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@Vedantu JEE I had written the benchmark test and scored 175 and 145 in the test and also have 98.96% in jee mains . But so far no call or message has been recieved in my side.I wish to be a part of the eklavya batch.Im very desperate for jee advanced.The classes are starting today plz sir
@@zeelgajeraa by drawing free body diagram we can see that mg acts downward and N upward also accl. of g/2 acts in upward direction. From that we get, N - mg = ma i.e., N- mg = mg/2 The value of N is 3mg/2 Now we have to find displacement so U=0 a=g/2 Using S=ut + 1/2 at² we get S=gt²/4 Then applying W=N.S u'll get uption D as ans
Mechanics module of Physics is so interconnected that each problem can be solved in at least two ways. Newton's laws/conservation of momentum or energy method. This is the actual beauty. ❤️
As upward force= mg+N thus N= mg/2(if not so block is not intact with plywood) now W=F.ds,as constant acceleration is there using v=u+at ,v=gt/2 ,v=ds/dt so W=mg^2t^2/8 option b is correct
No bro it's just u have to put s = ut +1/2.g/2.t^2 since it start from rest so u=0 and force is N +ma which is mg+mg/2 = 3mg/2 so after applying W=F. S ...... U got option (d) 👍👍
Why cant answer be option B work done by this force equal to change in ke and hence w equal to 1\2 mv2 and v can be found out be integrating acc so w equal to half mg^2t^2by 8 that is option b
In the lift question why did the external force becomes equal to weight and friction. if it so then the lift will be at rest how do we calculate max velocity?
Sir the ques in which work is to be calculated at first 5 second...where X=3t^2+5 .....why I am not getting 900 J answer by using W=F × X(at t=5sec)....is this formula invalid in this ques to apply ... I had done F=Ma (M=2kg; a=6ms^-2) ×X(at t=5sec) Ans of last Ques is option D
@@ayushbisht9539 That's because you're messing with the position function ,x = 3t²+5 as displacement, calculate position at t=0 and t=5s and find their difference to get displacement. On double differentiating the postion function the acceleration comes out to be a constant 6m/s², then use the above logic .
many students who have written the test and scored 99% above and were excited for the eklavya batch but still are waiting ,while others have been added to this batch. What about us??
Because you are calculating the work done by F. In question we has to find the work done by Normal reaction (N) & not F After drawing free body diagram, u will get N=3/2mg. Now use S=ut+1/2at² (HEre , u=0, a=g/2) ..S=gt²/4 Work (done by normal reaction)=N.S=3/2mg.gt²/4=3/8mg²t²
✅ Use Code SMCC to Get 5% off on JEE Crash Course (Limited Time Offer): vdnt.in/JEECCE
For more updates 📢 Join our telegram group: vdnt.in/JEEVedantu 🔔
@Vedantu JEE I had written the benchmark test and scored 175 and 145 in the test and also have 98.96% in jee mains . But so far no call or message has been recieved in my side.I wish to be a part of the eklavya batch.Im very desperate for jee advanced.The classes are starting today plz sir
Sir please first take some theory part in session then solve the paper. That will help us a alot
Hey guys,
Suri (Mogambo) sir here
The correct answer to the HW question is option (D)
Congratulations to those who got it right 👍
Sir can u please teach in crash course
Sir, can you please explain the HW question of thie video. I am not getting it.
Awaiting for your earliest reply.
@@zeelgajeraa I too didn't understand the question
@@zeelgajeraa by drawing free body diagram we can see that
mg acts downward and N upward also accl. of g/2 acts in upward direction.
From that we get,
N - mg = ma
i.e., N- mg = mg/2
The value of N is 3mg/2
Now we have to find displacement so
U=0
a=g/2
Using S=ut + 1/2 at² we get
S=gt²/4
Then applying W=N.S u'll get uption D as ans
@@KhushiS879 thanks khushi
Appreciate u for ur efforts
Which std?
7:40 from here actual class started
Really needed this info...
Thnx u save my time
Thanks 😊
Exactly
Mechanics module of Physics is so interconnected that each problem can be solved in at least two ways. Newton's laws/conservation of momentum or energy method. This is the actual beauty. ❤️
As upward force= mg+N thus N= mg/2(if not so block is not intact with plywood) now W=F.ds,as constant acceleration is there using v=u+at ,v=gt/2 ,v=ds/dt so W=mg^2t^2/8 option b is correct
No bro it's just u have to put s = ut +1/2.g/2.t^2 since it start from rest so u=0 and force is N +ma which is mg+mg/2 = 3mg/2 so after applying W=F. S ...... U got option (d) 👍👍
Answer to the question is 3mg²t²/8 .
N= 3mg/2 and s= gt²/2
And work done = F.S
N=3mg/2, S=gt²/4
Why cant answer be option B work done by this force equal to change in ke and hence w equal to 1\2 mv2 and v can be found out be integrating acc so w equal to half mg^2t^2by 8 that is option b
Answer for HW question is D . Thanks for an amazing session sir.
how
??
The answer for the homework question is option D
Answer to hw should be (d) 3mg²t²/8
In the lift question why did the external force becomes equal to weight and friction. if it so then the lift will be at rest how do we calculate max velocity?
D. option of the correct answer of final question
The answer of the last question is D
Correct answer is B
Yes sir H.W que, answer is D
Sir why we are not using formula W=F.S in this Question (Time 27sec )
Ans is option d as total force acting on the block is F+N
Answer D
Sir f=-du/dr
Yes subhita deepchand i also have same doubt why did sir write f=du/dr??!! Anyone please help
HW ANSWER is option
D 3mg²t²/8
How can join sri
Sir at 12:48 formula is f= -(du/dr)
rank should be inversely proportional to number of chapters we are good at...............think practically
session starts from 7:35
could u plz tell me where is pahul sir?...why he is not appearing since many days.....we need his classes.....
3mg square tsquare ÷8... Ie d option
Sir if i just listen this lectures n do previous year ques it is enough?
Answer is D
Sir the ques in which work is to be calculated at first 5 second...where X=3t^2+5 .....why I am not getting 900 J answer by using W=F × X(at t=5sec)....is this formula invalid in this ques to apply ... I had done F=Ma (M=2kg; a=6ms^-2) ×X(at t=5sec)
Ans of last Ques is option D
Because x is given position not displacement..
At t=0... X =5 &
@ t=5....X=75...
So actual displacement is 70.
Yes I too do in that way
I also not getting the ans
If u get so share it with me
@@ayushbisht9539 That's because you're messing with the position function ,x = 3t²+5 as displacement, calculate position at t=0 and t=5s and find their difference to get displacement. On double differentiating the postion function the acceleration comes out to be a constant 6m/s², then use the above logic .
the first question can be handled easily by dimensional analysis
Last question answer is 3/8mg2t2
Sir bring such videos its helpful you are awesome sir love your teaching 😍😍😘😘
36:56 sir if V(max) = 1.86
Thn answer should be less than 1.86
i.e B) 1.7
and not 1.9
Sir ans to that question is D
Really
But how?
Sir can we solve the 3rd question using WE Theorem?
Sir to you are best
Correct ans for last ques is B.
Thanks sir for such an awesome session 👍👍👍👌👍😊
Will there be sprint for April mains?
H. W. Question answer is D
Lecture starts at 7:31.
many students who have written the test and scored 99% above and were excited for the eklavya batch but still are waiting ,while others have been added to this batch. What about us??
Same with me
I have tried to know about the classes by email and phone too, but they haven't yet given any reply
Hi karthik, All the shortlisted students will be contacted directly by Vedantu for Eklavya Batch.
@@JEEVedantu are the admissions still going on? Im very sorry for my outrageous manner of comments. Im just very frustrated.
Hy did anyone get a call?
@@pavan4019 me abt crash course
Sir can't we do the question of work done in 5 seconds
By finding acceleration
I tried but got diff.ans
You'll get the same answer.
I got 1800
How I got 150000000054564550000
Answer of last question is option B
Sir plzzzzzzzzzzzzzzzzz provide an assignment too to do after your session plzzzzzzzzz
@29:10 why am I not getting answer with W=F.S?
Because you are calculating the work done by F.
In question we has to find the work done by
Normal reaction (N) & not F
After drawing free body diagram, u will get
N=3/2mg.
Now use S=ut+1/2at²
(HEre , u=0, a=g/2)
..S=gt²/4
Work (done by normal reaction)=N.S=3/2mg.gt²/4=3/8mg²t²
Video start at 7:30 sorry 7:32
At 12:28 F=du/dr how??
U = integral of F.dx so thats where it comes from.... but i think u already have appeared for jee lol
@@theadieke6584 kafi jldi bta dia ..... btw im in dtu😎
@@mohdshahnewaz4075 congrats!
@@theadieke6584 thx
Suri sir please take class on rotational dynamics for adv and mains...
Yes I am not good in this chapter
Sir I'm getting option D
sir answer for the H>W question is D) . thanks for such a wonderful session.
Sir but F = -du/dt
Option D is right sir
Sir answer to the given homework is option d
Ans to hw q is D
EXCELLENT Explanation
"As simple as that".............😄😍😍💓💓
Sir u should please teach in crash coarse
Last question answer is 3mg2t2/4, there should be 4 in denominator Am I right??
Thanks for this awesome session sir 😊😊and the answer for h.w question is D)
Option d
amasing sprint sir hw ans.D
Sir session pdf plz
It will be available in the description soon.
sir you had made a major mistake as F = -du/dr
Yes
Yoo Sir very good
B
The answer to question is option D
D
Hindi me padha karo in india because of nation language
Hello disha
f vedantu
D
D
D
D