I'm Solving An Exponential Equation

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  • Опубліковано 20 жов 2024

КОМЕНТАРІ • 14

  • @barberickarc3460
    @barberickarc3460 4 місяці тому +2

    Struggled for a bit to put the equation in a proper form but after the first few steps the solution method was apparent.
    Write the equation in simplest form, 3^x * 5^(2/x) = 3^2 * 5
    3^(x-2) = 5^(1-2/x)
    Ln everything, multiply by x and distribute the ln3 and ln5. Move some stuff around and you have a quadratic in x. After simplifying we see the discriminant is a perfect square and solving further we get two solutions, x=2 and x=log_3(5)

  • @Sugarman96
    @Sugarman96 4 місяці тому

    The second solution is cool when actually plugged in. Like the immediately apparent x=2, it produces the two factors of 5 and 9, except from the other bases

  • @Skyler827
    @Skyler827 4 місяці тому +1

    I was able to formulate the quadratic, and I can guess and check the x=2 solution, but i wasn't able to simplify it when I tried to solve it. Great problem and great solution!

  • @neuralwarp
    @neuralwarp 4 місяці тому

    Well, by "guess and check", x=2, but rigorously, what other solutions are there?

  • @KoiMorris
    @KoiMorris 4 місяці тому +4

    You forgot to show the graph of the functions at the end.

    • @jackyzhang588
      @jackyzhang588 4 місяці тому

      😊😊 I'd say the same thing.

  • @jurajhabek2782
    @jurajhabek2782 4 місяці тому

    Correct me if I am wrong, for I have came to the solution that is much shorter and more easy to understand:
    3^x * 25^(1/x) =45
    3^x * 5^(2/x) = 45
    3^2x * 5^2 = 45^x
    3^2x *25 = 45^x
    9^x *25 = 45^x
    25 = 45^x / 9^x
    25 = 5^x
    5^2 = 5^x
    2=x

  • @DineshMohapatra-ng5xe
    @DineshMohapatra-ng5xe 4 місяці тому

    Another solution is here,
    3^x. 25^1/x= 45
    =3^x.25^1/x = 3^2×(5^2)^1/2
    Compring both side we get,
    X=2 😮

    • @auztenz
      @auztenz 4 місяці тому

      Near end of vid

  • @rakenzarnsworld2
    @rakenzarnsworld2 4 місяці тому

    x = 2