Ampere's Law: Magnetic Field in a Coaxial Cable

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  • Опубліковано 16 січ 2025

КОМЕНТАРІ • 204

  • @lNDlANSPlCE
    @lNDlANSPlCE 5 років тому +39

    Why doesn't this have more views... I'm gonna share it with all my emag friends. Thank you, Ninja! When I graduate and have an engineer's salary I will be able to contribute and quantify my gratitude for your videos!

  • @brianrook6207
    @brianrook6207 5 років тому +25

    An outstanding presentation. It has cleared up all the problems I had understanding the physics behind coaxial cables.
    Thank you
    Brian Rook

  • @ronnyalfons7096
    @ronnyalfons7096 4 роки тому +4

    Without watching about 2 minutes of the video, i can already tell that there's good teaching in this video

  • @hughrountry1281
    @hughrountry1281 7 місяців тому +4

    Audio mixing could be improved, but the content is very helpful.

  • @rifusaki
    @rifusaki 3 роки тому +2

    You've just saved an anonymous student on the internet! This explanation is awesome!

  • @leandrogarcia6396
    @leandrogarcia6396 2 роки тому +2

    This is the best video on the god damn internet

  • @laisguizelli25
    @laisguizelli25 3 роки тому +2

    Congratulations from Brazil, your video help me a lot!!

    • @PhysicsNinja
      @PhysicsNinja  3 роки тому +1

      Thanks for watching and the support. It's great to hear from students.

  •  6 років тому +2

    Hey dude I guess you made a mistake. It will be good for you if you check the b

  • @gideonkyeremeh868
    @gideonkyeremeh868 5 років тому +2

    Thanks Ninja... Just got it at the right time for my presentation the next morning

  • @libertyprime656
    @libertyprime656 3 роки тому +3

    Excellent video, thank you for creating this. Studying for my E&M final and this has been extremely helpful

  • @bobross5716
    @bobross5716 5 років тому +5

    Thank you so much! Not even Griffith’s could properly go over these types of problems

    • @estebansingh9411
      @estebansingh9411 3 роки тому +1

      In my experience UA-cam tutorials work better than books. At least better than griffiths, purcell and thermodynamics books

  • @etanetan101
    @etanetan101 2 роки тому +2

    I think you just saved me before my midterm tomorrow. 😂 Thanks so much!!!

  • @cosmolearner5562
    @cosmolearner5562 4 роки тому +1

    @21:05 Which current is taken positive and which one negative is also included in ampere's law -
    First arbitrarily consider the direction of path that you have choosen (generally taken same as magnetic field)
    The apply right hand thumb rule to the path choosen the direction of thumb is taken as positive that mean on applying RHT rule on path all the enclosed current in the direction of thumb are taken as positive and all other currents opposite to direction of thumb are taken as negative..

  • @lagado1lag
    @lagado1lag 3 роки тому +5

    Amazing! I really understood the exercise. Thank you!

  • @wlk1757
    @wlk1757 2 місяці тому

    I have question, in the b

  • @dareadegun2460
    @dareadegun2460 2 роки тому +1

    Thanks for the clear and smooth explanation

  • @piao-o3w
    @piao-o3w 2 роки тому

    It is the best video for a college student studying electromagnetism. It was very helpful. Thank you.

  • @jennykeeling747
    @jennykeeling747 Рік тому +1

    This was explained so well thank you so much!

  • @karthikkrishnan7558
    @karthikkrishnan7558 4 роки тому +1

    simple explanation...helped me a lot.. Thank you Sir

  • @lilac.2858
    @lilac.2858 10 місяців тому +1

    So well explained!

  • @igorsantos-qj3zd
    @igorsantos-qj3zd Рік тому +1

    Thx from Brazil!

  • @JH-ux1re
    @JH-ux1re 2 роки тому +1

    Perfect! I was always confused by these things. Thank you very much! Saved me!

  • @asgoodasbread5559
    @asgoodasbread5559 2 роки тому +1

    Great Explanation !! TY

  • @sor3na369
    @sor3na369 Рік тому +1

    Thanks for great explanation.

  • @shaunwu3609
    @shaunwu3609 6 років тому +1

    Thanks for going into the details! You have a nice voice as well!

  • @brayschway6746
    @brayschway6746 3 роки тому +2

    This was beautifully done. Thank you.

  • @juliazhang3600
    @juliazhang3600 4 роки тому +1

    simple explanation! I love it!

  • @Mehmetalp99
    @Mehmetalp99 2 місяці тому +1

    Great explanation

  • @rodolfogarcia6263
    @rodolfogarcia6263 6 років тому +1

    Would a

    • @PhysicsNinja
      @PhysicsNinja  6 років тому

      This is done @ 10:44. In this case the field is not 0 because the Amperian loop will enclose all of the current within the small wire in the middle.

  • @kabandajamir9844
    @kabandajamir9844 8 місяців тому

    The world's best teacher thanks sir

  • @masouddayaghi5923
    @masouddayaghi5923 6 років тому +4

    Thanks a lot man, it was wonderful.

  • @boysenbeary
    @boysenbeary 3 роки тому +1

    Great explanation!

  • @pierretobgui1792
    @pierretobgui1792 5 років тому +1

    Really helpful

  • @salmamahameed2160
    @salmamahameed2160 3 роки тому +1

    this isn't an empty cable right? like it's not a shell of a coaxial cylinder cable? and if that was the case shouldn't the magnetic field in the r

  • @cnnn7885
    @cnnn7885 5 років тому

    for b < r < c situation, why is it (r^2 - b^2) but not (r - b)^2 , same as (c^2 - b^2)

    • @PhysicsNinja
      @PhysicsNinja  5 років тому +1

      Because the area will be the difference between r and b. Pi- r^2 will be area. Of entire circle then take away area of inside part Pi-b^2. The area is not pi- ( r-b)^2

  • @HakaiShakai
    @HakaiShakai 3 роки тому +1

    Literally saved my life
    God bless your soul

  • @jorgemillan4041
    @jorgemillan4041 5 років тому +1

    these are great please make more

  • @rakibuddin385
    @rakibuddin385 5 років тому +1

    Thank you so much .you explained so easily

  • @sealol5209
    @sealol5209 6 років тому +1

    Thanks man! Was having trouble understanding this question!

  • @HuFocus-f2y
    @HuFocus-f2y 2 місяці тому +1

    Why cant my professors make videos like these!!! Thank you

  • @hasranman
    @hasranman 5 років тому +1

    This really helped me. Thanks!

  • @EnzoChai
    @EnzoChai 5 років тому +1

    Tq very much man...save my day 🙌🙏

  • @Arif.mohmand
    @Arif.mohmand 2 роки тому +1

    Very nicely presented, at the end you said, it was a special coaxial cable with the both the same currents, thats is why B is zero, wasn't it zero because they were different currents in the direction?

    • @PhysicsNinja
      @PhysicsNinja  2 роки тому

      Same current, different direction will result in 0 field outside of cable because total current enclosed is 0.

  • @MayankLC93
    @MayankLC93 5 років тому +1

    GREAT HELP SIR !!!
    💞INDIA

  • @user-ny1vt3ek4i
    @user-ny1vt3ek4i 4 роки тому

    Thank you Physics Ninja!!!!

  • @linjisoo9975
    @linjisoo9975 3 роки тому

    Very helpful video!

  • @taladiv3415
    @taladiv3415 4 роки тому

    Thank you for this clear solution.

  • @saffyt348
    @saffyt348 6 років тому +1

    This was so helpful! Thank you!

    • @PhysicsNinja
      @PhysicsNinja  6 років тому

      Glad the video was helpful for you.

  • @뿌엥-w7d
    @뿌엥-w7d 3 роки тому

    You’re better than my professor, thank you

  • @thuonghoang530
    @thuonghoang530 3 роки тому

    thank for your lectures, I am a teacher, I would like to know exactly the divide you (everyone) used to draw lectures beautifully?

  • @sanskararora6425
    @sanskararora6425 4 роки тому

    as the inner cylinder is a conductor so all charges would be at the surface of the cylinder and hence the current should flow through the surface (as current is the flow of charges) so I would be zero for r

  • @kholoudhakim7887
    @kholoudhakim7887 5 років тому +1

    thanks so much

  • @ShrabantiDeb
    @ShrabantiDeb 2 роки тому +1

    better explanation than books..

  • @maxdougherty3429
    @maxdougherty3429 4 роки тому

    Great explanation! I wish I had you teaching my physics class!

  • @asmartguycodename4721
    @asmartguycodename4721 3 роки тому

    Thanks for this great help. 😃

  • @betulguncaldi4676
    @betulguncaldi4676 4 роки тому

    Beautiful explanation! You're great! :)

  • @matthew_bang
    @matthew_bang 4 роки тому

    Fantastic work

  • @peytonkliewer1997
    @peytonkliewer1997 3 роки тому

    Thank you so much! This was very helpful!

  • @antirunescape4128
    @antirunescape4128 Рік тому +1

    thanks but too many ads interrupting

    • @limdronephooh910
      @limdronephooh910 8 місяців тому +1

      You choose the premium and no advertising

  • @ezefferth
    @ezefferth 3 роки тому

    Brasil love's you!! grateful!!

  • @aprilsianpi7973
    @aprilsianpi7973 4 роки тому

    i don't think you have to include the interior of I at 13:20 minutes in region (b

    • @PhysicsNinja
      @PhysicsNinja  4 роки тому +1

      Yes you do, it’s the total current enclosed by the loop.

    • @PhysicsNinja
      @PhysicsNinja  4 роки тому +1

      Superposition of fields

    • @aprilsianpi7973
      @aprilsianpi7973 4 роки тому

      @@PhysicsNinja Thank you. You clear up all my confusion.

  • @3washoka
    @3washoka 5 років тому +1

    Thank you 🙏🏼

  • @JD867
    @JD867 4 роки тому

    You're awesome. This helped me a lot.

  • @kateystevenson7912
    @kateystevenson7912 3 роки тому

    Great video, thank you!

  • @RicktokSV
    @RicktokSV 6 років тому +2

    Hi ninja ninja leader. Cheers!!. I have a question, what is the difference between magnetic field and magnetic field intensity? Thank you.

  • @aysenuratagun
    @aysenuratagun 4 роки тому

    Thanks a lot, this video helps me a lot anytime i need :)

  • @yigitarsoy1944
    @yigitarsoy1944 5 років тому +1

    This is awesome!

  • @km-sc4kz
    @km-sc4kz 4 роки тому

    is there any possibility of electric field being produced by this coaxial cable (atleast in a

  • @birahnugmedhin1934
    @birahnugmedhin1934 Рік тому

    You are special❤❤❤❤❤

  • @Zakirhossain-wx8qc
    @Zakirhossain-wx8qc 3 роки тому

    Thank you ♥️♥️

  • @yusufkeskinoz9740
    @yusufkeskinoz9740 5 років тому +13

    Sound needs to be fixed but other than that lecture is okay

  • @allendeguzman6771
    @allendeguzman6771 6 років тому +1

    wow. you nailed it,, well explained.. Wonder if you could make videos about magnetic moments for rotating charge disk, spheres, etc.

    • @PhysicsNinja
      @PhysicsNinja  6 років тому +2

      Thanks for the comment, i'll make a video tomorrow night comparing the magnetic moments of a disk, spherical shell, and a uniformly charged sphere. Physics Ninja loves requests!

    • @allendeguzman6771
      @allendeguzman6771 6 років тому +1

      cant wait to learn form that video..
      ,,,
      this might be too much but it will makes sense if there is also a great video about electric fields, (gauss law) or gaussian surfaces to see connections to amperes law(amperian surfaces.

    • @PhysicsNinja
      @PhysicsNinja  6 років тому +2

      i have a few videos on Gauss' Law. Here's the first of the series. ua-cam.com/video/fGB1csk7tX8/v-deo.html
      I'll try to finish the one on magnetic moments soon. Physics Ninja is a busy guy!

    • @PhysicsNinja
      @PhysicsNinja  6 років тому +2

      Here's the first part of magnetic moment series. I'll add the other 2 parts tonight. Happy Learning! ua-cam.com/video/4F0p_VvYvMc/v-deo.html

  • @THEWouter1212
    @THEWouter1212 3 роки тому +1

    Thanks a lot!

  • @ferhat_ee-76
    @ferhat_ee-76 3 роки тому

    man you are the best, I tried to find the answer to the same question

  • @nabeelljassim6652
    @nabeelljassim6652 2 роки тому

    Great good teacher

  • @monoinluv4894
    @monoinluv4894 3 роки тому

    13:23 does the direction of the current matter in terms of the sign for B? would dl and b be in the same direction?

  • @martinsibanda8026
    @martinsibanda8026 4 роки тому

    thank you well explained

  • @ozanyldz445
    @ozanyldz445 4 роки тому +1

    thanks a lot

  • @johnkay1952
    @johnkay1952 3 роки тому +2

    Just wondering, does this implication of the magnetic field being 0 outside the outer loop bypass the limitations of really small computers? I remember hearing somewhere that there's a limitation of how small circuit elements can get because their magnetic field would induce currents in nearby circuit elements.

    • @TheLeontheking
      @TheLeontheking 2 роки тому

      Good question! I'm not educated enough to answer it, but I would guess that for these small scales the classical theory presented here does not longer hold.

  • @shimabarati7963
    @shimabarati7963 5 років тому +1

    tnx a lot! very well !

  • @aryanviolett4606
    @aryanviolett4606 4 роки тому +1

    Nice! Thanks alot :)

  • @yamaan93
    @yamaan93 3 роки тому +1

    it's a good video and good explanation but the microphone popping makes it quite difficult to listen to

    • @PhysicsNinja
      @PhysicsNinja  3 роки тому

      Thanks. Ninja has a new microphone now.

  • @JamBergMann
    @JamBergMann 2 роки тому

    Great explanation! Thank you. Can we also calculate the B-Field for high frequency currents taking the skin effect into consideration with this method?

  • @fatmanur5409
    @fatmanur5409 Рік тому

    Could you please also calculate the current density for each interval?

  • @teambananakinns
    @teambananakinns 6 років тому

    what if the equation was asking for r

    • @PhysicsNinja
      @PhysicsNinja  6 років тому

      I think the solution cover all values of r. Maybe i don't understand your question

  • @akibmostabe98
    @akibmostabe98 6 років тому

    Well explained,but when u do the closed integration it should be integration over rho product with dfi according to cylindrical co-ordinate system(Here rho is a product with dfi because rho is the perimeter across the arc dfi).Above all its good.
    Another thing is that u may use H(Magnetic field intensity) instead of B (Magnetic flux density) because when we r considering free space only then they aren't equal that is B=meu(o).H.But in practical cases medium may vary according to products choice

  • @uchennaubeh9498
    @uchennaubeh9498 5 років тому +3

    Thanks so much, this clarified my Delima about the magnetic field everywhere in space.

    • @lukedimitriades9835
      @lukedimitriades9835 5 років тому

      Now your only dilemma is learning how to spell dilemma 😂

  • @syedmuhammadhaziqbinsyedah767
    @syedmuhammadhaziqbinsyedah767 3 роки тому +1

    Thank you :3

  • @abhishekpawarpoems
    @abhishekpawarpoems 6 років тому +1

    Thanks brother!

  • @dr.kareemdifar7348
    @dr.kareemdifar7348 6 років тому +1

    God Bless You

  • @AndreaGarcia-rl8cs
    @AndreaGarcia-rl8cs 6 років тому +1

    THANK SO MUCH!

  • @RinaNewhouse
    @RinaNewhouse Рік тому

    Do you know why it matters to take the fraction of the AREA of the cylinders when finding the B field in situations 1 and 3?

  • @antiquarian1773
    @antiquarian1773 5 років тому +1

    what would happen if the currents aren't flowing in the opposite directions? would that mean the current is doubled when r is greater than c?

    • @PhysicsNinja
      @PhysicsNinja  5 років тому

      Yes you are correct, the field would be be different inside the outer shell and outside of both the field would that of a wire with current =2I

    • @antiquarian1773
      @antiquarian1773 5 років тому

      @@PhysicsNinja thank you for the quick response!!

  • @k12h6
    @k12h6 6 років тому +2

    Thanks man

  • @samogx86
    @samogx86 3 роки тому

    Thank you.

  • @eckardbezuidenhout
    @eckardbezuidenhout 5 років тому

    Hello sir, thank you for your thorough explanation. I just need to understand something please. Let us for now consider only the small conductor (gold). Seeing that it is a conductor, will all the charge/current not be located on it's surface only? Ergo, a proper Amperian loop would be such that it goes around the entire conductor and not inside the conductor. This would then change the outcome of this part and the rest of the problem. I need to understand this because there are so many people on the internet doing their own thing and in the end the information conflicts in the small but very necessary details.
    Thank you again for this explanation.

    • @braceyourselvesfortruth2492
      @braceyourselvesfortruth2492 5 років тому

      Not 100% sure but you may be confusing current (moving charges) with static charges. Current is based on cross-sectional density so the amount of the wire we draw our loop around determines the total enclosed current.

  • @johngordon8513
    @johngordon8513 2 роки тому +1

    ur a legend

  • @danilovtoria
    @danilovtoria 6 років тому +2

    Melhor explicação que encontrei

  • @killirina
    @killirina 5 років тому +1

    dude, thank you!

  • @lauraaconceptslk
    @lauraaconceptslk 4 роки тому

    Nice one