voltage= current(amps) x resistance(ohms) so if I need a 6 ohm 12v led to work and I have a 20 volt input at 4 amps so input would be 20 v/4 A= 5 ohms led I used the amperage of the input to find out the resistance to run it 20v /6ohms = 3.333 amps needed? so I need to decrease the amperage to run the 12v 6 ohm led, because if I rework it 12v/6ohm requires 2 amps to run, so If I take the 20v / 2 amps = 10 ohms needed? Might be completely wrong
thank you! have a science exam in a few days lol, i completely forgot about ohms law so here i turn! slight suggestion though is just mention when you rounded something off because i try to solve it first then compare our answers. i thought i was wrong lol anyways, thanks!
I need help with this question The seal of a patch clamp pipette is very important. The resistance of the seal determine how much leak current you will have. This leak current becomes noise when you want to record the current of single ion channels with the pipette. Assume you have an ion channel that allows a current of 2 pA to flow through the current. What is the minimum seal of the patch to half a signal-to-noise ratio of 2. Assume that the pipette is 5 mV depolarized with respect to the outside batch. the answer is 10 GigaOhms but I need to know how that was solved
What would happen if a wire having no resistance at all (0 Ω) were connected directly across the terminals of a 6-volt battery? How much current would result, according to Ohm’s Law?
i took electronics in school years ago and dont ouite remember but i have a battery charger that puts out 24 volts and i want to drop the voltage down to 6 volts, so i decided to use ohms lawso that would mean v/i =r v=24v/1000ma=the resisance
I teach in physics in a high school. My background is in chemistry. These Ohm's law problems are genuinely helpful.
Great that you found them helpful. Send me your email address and I can send you the assignment sheets I have as .pdf files.
This really helped me I am in grade 6 and u are a better teacher than my science teacher ❤
I'm so glad it helped you!
Thank you s much! I'm in 8th grade and I'm having a hard time understanding my modules, an this helped me a lot!😊
Are you from mdps
Thank you! I have my science lab exam today, and it's on Ohm's law. Helped me out a lot :)
Great, hope the lab exam goes well.
This gave me a genuine better understanding of ohms basics. Thank you very much!!
Glad it was helpful!
I was trying to get an explanation on ohm's law and how to use it your guidance has made me understand it much better
Glad to hear that. Thanks for your comment.
You are better teacher then my teacher
👍 easy to understand
Thanks for the vote of confidence. I love being a teacher.
I’m 23 now learning this, big help bro Thankyou !
Glad to hear it!
How do I start from the beginning of this series on electricity?
Here is the link to the playlist.
ua-cam.com/play/PLcJ1NYursFxiRnjN28UEf_18zaVO9ub2B.html
voltage= current(amps) x resistance(ohms)
so if I need a 6 ohm 12v led to work and I have a 20 volt input at 4 amps
so input would be 20 v/4 A= 5 ohms
led I used the amperage of the input to find out the resistance to run it 20v /6ohms = 3.333 amps needed? so I need to decrease the amperage to run the 12v 6 ohm led, because if I rework it 12v/6ohm requires 2 amps to run, so If I take the 20v / 2 amps = 10 ohms needed? Might be completely wrong
Thank you for making this instructional video!
You bet, happy to do so. Thanks for watching!
thank you so much I was about to fail ninth grade
You're welcome, you can do this!
thank you! have a science exam in a few days lol, i completely forgot about ohms law so here i turn! slight suggestion though is just mention when you rounded something off because i try to solve it first then compare our answers. i thought i was wrong lol
anyways, thanks!
You're welcome and thanks for the tips!
Thank you so much, you helping me with my physic class and MCAT prep
Happy to help! You're very welcome.
thanks a lot! i havent listened to the discussion of my teacher abd this helped understood
Glad that it helped out.
Thanks for the great explaining of the ohms law.
You're welcome, glad it was helpful.
I didn’t understand example 5 can you help me please? Why did you put 10-3 V?
Because the current is given in mA (milliamperes) and milli is 10 raised to the power of -3.
Very educative and helpful
Thanks, glad you think so!
thank you very muuchh this made answering modules easierrr!!
That's great. Glad it helped!
I need help with this question The seal of a patch clamp pipette is very important. The resistance of the seal determine how much leak current you will have. This leak current becomes noise when you want to record the current of single ion channels with the pipette. Assume you have an ion channel that allows a current of 2 pA to flow through the current. What is the minimum seal of the patch to half a signal-to-noise ratio of 2. Assume that the pipette is 5 mV depolarized with respect to the outside batch.
the answer is 10 GigaOhms but I need to know how that was solved
Thanks your questions were helpful to me🙏
I have my exam today
Glad it was helpful and I hope your exam went well!
Thank you,
I am seeking knowledge about ohms law in reference to audio amplifier and speakers.
I do not have videos for that.
I wanted to know about the problems which have to be solved with the formula of “ R = p .l/a
Thank you for the tips💚 EFFECTIVE
You're welcome, glad it was helpful
Very helpful Thanks mate
Glad it helped!
Well explained thank you, this will help me greatly
Glad to hear it!
What would happen if a wire having no resistance at all (0 Ω) were connected directly across the terminals of a 6-volt battery? How much current would result, according to Ohm’s Law?
There would be an infinite current and the wire would eventually melt
Nice to learn from you dude.
Glad to hear it!
Thank you so much 😊 Your a Life saver
You're so welcome!
amazing man, keep it up
Thanks, will do!
Very helpful !!
Glad to hear it, thanks!
Thank you for this video, it has been a huge help to me to understand solving ohm’s law problems!
Glad it was helpful! Thanks for the comment.
Does this really need to be round offed?btw ThanKs.
Thanks
I don't really gethow you get volts
Thank you for sharing your idea
My pleasure!
@@stepbystepscience its a big help for my studies💜 specially this online class
That lip smack in the beginning 😂😂😂😂
Thanks
Great video
Thanks, glad you liked it!
i finally learned something about ohms law cuz i dint listen in class cuz i just slept and a day later i got 15/15 😊👍
👍 Great.
Lets hope you find a good video on English as well
@@alzeNL lol ye
Thank you sir for these amazing questions that u gave us for practice.
And I have enjoyed these questions when I solving them 🥰🥰👍👍 ;)
It's my pleasure and thanks for the comment.
@@stepbystepscience ✌👍👍
Thanks for this video
You're most welcome
Thank u man u have wisdom
Thanks and best wishes to you
How abt this formula? i=v÷r
That is correct, ohms law solved for current.
Fantastic - Thank you!
You are very welcome!
I am in grade 7 and you realy helped me bra thanks😀😁🙂😮🤓
Happy to help!
I like the way you explain thank you!
Thx for the the help
You bet, and thanks for watching!
You are amazinggggg❤️thank you so much
Thanks to you for the nice comment.
Thank you so much!i like it 👌😊
You're welcome 😊, glad you like it!
Thank you sooooo much 💖
You’re welcome, thanks for watching
Thank you , it was helpful :)
Glad it helped! Thanks for the comment.
Thank you!
You bet!
Just found your channel. I’m trying to build a 24V with 7S 18650 batteries.
Helpful 💖
Glad it was helpful!
good job reaching 100k
Thanks! 😃
Who come in this video because they can't understand the ohms law
Video is but standard of questions should increase for next time
Increase like how?
@@stepbystepscience increasing level of questions
Thanks man
You bet!
POV:your answering your school works and u don’t know how so you go here
Helloooo I need this so muchhhhh 😭
Hope it helps. Thanks for watching!
Thanks for this! I subscribe keep it uppp!
Will do. Thanks for watching!
Love dis video tanx a lot
3rd week 101 class here so sorry if dumb question. But 1st one is .35/750 comes out to 262.5..do we automatically round up to 263?
I you want to round to three significant figure then yes.
Thank you.....
You are very welcome!
You are amazing
Very nice of you to say so.
Thnxxxx bro
Thanks for tips
You are very welcome!
Thank you ❤❤❤❤❤
Welcome, my pleasure
Thank I learned from the video💬
Thank you sir 👍👍👍
Very nice
Thanks
tnx for this video I have a knowledge like wise...
Great and thanks for the comment.
Sir 2 nd answer of question is R=18.4 ohm
Thnq ♥️
Hi from PHY-252 :D
Shantanu Hello from Berlin, Germany, where is PHY-252?
@@stepbystepscience I am in College in Boston, US. My professor us asked to see this video! The name of my class is PHY-252
Great, tell your professor I said hello and thank you.
i took electronics in school years ago and dont ouite remember but i have a battery charger that puts out 24 volts and i want to drop the voltage down to 6 volts, so i decided to use ohms lawso that would mean v/i =r v=24v/1000ma=the resisance
Genios
thanks
THIS YES
Thanks!
I'm a grade 12 student and I still suck in this🤦♀️
Keep trying, and I hope the videos help!
Hi buddy what's dood man
Please give heart ❤
i though current was magic
subscribe BTW.
Fantastic!
Niceeeeeeeee
Thank you!!
Sir 1st question answer is 262.5 Or any other
nice joke in remembering the formula😂
Thanks!
Repent and forsake sins Jesus is coming accept Jesus now
OK, thanks for the reminder.
Your language is not understanding please improve it😵😵😵
👎👎👎👎
Maybe you should learn to speak English before criticizing others.
Thank you s much! I'm in 8th grade and I'm having a hard time understanding my modules, an this helped me a lot!😊
That's great to hear. Glad it was helpful!
I'm grade 7
@@koro3259 same, that you so much for helping me understand