Operations on Regular Languages

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  • Опубліковано 16 жов 2024
  • TOC: Operations on Regular Languages in Theory of Computation.
    Topics Discussed:
    1. Union operation on regular languages.
    2. Concatenation operation on regular languages.
    3. Star operation on regular languages.
    4. Theorems on Union and Concatenation.
    Full Course on TOC: goo.gl/f4CmJw
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    Music:
    Axol x Alex Skrindo - You [NCS Release]
    #TheoryOfComputation #TOCByNeso #RegularLanguages #AutomataTheory

КОМЕНТАРІ • 137

  • @starzone9843
    @starzone9843 5 років тому +211

    Sir, i am binge watching your videos.. i have already watched 14 of them, your way of explanation beats our professors. Keep it up 👍🏻👍🏻👍🏻👍🏻 big fan👍🏻

    • @marxman1010
      @marxman1010 3 роки тому +4

      Better than other automata online courses, surprisingly articulate.

    • @praviveekray1907
      @praviveekray1907 Рік тому

      ​@Radar123 to 🔥

    • @kartikforwork
      @kartikforwork Рік тому +2

      but this is 9th feku

    • @prashantpaliwal2286
      @prashantpaliwal2286 Рік тому +7

      Thanks man, along with automata i am also improving my grammar or vocab from comment section. Today I learned the word -
      binge-watching.

    • @captainstark5496
      @captainstark5496 7 місяців тому

      This teacher's professor is my professor

  • @Furious_footballs
    @Furious_footballs 7 місяців тому +8

    Surely I will donate some money that I could afford when I get my first month salary........Hats off for your sincere hard work and this is my first comment on UA-cam.

  • @shariquatkhan
    @shariquatkhan 7 років тому +85

    I wish you were my college automata teacher😍 Taught so well. Thank you☺

  • @ThePhlox99
    @ThePhlox99 5 років тому +100

    Theorem: The class of regular languages is closed under union and intersection. That
    is, if L1 and L2 are regular languages, the so are L1 ∪ L2 and L1 ∩ L2.
    Proof Lets start with the union. For simplicity, let us assume that L1 and L2
    are languages over the same alphabet Σ.
    Since L1 is regular, there exists a DFA
    M1 = (Q1, Σ, δ1, q1, F1) which recognizes L1.
    Similarly, there exists a DFA M2 =
    (Q2, Σ, δ2, q2, F2) which recognizes L2.
    To prove that L1∪L2 is regular, we will construct a DFA M∪ which recognizes L1∪L2 =
    {w|w ∈ L1 or w ∈ L2}.
    The idea: M∪ = (Q, Σ, δ, q0, F) simulates a parallel execution of M1 and M2. M∪ is
    defined as follows:
    - Q = Q1 × Q2;
    - Σ is the same;
    - δ((q1, q2), a) = (δ(q1, a), δ(q2, a));
    - q0 = (q1, q2);
    - F = {(r1, r2) | r1 ∈ F1 or r2 ∈ F2}
    To prove correctness we need to show that w ∈ L1 ∪ L2 if and only if M∪ accepts w.
    This, in turn, follows from the fact that (r0, r1, . . . , rn) is a computation of M1 on w, and
    (t0, t1, . . . , tn) is a computation of M2 on w, if and only if ((r0, t0),(r1, t1), . . . ,(rn, tn))
    is a computation of M∪ on w.

  • @yt_souvik
    @yt_souvik 2 роки тому +8

    I finished this lecture just now. Please upload those two theorem proofs in Another video, it will be helpful for us.

  • @MSneberger
    @MSneberger 5 років тому +22

    For proof that Regular Languages are closed under Union Operation see Theorem 1.25 on page 45 of Sipser's textbook. For proof that Regular Languages are closed under Concatenation Operation see Theorem 1.26 of Sipser's textbook on page 47.

    • @alan2211
      @alan2211 5 років тому +1

      Sipser no make sense.

  • @diptamanguha155
    @diptamanguha155 7 років тому +8

    Sir..your videos are great.These helped me a lot.Will it be possible for you to upload videos on C programming,data structures and algorithm?

  • @kasozivincent107
    @kasozivincent107 4 роки тому +7

    Hello. I think u messed up the Kleene star operation. It is not just a concatenation of all elements of A. It contains strings of 0 lengths, 1, 2, and so on. So I guess they should even be separated by commas. I suggest it would be better to use union notation. A mathematical definition would suffix for this, if L = {a,b}, L* = {@, a, b, aa, ab, ba, bb, aaa, ...} not just a concatenation of symbols from the alphabet that L is defined. {bbabababbabaabababa} for example is just an element of L*

  • @gedelasivakrishna
    @gedelasivakrishna 3 дні тому +1

    Thankyou !!

  • @flovous
    @flovous 2 роки тому +1

    Thank you for the content, as always. Very easy to follow and understand

  • @adiyc2909
    @adiyc2909 4 роки тому +3

    Thank you ,sir . Very easily understandable . But can you please provide the proofs of the theorems also ?

  • @ktwsahil7445
    @ktwsahil7445 Місяць тому +1

    Thank you so much sir

  • @venkatasatyatejakapuganty
    @venkatasatyatejakapuganty 8 місяців тому +1

    please upload a video on proofs of the theorms at last

  • @jaiashutosh2181
    @jaiashutosh2181 7 місяців тому +1

    for union purpose dont you think we should mention and like x belongs to a and x belongs to b. please correct me if i am wrong.

  • @AnonymousDeveloper1
    @AnonymousDeveloper1 7 років тому +18

    Hello, question not specific to current subject but I must ask you:
    Will you record data structures and algorithms tutorial series in the future?

    • @AnonymousDeveloper1
      @AnonymousDeveloper1 7 років тому +5

      Wow, nice! I would like to see this series because you are great.

    • @shivamdubey7599
      @shivamdubey7599 7 років тому +3

      Please bring up the algorithm part as quick as you can. It would be very kind of you.

    • @Aba9846
      @Aba9846 6 років тому +1

      Awesome! Where can we find these videos?

  • @fnaticbwipo1222
    @fnaticbwipo1222 Рік тому

    for proof of the following theorems I will use the fact that regular languages are those that can be described by regular expression, let's say we have 2 regular languages A and B, and their regex be p and q, then concatenation of those languages can be described by pq (first part will describe string from A and second part string from B), as for union we can use | operator for regular expressions and describe language by (p | q) since union contains strings that are present in both languages.

  • @alitcher4425
    @alitcher4425 Рік тому +1

    Id like proofs of those 2 theorems please. Thank you for this video as well sir!!!

  • @fcreany9147
    @fcreany9147 4 роки тому +3

    Should the AUB and A•B included the Epsilon ?
    Such that
    AUB ={ε,pq ,r,t,uv}
    A•B={pqt,pquv,rt,ruv, ε,pq(=pqε) ,r,u,t}

    • @NSHAIKAMEENA
      @NSHAIKAMEENA 4 роки тому

      No

    • @hygieia5672
      @hygieia5672 Рік тому

      For anyone wondering about this in the future, and to be more helpful than just "No", only A* can contain epsilon because in the definition it says there are k elements of A where k can be any positive number including zero. k being zero is how you get epsilon aka no elements at all.

  • @roshannalawade7389
    @roshannalawade7389 7 років тому +58

    sir give me the proof of this

  • @tharunkumar8430
    @tharunkumar8430 Рік тому +1

    Your videos pretty great SIR ..😃
    Guy's do follow this channel is very useful to gain knowledge easily...
    👍👍

  • @Kshirabdi.Tanaya
    @Kshirabdi.Tanaya Рік тому +1

    Sir please make a video on theorems.🙏🏻

  • @mercyoroc8721
    @mercyoroc8721 2 роки тому +1

    Thank you so much to explaining us 😍😍

  • @notsphinxz
    @notsphinxz 2 роки тому

    Thank you Neso Academy I watched some of FSM videos are very Interesting and Entertain to Learn for my Computer Science Career! Cheers UP

  • @ankitjain2398
    @ankitjain2398 6 років тому +3

    Sir please record videos on Computer Networks of CS branch

  • @dillipkumarsahoo5017
    @dillipkumarsahoo5017 2 роки тому

    Sir please make a video of proving the
    all theorems of regular languages

  • @technicalinfochannel66
    @technicalinfochannel66 5 років тому +2

    dear sir kindly explain the theorem of class of regular language is closed under the "kalena" star operation

    • @aydict
      @aydict 4 роки тому

      kleene*

  • @shivrajkhose7875
    @shivrajkhose7875 7 років тому +1

    please upload videos of turing machine,recursive and recursively enumerable language

  • @omkarmarbhal
    @omkarmarbhal 7 років тому +4

    Best Tuts Ever........!!!!

  • @pushplataraina51
    @pushplataraina51 7 років тому +10

    hi sir,
    i want
    proof of theorems

  • @rohitpandey4
    @rohitpandey4 3 роки тому

    Sure sir can you make a video for Proof of Theorem1 and Theorem2

  • @jsbbatth8667
    @jsbbatth8667 3 роки тому

    Please make a video on proof of the theorems

  • @jeetdas4799
    @jeetdas4799 6 років тому +1

    Helps me alot....tnk u sir ji

  • @sasswithdivyanshi
    @sasswithdivyanshi 4 роки тому +3

    This is so well explained ❤️❤️❤️❤️❤️❤️❤️

  • @Ana-el3gk
    @Ana-el3gk 4 роки тому +1

    Amazing! thank you

  • @trywellwashington7506
    @trywellwashington7506 4 роки тому +1

    concatenation: cartesian prod, order of elements in pair immaterial

  • @akshunkc6884
    @akshunkc6884 7 років тому +4

    hi sir nice TOC series...plz also upload profs of these theorems...?
    thanks in advance...

  • @devmahad
    @devmahad Рік тому

    Union, Concatenation & star.

  • @saidurgaprasad5172
    @saidurgaprasad5172 2 роки тому

    Thanks you sir

  • @anirudhyasarkhel8247
    @anirudhyasarkhel8247 6 років тому +4

    Sir please provide proof for those 2 theorems, imp for exam

  • @sourjadhar9332
    @sourjadhar9332 2 роки тому +1

    The star one is also called kleen closure .

  • @sathirajumadhavarapu3065
    @sathirajumadhavarapu3065 5 років тому +2

    sir, could you please explain proof of two theorems

  • @satwikyalamarthi1162
    @satwikyalamarthi1162 7 років тому +15

    We want proof...... Can you please explain

  • @adhishagammanpila
    @adhishagammanpila 6 років тому

    Really appreciate if you could do the proof too

  • @Montserratx
    @Montserratx 4 роки тому

    Can you explain to me this example, please?
    A*={a*,b*,a*,b*}

  • @chandanpatra3850
    @chandanpatra3850 7 років тому +1

    sir can I use this answer for closure properties of regular sets.

  • @uditisinha357
    @uditisinha357 Рік тому

    what is the significance of putting k => 0 for A*?

  • @apporvaarya
    @apporvaarya 5 років тому

    nice concept

  • @dhanushsivajaya1356
    @dhanushsivajaya1356 3 роки тому

    Thankyou sir

  • @richierabbit2733
    @richierabbit2733 7 років тому +1

    please please make vedios on data structures

  • @muhammadashfaq8032
    @muhammadashfaq8032 2 роки тому +1

    Love from muzaffer garh Pakistan

  • @Ankit-we8ym
    @Ankit-we8ym 7 років тому +2

    dear sir are you also teaching any other subjects for cse students

  • @risingsingh3424
    @risingsingh3424 5 років тому +1

    How to visualise practically the concept of regular languages

  • @AhamedKabeer-wn1jb
    @AhamedKabeer-wn1jb 4 роки тому

    THANK YOU..

  • @saptarshiroy3943
    @saptarshiroy3943 2 роки тому

    Sir, can you provide the proof of Regular language expression?

  • @kishankanabar6620
    @kishankanabar6620 6 років тому

    sir i can find one ambiguity over here.When you are declaring definition of star,i.e. A*={x1x2x3...xk:k>=0 and all xi belongs to A}.So when k=0,what would be the concatenating string?and if you are saying it is a null string then again ambiguity arise because as you said all xi,including x0 should belong to A,but that is not in the actual case.Please make it clear.

    • @vivekkumar-xc8vq
      @vivekkumar-xc8vq 6 років тому

      Kishan Kanabar Hey... Are you not aware of the fact that all sets have a null element i.e. null element belongs to each and every set....

  • @ronikseth6742
    @ronikseth6742 6 років тому

    sir i want regular language's many types of problem with solution for better understand.thank you.

  • @knvssandeepbolisetti5008
    @knvssandeepbolisetti5008 6 років тому +3

    Sir pls give the proof for theorems

  • @ashisraha9263
    @ashisraha9263 2 роки тому

    Sir I need proves of two theorem of regular languages. If you send me then I will be thankful to you.

  • @imhsk1037
    @imhsk1037 5 років тому

    pls clarify our doubts

  • @RNCSSakshamBhatia
    @RNCSSakshamBhatia 2 роки тому

    If possible please give the proof of theorems.

  • @moazzamali5995
    @moazzamali5995 4 роки тому

    Sir plz..show some prove. Of this theorem

  • @-kurdush
    @-kurdush 4 роки тому

    plz.. explain proofs of those theorems

  • @akshaykhachi8565
    @akshaykhachi8565 4 роки тому

    If L={ab, c}...what will be L^3....??

  • @ishmitabasu9623
    @ishmitabasu9623 6 років тому

    Can i please get a proof of the two theoram?

  • @teenanandwani8823
    @teenanandwani8823 5 років тому

    Sir please explain Kleen's theorem...

  • @saraswatibepari8233
    @saraswatibepari8233 3 роки тому

    Sir , give us the prove of this 2 theorem ... please

  • @Uttamkeshri726
    @Uttamkeshri726 3 роки тому

    In A* prq also be there

  • @durgarajeswaritalluri4124
    @durgarajeswaritalluri4124 5 років тому +1

    sir will pqpqr is also in A* ??

  • @fizzsfizz7617
    @fizzsfizz7617 6 років тому

    Video was awesome but You should provide proof to complete topic

  • @dulldelusion
    @dulldelusion Рік тому +1

    Sir predicted "RRR" Film before it was a thing...

  • @nebiyumesfin9620
    @nebiyumesfin9620 4 роки тому

    Set of regular languages over a given alphabet is not closed under
    a) union b) complementation
    c) intersection d) none of the above

  • @thirumenipharma2612
    @thirumenipharma2612 2 роки тому

    what about (A+B)*

  • @VikashSingh-sq2yy
    @VikashSingh-sq2yy 3 роки тому

    Sir please give the proof of the theorem.

  • @barathkumarsr9890
    @barathkumarsr9890 3 роки тому

    Please prove the theorem 1& 2 sir

  • @sambhavjain9382
    @sambhavjain9382 5 років тому

    can we have the proofs please?

  • @pedarayududola1672
    @pedarayududola1672 6 років тому

    what is regular language

  • @CyrusXIII
    @CyrusXIII 3 роки тому

    Thank you :)

    • @shankarreddy4674
      @shankarreddy4674 3 роки тому

      What is it mean every one commenting like this

  • @laxmiwodeyar3113
    @laxmiwodeyar3113 6 років тому

    Sir please do proo

  • @UniversalUnicorn
    @UniversalUnicorn 7 місяців тому

    5:35/5:57 : 🦭🦭

  • @continnum_radhe-radhe
    @continnum_radhe-radhe Рік тому +1

    ❤❤❤

  • @pranaysahariah6193
    @pranaysahariah6193 5 років тому

    Proof of the therom sir pls

  • @msm8416
    @msm8416 6 років тому

    Proof for Theorem 1,Theorem 2 plz

  • @shaganpreetkaur1397
    @shaganpreetkaur1397 7 років тому

    thermos of regular languages expain sir

  • @vlogsnepal9550
    @vlogsnepal9550 6 років тому

    sir proof please on union operation

  • @shinigamiryuk4183
    @shinigamiryuk4183 3 роки тому

    my teacher plays your videos in lectures

  • @naveenraju3540
    @naveenraju3540 3 роки тому

    sir proofs please

  • @bhishmapitamah3681
    @bhishmapitamah3681 3 роки тому

    5:52 your device is fine

  • @SanjeevKumar-td4bj
    @SanjeevKumar-td4bj 6 років тому

    sir please upload proof of this video

  • @neiljohn2637
    @neiljohn2637 3 роки тому

    Level 9 reached @!

  • @vishalsaxena4869
    @vishalsaxena4869 7 років тому +4

    need proof

  • @saideep9808
    @saideep9808 4 роки тому

    sir we want proof

  • @khushiahuja82
    @khushiahuja82 5 місяців тому

    sir bta do proof!!!!

  • @swadheenta.957VBTS
    @swadheenta.957VBTS 2 місяці тому

    💜💜

  • @15tefera
    @15tefera 6 років тому

    Sir, I want bob please

  • @sanathramesh7254
    @sanathramesh7254 6 років тому

    Proof please

  • @sudiptacoachingcentre4118
    @sudiptacoachingcentre4118 2 роки тому

    Want the proof

  • @addagallanaresh4044
    @addagallanaresh4044 Рік тому

    Want proof

  • @DnyaneshwarPanchaldsp
    @DnyaneshwarPanchaldsp 4 роки тому

    💐💐💐💐👌

  • @USBEN.
    @USBEN. 5 років тому +1

    Theorm : Stating the obvious facts with fancy english .

  • @dqfans3364
    @dqfans3364 9 днів тому

    prooof