Because the example uses stations for the length, it's appropriate to keep 4.8 as a percent. Using stations instead of feet effectively compensates for using 4.8 instead of 0.048. So, the calculation could be -4.8*(5.5/2) or -0.048*(550/2). Let me know if that makes sense.
Great question - in this video, starting at about 2:48, you can see how the elevation of each whole station is established. The key is to find the appropriate "x" value, which is the distance from the PVC, for each station (you can use a table like this one to set up your calculations).
Can you provide a little more detail/description about what you're looking for? With the grades, you can find the angles around the PVI, but I'm not sure how you plan to use them or what you're trying to solve for.
@@FindleyDaniel Thank you very much. I am from Iraq, a student. I would like to get the source that you depend on. I study on UA-cam, through your very elegant explanation. May I get the source and solutions, and I hope you will upload other clips on the vertical curves
@@mira-zy9jp I have an organized list of videos (including vertical) that might be useful for: sites.google.com/ncsu.edu/daniel-findley/educational-resources
Had this been a crest vertical curve, the elevation of PVC would have been less than the elevation of PVI.
Thanks for the great video.
That's correct!
Thanks for the brief, we hope from you to clarify the unsymmetrical vertical curve calculations.
You made a big mistake at 1:39, you should have converted 4.8% to 0.048, and I checked your math, it was totally multiplied by 4.8.
Because the example uses stations for the length, it's appropriate to keep 4.8 as a percent. Using stations instead of feet effectively compensates for using 4.8 instead of 0.048. So, the calculation could be -4.8*(5.5/2) or -0.048*(550/2). Let me know if that makes sense.
@@FindleyDaniel I see now, I guess I was taught with the second equation you wrote so it really confused me at the time. Thank you it does make sense.
How to get the elevation in every station sir?
Great question - in this video, starting at about 2:48, you can see how the elevation of each whole station is established. The key is to find the appropriate "x" value, which is the distance from the PVC, for each station (you can use a table like this one to set up your calculations).
Thank you.
You're welcome!
Need to find angle at pvi how this please solve thanks
Can you provide a little more detail/description about what you're looking for? With the grades, you can find the angles around the PVI, but I'm not sure how you plan to use them or what you're trying to solve for.
Sir send me mail address I send u what I want to solve
ncees hb 1.1, p. 278.
can you answer me please
Bsdk
can you answer me please
Sure, what's your question?
@@FindleyDaniel Thank you very much. I am from Iraq, a student. I would like to get the source that you depend on. I study on UA-cam, through your very elegant explanation. May I get the source and solutions, and I hope you will upload other clips on the vertical curves
@@mira-zy9jp I have an organized list of videos (including vertical) that might be useful for: sites.google.com/ncsu.edu/daniel-findley/educational-resources