@WirelessBhai kal tera CA hai
Love you bro...you teach us in a very friendly manner..it really helps......thank you..😘
i1=-1.46A, i2=7.22A, i3=-2.77A
I1=-1.4647
I2=7.225
I3=-2.774
Glt
Sir you are just tremendous,
Aaj mera exam hai or aapke hi vajah se main prepare ho paya,
Thanks alot Sumer Bhai❣️❣️
Kaisa raha exam,?
Current through 50 ohm is 10A
How
✅
Provide solutions
Current through 50ohm Resistance in super mesh is=9.99Amps =10 Amps
Bro niche likha to hai 10 amp to asa comment me kyu likh rhe ho 🤣
yeah bro same ans
correct
I love your teaching style. You really helped me a lot 😘
you don't have to go for too much cal
i2-i3=10 is already given in qsn thus the flow of current in 50 will 10
Vo sb ko pta hai question solve krna Sikha rhe hai vo.
Answer: 9.9A current through 5 ohm resistor
Yes, 9.952A
10 A
50 ohm k through current 10 Amp hoga kyuki woh 10 Amp k current source k saath series me hai. Ise solve karne ki bhi jaroorat nahi hai.
Current ki direction niche hai upar hotha tho 10 amps hotha I think:-( shayad🤔
Yes Bro
@@DEEPAKSINGH-17 No
It's ...-90=0
Because + to - is -90 V
N then it becomes
....=+90
I think there's a mistake??
Ya there's a mistake
No mistake,use the trick
Or see the video that provides the trick,u will get ur ans
It's same yr
Taking common " - " LHS and RHS
mesh 3 me +30 I2Hoga
Guyss... I have gone through exactly what our professor and our course book has taught us..
From - to + ...+V
And from + to - .... -V
sumer vai. I m Bangladeshi
U r really great. Tnx a lot. For give some opportunity to learn about shortcut trick
Ur wlcm we are happy to help you
I am also bangladeshi bro
Vaii Tere ko hindii samaj aati h kya
@@AshishKumar-nd8ur tumsa behtar ataya
wow... it the best way to find i1 ,i2 and i3>>>>>>>thank you very much
Thanks you sir,very good explanation,Btw answer of the homework,
I1=-1.65
I2=6.923
I3=-3.08
Current through 50ohm=I2-I3
=6.923+3.08=9.99~10A
bee phle bahut tough lgta tha par avi tak ke aapke videos dekh kr smjh aane lga h. Thank u so much
Thank you bhaiya....... For Teaching us
i1=1.91
i2 = -7.14
i3 = 2.85
Current through 50 ohm resistance is 9.99A
solution milega ??
i1= 4.12, i2= 6.54, i3= (-16.54)
so from 50ohm = 16.54-6.54 =10 ohm this is the correct answerThank you ✌️✌️
Bhaiya please update your notes URL , it is not working... Thank you for these concepts . its really helpful
Bro beat boxing tutorial k sath sath ye academics videos v.......wow bro.......love your sprit
Thank you so much bhai tere karan meh exam clear karpaya
I can't solve some mesh CKT...bt from now it will be easy...thnx bro for Redundancy concept
Nodal analysis pe bhi video upload kijiye
no calculation need . We can direct say that the current following through 50ohm is 10A.
Current from 50 ohm resistance is 9.99A.
X=-1
Y=9
Z=-1.3
I=9+1=10
Best place to find mistake on Earth:
Comment Section 😂
I liked you concept ...
Maja aaya.
Hlw.. Bhaiya.. Thanks for these videos.. My mid sem is from 9 march.. going through your videos.. Can you please tell me if I watch this playlist and go through PYQ and sir's notes will I be able to solve & pass in exams..?
Answer is = 7.22-(-2.77)= 9.99 A
Excellent video sir all doubts are clear thanks 🙂👍👍But replace -90 by 90.🙂
Yeah! You trying to your level best, and I like to your teaching style, bhai ek board lelo or achcha lagega, it's not looking clear your circuit.
agar wo 10 amp current source ke sath series me ek resistance hota toh bhi ye super mesh hota kya?
Very good
I1=1.88A
I2=12.80A
I3=2.80A
I2-I3=10A
Tomorrow I am going to graduate. I wanna thanks you.
thanks bro, you made it very easy
I1=-1.465
I2=7.225
I3=-2.775
Sir plz Laplace transform in network ..par ek video banaiye na plz sir
thanks u very much for the video.. it really helped me in my exam preparation
-7.187
-2.3125
-12.31
why we need to solve the last one as the current source is in series so the current must be equal to current source = 10 A. Right??
Brother aap apne vedio me part1 part2 name deke bnaya kro ishse concept aur achhe se clear hoga
It's 30I2-90I3=-90
THEN I1 =10.22,I2=0.22,I3=1.07
I(1)=-13 I(2)=7.5 I(3)=-2.5
So I(2)-I(3)=7.5+2.5=10
Nice..
say dat v r neglecting significance of current source by open ckt. for voltage source v r short ckt by that v can neglect its significance while v r applying super mesh r super node respectively
Thanks for the useful information 👍
Great sir🎉
i¹=-1.46A
i²=7.22A
i³=-2.77A
I1=-0.26 i2=9.230 i3=-0.76 and across 50 resistance cureent is -9.99amper
Good evening sir
Thank you sir😊
The current in 50 ohm resistance is 10A
thanks bro your videos are very helpful
Behtreen....ho gaya.....from pakistan
Sir wo supermesh me +20 hoga na 20 khudka hai na share wala nhi hai ese lea
Bhai bahut achha samjhaya
I1=1.2Amp
I2=7.53Amp
I3=-2.47Amp
Tq bro❤️❤️❤️❤️❤️❤️ today is my exm...
kadak ek dum
Current through 50 ohm resistor is 9.99~10 A
sir plzz kvl and kcl with dependent source par video upload kijiye with simple tricks
Good
i¹=0.2352 , i²=10.058 , i³=0.058
i²-i³=10.058-0.058=10💪💪
Thank you brother, good luck 🎉🎉🎊🎊
broh i also got the same 9.99amps ==10amps
yes bro me to got 10 amp answer thank you to make my answer correct by commenting 😇
bhaiya 2nd Q mein voltage ke parellel mein resistance bhi hai toh humne usko neglect kyun nhi kiya?
Love you bro from pakistan
Use +90 in equation 1
Just a doubt there is a current source in that branch so can't we simply apply current is 10 ?
Last mesh me direction anticlock wise ayega na
in the last question , can we just use 2 equation ? 1st one for the junction , i1+i2=i3 and from the current source i2-i3=10?
I like your video may God you long life b/c your video help us
I3-I2= 4.4A
Wao Bhaiya!
Thank you bhaiya
Welcome
Sir calc konsa
Bhai jab mesh me 3 loop ho to konsi trick use kre
Sir plz confirm 1thing when we apply kvl in each loop and find eqn. at that time only we hv to ignore that resistance?
Nice
Eya mera vi same question?
Tysm sir 🙌❤️
Welcome
Bhai 3 wale minute main 2 ND mesh main ek resistance v hai....uska Kya???
I2 wale ke sath positive sign aye ga r -90 I3 hoga bhai
Sir I have a doubt 🧐
R×I=V according to matrix.
than i1-i2 = 10 .ye 10 to current hai
Fir matrix likhate time voltage me kyu .????🙄
thank you
Meri engineering hone ka credit bhai tumko dunga 🙏
Can u please tell if the resistance is joined with negative potential of battery than how to convert into current source
Thanks Sir..
From Pakistan.
what would be the supermesh equation, if current is in upward direction???? like (↑)
Thank you so much
Really helped in the last moment!! 👍😀
50ohm me 9.995A=10A current follow hoga
Source conversion apply nahi kar sakte kya
Sir Can u please release a video of mesh analysis with dependent sources
I3-i2 = -9.9A is it correct sir
Mistake: 1:29
In RHS, it's going to be +90. (not -90)
Nhi brother Mai bhi janta hu ki current ki direction clockwise hai par current plus se enter hokar minus par end hota hai to -90 hi aayega mujhe bhi bahut confusion tha par mene book me dekha to doubt clear ho gya.
Confused with _ ve and +ve sign!!!!!!
You are amazing!!!
Thanks alot
Solution of the last problem:
Equations are:
50i1 +0i2 +0i3 = 10
0i1 + i2 - i3 = 10
3i1 - 4i2 -12i3 = 0
Upon solving we get:
i1 = 1.52 A
i2 = 7.78 A
i3 = -2.21 A
As i2 is greater than i3
We do i2 - i3
=> 7.78 - (-2.21) A
=> 9.99 A
Hence 10 A current is flowing through the 50 ohm resistor.
in your first equation how there is 0i3 it should be 30i3 na
@@gauravraj8728 han bro galat likha hai vo
I3 value is 3.66A
In short sir you are rock💗💖
Thank you
i= 9.99 A ~ 10 A