It base on the you use the spectrum scan by photon different imagine the distance as small as 3.3×10^-43 in an in of cc'd array then you can enlarge it to the able to see even 1×10^-10 m from a distance l /d= sine 45 and d = c × 2t = (64600 km/ s ) ×2t
100... since it is 10m resolution. A 100*100 m2 football ground can be divided into 10 rows and columns of 10m length. So 10*10 = 100 pixels will be the answer.
Thank you very much, from South Africa 💯🌍🤗
Great to see you here sir!! :) One of the best profs in Xaviers !
Thank you sir. Sending love from Sri Lanka
Great! Thank you for this clear explanation.
thanks you master from dominican republic
Crystal clear knowledge ✌️.
simple, clear explanation.
Clean and clear explanation, thankyou very much sir
very good Sir... so pleased by your way of explaining
It's very simple and clear👏
Very nice explanation sir ... thank you
that was best description
Please continue uploading videos of thisss
Thank you sir, wonderful explanation
nice and clear..thank you sir!
Thankyou so much professor, please give insights also on spectral and radiometric resolution
ua-cam.com/video/61jLqkITogk/v-deo.html
Very clearly explained.
Thank you. It's clear.
Really great video!
thank you sm sir,this helped a lot
i did not understand how a can you see a field wild big if your remote sensor is 10 meter above the ground
Thank you for this information sir
It base on the you use the spectrum scan by photon different imagine the distance as small as 3.3×10^-43 in an in of cc'd array then you can enlarge it to the able to see even 1×10^-10 m from a distance l /d= sine 45 and d = c × 2t = (64600 km/ s ) ×2t
Thank you
Thanks
GOD BLESS You
Thank you sir
Awesomeness.
10 pixels or hundred? 1:27
100... since it is 10m resolution. A 100*100 m2 football ground can be divided into 10 rows and columns of 10m length. So 10*10 = 100 pixels will be the answer.
@@mandeepashiya2229 thank you
Thank uu sir