Make videos on combinatorics and probability problems as well If possible, create a discord channel where you could get problem suggestions from viewers. It could also serve as a platform for us to get help (from other members) on the problems in which we are stuck.
Interestingly, if you flip the sign of 3q³ into p³ - 3q³ - 32, you still get q = 2, but an infinite number of values for p. Here is a few: 13³ - 3∙2³ - 32 = 2141 19³ - 3∙2³ - 32 = 6803 43³ - 3∙2³ - 32 = 79451 73³ - 3∙2³ - 32 = 388961 109³ - 3∙2³ - 32 = 1294973 127³ - 3∙2³ - 32 = 2048327
You make things look so easy. Brilliant solution sir. Loved it !!
Make videos on combinatorics and probability problems as well
If possible, create a discord channel where you could get problem suggestions from viewers. It could also serve as a platform for us to get help (from other members) on the problems in which we are stuck.
Once I realised that the LHS is even for p,q >2 it was a simple matter of testing p=2 and q=2.
I did it like you but I started with p,q = 2.
Interestingly, if you flip the sign of 3q³ into p³ - 3q³ - 32, you still get q = 2, but an infinite number of values for p. Here is a few:
13³ - 3∙2³ - 32 = 2141
19³ - 3∙2³ - 32 = 6803
43³ - 3∙2³ - 32 = 79451
73³ - 3∙2³ - 32 = 388961
109³ - 3∙2³ - 32 = 1294973
127³ - 3∙2³ - 32 = 2048327
You pleased me ,Mr.Mizard X.Let your brain power ,health and spirituality be enhanced !!! God bless you !!!
Wow that was super brilliant
You make things easier with just a simple trick
it is magic!
K I liked your solution very much
It’s not just a valid solution it’s the only solution.
Great question and solution.
Genial.
p=2 and q=3 gives the Grothendieck prime 57.
looool
P=3 and Q=2
Just read what he had written
Lol