why you dont take the structure as a whole? is it already in equilibrium condition so you can take FBD below the cut wire ? is it because you already found the value of Nab so you can consider the structure already in equilibrium condition? because we still dont know the value of Ax and Ay, and if you take the structure as a whole, will the structure considered as indeterminate structure? or we can use B as an internal hinge so it remains determinate ?, thx for the video, very helpful
the position of the resultant force from the thin side of the triangular distributed load will 2/3 the base, here's the proof ua-cam.com/video/I-IWpPNcFDI/v-deo.html
Yes. Waiting u
U are honnorable teacher love from Somalia
Always fun to watch. Thanks for sharing.
why you dont take the structure as a whole? is it already in equilibrium condition so you can take FBD below the cut wire ? is it because you already found the value of Nab so you can consider the structure already in equilibrium condition? because we still dont know the value of Ax and Ay, and if you take the structure as a whole, will the structure considered as indeterminate structure? or we can use B as an internal hinge so it remains determinate ?, thx for the video, very helpful
The value of w is correct! 😅
Woo hoo. Thanks!
how did you come up with the distance of the resultant force from point c?
the position of the resultant force from the thin side of the triangular distributed load will 2/3 the base, here's the proof ua-cam.com/video/I-IWpPNcFDI/v-deo.html