Hello bacho, isme ek question tha maine trim karwa diya hai taaki bache galat na samjh le. Usme resistance across diameter bola tha humne total nikal diya tha. Next session me karwaunga abhi trim kar diya hai. Thanks
Sir at 1:40:35 the question is asking resistance between end of the diameter that means the upper half and lower half part of the conductor is in parallel combination Resistance of upper half= 2×10^-3 × π(1) and same of lower half and both of them are in parallel combination So 2×10^-3 ×π /2 So the effective resistance comes out to be = 10^-3 × π that is option a
1:42:50 sir iss question me resistance across ends poocha hai to hume diameter ke end me do wires jod ke paralel ka net resistance nikalna hoga so I'm sorry but answer π x 10-³ hoga maine google bhi kiya hai.
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1:42:50 sir iss question me resistance across ends poocha hai to hume diameter ke end me do wires jod ke paralel ka net resistance nikalna hoga so I'm sorry but answer π x 10-³ hoga maine google bhi kiya hai.
Complete step by step answer: Resistance is defined as where The resistance per unit length is given to be Ohm per metre. So the length can be calculated as where is given a diameter of 2 m. Hence L= 2π metres. Therefore, Now when the resistance is measured between ends of any diameter, it can be seen as a parallel connection of two resistances R/2 each. Solving we get So the resistance between two endpoints of a diameter will be R/4 i.e. .
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1:40:28 answer should be option a )π×10^-3....please recheck as it is asking the resistance between 2 points of circle not the resistance of full circle
sir last third question 1:41:30 m option a correct h bcz usme resistance between the diameter end pucha h jisse total resistance half hoke parallel m add ho jayega aur option c ki jagah option a hoga . thank you sir for the class 😍
Hello bacho, isme ek question tha maine trim karwa diya hai taaki bache galat na samjh le. Usme resistance across diameter bola tha humne total nikal diya tha. Next session me karwaunga abhi trim kar diya hai. Thanks
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Sir at 1:40:35 the question is asking resistance between end of the diameter that means the upper half and lower half part of the conductor is in parallel combination
Resistance of upper half= 2×10^-3 × π(1) and same of lower half and both of them are in parallel combination
So 2×10^-3 ×π /2
So the effective resistance comes out to be
= 10^-3 × π that is option a
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1:42:50 sir iss question me resistance across ends poocha hai to hume diameter ke end me do wires jod ke paralel ka net resistance nikalna hoga so I'm sorry but answer π x 10-³ hoga maine google bhi kiya hai.
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1:42:50 sir iss question me resistance across ends poocha hai to hume diameter ke end me do wires jod ke paralel ka net resistance nikalna hoga so I'm sorry but answer π x 10-³ hoga maine google bhi kiya hai.
Complete step by step answer:
Resistance is defined as
where
The resistance per unit length is given to be
Ohm per metre.
So the length can be calculated as
where
is given a diameter of 2 m. Hence L= 2π metres.
Therefore,
Now when the resistance is measured between ends of any diameter, it can be seen as a parallel connection of two resistances R/2 each.
Solving we get
So the resistance between two endpoints of a diameter will be R/4 i.e.
.
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1:40:28 answer should be option a )π×10^-3....please recheck as it is asking the resistance between 2 points of circle not the resistance of full circle
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sir last third question 1:41:30 m option a correct h bcz usme resistance between the diameter end pucha h jisse total resistance half hoke parallel m add ho jayega aur option c ki jagah option a hoga . thank you sir for the class 😍
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