Розмір відео: 1280 X 720853 X 480640 X 360
Показувати елементи керування програвачем
Автоматичне відтворення
Автоповтор
Please correct me if I am wrong.It seems that in your calculations you have substituted a diameter equal 0.25 m for pipe # 5, not 0.20 m - as indicated in the table with data.Great video, allowed me to finally understand this method!
You are right
Are there any solutions to the Assignment question provided?
Where did the 6.02x10^-9 came from?
I got .0021 instead of 6.02x10^-9. Is that an error or am I missing something?
I got 0.0000021 (if you multiply 1000 to convert m3 to L)
@@dand7056 When you transfer 1000 that divides Q, you need to apply 1000^1.852
Can be hL value is minus?..
Thank you so much for this Sir.
keep it up👍👍👍
Thank you very much sir
nice video.... except backgroung noise
Please correct me if I am wrong.
It seems that in your calculations you have substituted a diameter equal 0.25 m for pipe # 5, not 0.20 m - as indicated in the table with data.
Great video, allowed me to finally understand this method!
You are right
Are there any solutions to the Assignment question provided?
Where did the 6.02x10^-9 came from?
I got .0021 instead of 6.02x10^-9. Is that an error or am I missing something?
I got 0.0000021 (if you multiply 1000 to convert m3 to L)
@@dand7056 When you transfer 1000 that divides Q, you need to apply 1000^1.852
Can be hL value is minus?..
Thank you so much for this Sir.
keep it up👍👍👍
Thank you very much sir
nice video.... except backgroung noise