3. Binary Division method (Restoring and Non-restoring Division Algorithm)

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  • Опубліковано 9 лис 2024

КОМЕНТАРІ • 177

  • @marvichadap8338
    @marvichadap8338 2 роки тому +27

    Thank you so much mister, my teacher taught this and i didnt understand anything. Its because of people like you that makes things easier and as a fellow indian, i would like to wish you success and hope the world recognises your talent someday.

  • @srushti1258
    @srushti1258 5 років тому +85

    Honestly you are the ones who should be honoured in ytff. We get to learn what we really need to!!
    Thanks a lot!🙏🏻

  • @aryaone8
    @aryaone8 25 днів тому +2

    I was just looking for 3:50. Thank you so much; my doubt has now been cleared.

  • @rafaelangelopiad8919
    @rafaelangelopiad8919 3 роки тому +55

    bro no words can express how helpful this is, thank you bro

    • @simonriley8696
      @simonriley8696 3 роки тому +7

      You just described it with words.

    • @rafaelangelopiad8919
      @rafaelangelopiad8919 3 роки тому +3

      @@simonriley8696 HAHAHAHAHAHAHAHAHAHAHAHA OH YEAH

    • @adarsh2004
      @adarsh2004 11 місяців тому

      hahahahahahahahahhahahahahahahahahahahahahahahahah oh yeah@@rafaelangelopiad8919

  • @HGCS_ASHWINIMD
    @HGCS_ASHWINIMD 3 роки тому +6

    Excellent teaching sir....it's very easy to understand everyone... Becz of... u teaching the way is very simplest..it's too much good sir..tqsm

  • @pranavchauhan3549
    @pranavchauhan3549 3 роки тому +4

    Very much needed bro...i cannot found this method anywhere on internet...🤘

  • @sakshirajput8828
    @sakshirajput8828 5 років тому +212

    Wht abt non restoring method.. If it was nt to be taught in this video then why the name is included..??

  • @manishswami7512
    @manishswami7512 3 роки тому +8

    For anyone wondering it is 10 / 3 instead of 9 / 3

  • @aditichatterjee3353
    @aditichatterjee3353 4 роки тому +7

    Thanks a lot bhaiyya!!!... I wasn't able to solve these questions earlier, this tutorial has clarified all my doubts on the topic, thank you😊

  • @MasterMindmars
    @MasterMindmars 4 роки тому +10

    P E R F E C T
    Amazing method to divide with a simple algorithm and resulting directly the quotient and the rest.
    Thank you

  • @saravanann9709
    @saravanann9709 Рік тому +2

    Thank you very much sir ... tomorrow i have exam...i understood clearly thanks a lot 🎉

  • @nikhilgiripunje2663
    @nikhilgiripunje2663 Рік тому +6

    First i was a little bit confused but after watching his video I'm now more confused

  • @nishtha9666
    @nishtha9666 2 роки тому +4

    Very well explained 👍👍Please divide 67÷14 using division algorithm....

  • @_PremKharat
    @_PremKharat 2 роки тому +5

    I was searching for such simple explanation and finally came across the video
    Thank you sir🤩🤩🤩

  • @harshaneelam
    @harshaneelam Рік тому +1

    Good Explanation For Morning Exam

  • @arshadshaikh5482
    @arshadshaikh5482 Рік тому +3

    Very nice explanation sir ,next time please cover whole page☺️

  • @OldSloGuy
    @OldSloGuy Рік тому +2

    This algorithm is actually a special case. NOTE the sign bit of the divisor being zero in this example. The generalized division algorithm does not require this but generates TWO carry bits. Processors do not handle a second carry bit, but it can be emulated by implementing a flip-flop in software. Yes, that requires the use of a goto operation which is spaghetti code. When it comes to division, goto is not harmful. A benefit of this is an extra bit of precision which allows correct rounding when the unsigned quotient is restored to a signed integer. While that is simple in assembly language, it results in complicated logic in many high level languages. Unsigned scaled integer division is usually ignored for this reason. The reader should understand what is being avoided in this video and why the extra zero in the divisor is so important. Omit that and the algorithm will work most of the time, and depending on the inputs, may occur so infrequently as to avoid detection during testing. The generalized version is never used in life safety software because it is so poorly understood by most programmers. Just because you understand it doesn't mean someone in the future won't clean up the code because they don't comprehend the reason it exists.

  • @kishoreshetty7338
    @kishoreshetty7338 2 роки тому +4

    Thank you sir ,please provide a clearer image of the flow chart in the description it really helps us a lot!

  • @TheStudyShackbySanketManiyar
    @TheStudyShackbySanketManiyar 2 місяці тому +2

    Thank you so much! Much needed video

  • @itsoknottobeok9381
    @itsoknottobeok9381 Рік тому +5

    If video is about restoring algorithm then remove (Restoring and non restoring algorithm) the title!

  • @bssumanth5427
    @bssumanth5427 4 роки тому +2

    Thank you so much sir ur teaching way really awesome concept cleared

  • @vikhyaths1369
    @vikhyaths1369 6 років тому +6

    Thank you so much for clearing the concept✌️

  • @samsunighar8134
    @samsunighar8134 3 роки тому +1

    Hats off bro. Superb and good explanation

  • @Watchfuse
    @Watchfuse 6 місяців тому

    great explanation , keep it up.

  • @ShrishtiMishraA
    @ShrishtiMishraA 2 місяці тому +1

    why you not restored A in 3rd cyclce? ..pls reply

  • @rutujabalak9310
    @rutujabalak9310 6 років тому +5

    I like it and I also understand it .Thank you

  • @manofsteel6173
    @manofsteel6173 Рік тому +1

    Helpfull❤️

  • @---MDEEKSHA
    @---MDEEKSHA 3 роки тому +3

    Explained very well

  • @rakshitsingh9690
    @rakshitsingh9690 2 роки тому +1

    Thank you so much for this video

  • @157_anweshasahoo7
    @157_anweshasahoo7 2 роки тому +1

    Thank you so much sir for make this video

  • @devagabond6926
    @devagabond6926 4 роки тому +2

    complimenttt...

  • @maziarghorbani
    @maziarghorbani 6 років тому +3

    Thank you for the great explanation.

  • @unmeshmandal3071
    @unmeshmandal3071 2 роки тому +2

    If the numbers are represented in signed 2's complement method then how 1010 becomes decimal 10.

  • @icemans1matedude339
    @icemans1matedude339 11 місяців тому

    Im assuming that A always has one more digits place than Q to account for sign bit and 2’s complement

  • @adarsh2004
    @adarsh2004 11 місяців тому

    very nice

  • @Arjun-px3gx
    @Arjun-px3gx 4 роки тому +2

    Thanks for this informative video...I have only one suggestion:the flow chart is not visible while you were explaining the procedure of getting answer....other than that it is good.. thank you very much🤝👍

  • @sakshirajput8828
    @sakshirajput8828 5 років тому +1

    Btw it cleared concept regarding restoring method

  • @muskansao1317
    @muskansao1317 3 роки тому +1

    Got my doubts clear ty sir

  • @ujjwalsinha1237
    @ujjwalsinha1237 6 років тому +1

    How are you doing the count operation? I mean to say by referring which thing you did the count operation?

    • @ujjwalsinha1237
      @ujjwalsinha1237 6 років тому +2

      Is this operation based on the number of bits present in the dividend?? I think that's why you are counting 4 cycles for complete this process.🤔

    • @MrBabaaldar
      @MrBabaaldar  6 років тому

      @@ujjwalsinha1237 Yes You are right.

    • @starkendeavours7072
      @starkendeavours7072 2 роки тому +1

      @@ujjwalsinha1237 What if Dividend is a -ve integer? Will it Count 5 Cycles then?

    • @techvishnuyt
      @techvishnuyt Рік тому +3

      @@starkendeavours7072 if the dividend is a negative integer, we need to convert it to its two's complement representation and perform the algorithm as usual. The number of cycles required will be the same as for a positive dividend, but sign extension will be required at the end to obtain the correct sign for the quotient.

  • @deveeshn1192
    @deveeshn1192 Рік тому

    thank u for saving my life sir😘😘

  • @prakashbharati6707
    @prakashbharati6707 5 років тому +2

    thanks it helps me to understand in better way

  • @samanvithachidella2485
    @samanvithachidella2485 5 років тому +3

    Why u didnt restored in 3rd cycle and last cycle..???

    • @srushti1258
      @srushti1258 5 років тому

      Samanvitha Chidella Restoring A was not needed because we got a positive number(starting with zero).

    • @samanvithachidella2485
      @samanvithachidella2485 5 років тому +1

      Yes... I later understood.... But i have forget to delete that comment

  • @sowmyakarra9413
    @sowmyakarra9413 2 роки тому +1

    Thank you so much sir😊

  • @elvindsa6283
    @elvindsa6283 2 роки тому +1

    Perfect ❤️❣️

  • @techworld2052
    @techworld2052 3 роки тому

    Bro place your camera little bit up , we wre not able to see the lower part of block diagram clearly ..

  • @Menkamohbekar
    @Menkamohbekar 4 місяці тому

    Why we add agr hume subtract krna tha t??

  • @afrozr9191
    @afrozr9191 2 роки тому +1

    In last step 00001 remainder in my reader ?

  • @shushrutgahane6551
    @shushrutgahane6551 Рік тому +1

    Thanku so much

  • @Biswachintamani
    @Biswachintamani Рік тому

    Thanks Sir 🙏🏻

  • @arpitbhaliya2972
    @arpitbhaliya2972 3 місяці тому

    Thanks sir ❤

  • @vishnusandeep4548
    @vishnusandeep4548 2 роки тому +1

    Did'nt restore in 3rd cycle??

  • @logarathinam1782
    @logarathinam1782 6 років тому +3

    Is this possible only for the unsigned values?? Is there any method for signed??

    • @patryk_49
      @patryk_49 6 років тому +1

      If sings of the input values are not the same you negate the output value. Thats all.

    • @m0st4fabideer14
      @m0st4fabideer14 3 роки тому

      You save the signs of the operands before the operation to determine the sign of the quotient, and then set their most significant bits to 0 (so that it doesn't affect the actual division), after the division is finished, you set the sign of the quotient (XOR the MSbs of the operands), the sign of the remainder is the always the same as the sign of the dividend.

  • @LUCIFER-uv3dt
    @LUCIFER-uv3dt Рік тому

    Hats off

  • @SmokyBigSmoke
    @SmokyBigSmoke 5 років тому +3

    thank you so much sir...

  • @trinhcuong9188
    @trinhcuong9188 5 років тому +6

    I do not understand why does A have 5 bits whereas Q has only 4 bits. Could you explain it for me? Thank you so much!

  • @shivsuthar9759
    @shivsuthar9759 2 роки тому +1

    Respect++

  • @chanu2400
    @chanu2400 8 місяців тому

    Thank you sir!

  • @sailajapalukuru7493
    @sailajapalukuru7493 2 роки тому +1

    I like you sir

  • @cutecreatures167
    @cutecreatures167 6 років тому

    Super teaching

  • @itspurelypassionate
    @itspurelypassionate 3 роки тому +1

    Thanks!

  • @lunavathsainaik4443
    @lunavathsainaik4443 Рік тому

    Sir I have a dought at 4th cycle ,why should we stopped at 4th cycle !

  • @muslimwaqar
    @muslimwaqar 4 роки тому

    thanks bro good explanation

  • @swopnilmaharjan8630
    @swopnilmaharjan8630 Рік тому

    shouldn't the bit size of A = Q?

  • @fujoshiarmygrl8377
    @fujoshiarmygrl8377 2 роки тому +1

    Thank u 💓

  • @rudrasama297
    @rudrasama297 3 роки тому +1

    But reminder should be 00000 why we are getting 00001 ? According to Decimal system 3 is totally dividing 9 leaving reminder as 0.

  • @vinayjadhav3502
    @vinayjadhav3502 2 роки тому

    how to solve this if the dividend is negative?

  • @DarkWebCode
    @DarkWebCode 6 років тому +1

    Thank you so much bro

  • @tadepu-raghavendra
    @tadepu-raghavendra 4 роки тому +1

    In 3rd cycle why not restore pls explain

  • @AbhishekKumar-my8sp
    @AbhishekKumar-my8sp 9 місяців тому

    Thanks a lot!🙏🏻

  • @kamyagupta4030
    @kamyagupta4030 2 роки тому

    Thank you so much 🙏

  • @harling9835
    @harling9835 5 років тому

    How to convert the remainder to the fornat bbb.bbb where b is binary numbers?

  • @rx5194
    @rx5194 Рік тому +1

    But at last step counter value is 1 then there will another step know as it is not zero

  • @THE_WAY_FORWARD
    @THE_WAY_FORWARD 6 місяців тому

    Sir I have a question, when setiing Qo to 0, then after that why not doing A= A+M

  • @yugendharsai
    @yugendharsai 5 років тому

    Nice

  • @govindprajapati5524
    @govindprajapati5524 6 років тому +2

    thanks so much bhaiiiii

  • @betavenomlite6379
    @betavenomlite6379 3 роки тому +1

    Tq sir

  • @kaustubh1871
    @kaustubh1871 3 роки тому

    after we shift and subtract.... if we get a carry do we discard or keep it??

  • @natureisbeautiful4486
    @natureisbeautiful4486 3 роки тому +1

    tnx

  • @raj12030
    @raj12030 Рік тому +1

    If there is A-B why he does A+B? Someone explain

    • @xteez6051
      @xteez6051 6 місяців тому

      Because he found the 2s complement which is basically -B so A+(-B)

  • @maddyabdullah6340
    @maddyabdullah6340 5 років тому

    is it possible complete division in this question... -15 divide by +5 ??? please if u could solve it.. i did and in last i did set it but i had to restore because it was 0 remainder please help?

  • @vinayak186f3
    @vinayak186f3 3 роки тому +1

    Exam offline hota to pakka ye aata 5 marks me ab to mcq de rhe hai 😓

  • @omarma2617
    @omarma2617 5 років тому

    Thank you very much

  • @suhaspp8885
    @suhaspp8885 3 роки тому

    Can u do binary division for 273/15

  • @karanswamygowda
    @karanswamygowda 6 років тому +1

    Thank you sir

  • @shubhamaynandi6068
    @shubhamaynandi6068 8 місяців тому

    sir aapka video toh bas black lover students hi dekhte honge 😷

  • @trendyvedios07
    @trendyvedios07 8 місяців тому

    🙏❤️👍

  • @harshsha0562
    @harshsha0562 Рік тому +1

    Sir Hindi m hi Vdo bnaya kare thodi problem hoti hai samajne m😢😢

  • @3dy97
    @3dy97 6 років тому +1

    Thank you!

  • @sayantandas7054
    @sayantandas7054 5 років тому +1

    Y u haven't restore on 3rd cycle

  • @NCCSSandhyaN
    @NCCSSandhyaN 3 роки тому

    Sir can u help me for another example . Dividend=1010, divisor=0100 . Plzz

  • @TheBhadhu
    @TheBhadhu 6 років тому +1

    Thank you so much . Great video btw :)

  • @kunalsrivastav2913
    @kunalsrivastav2913 4 роки тому

    can somebody tell me how to identify if a given binary bit is +ve or -ve? i know what is sign bit, still how can i differentiate between any randomly given binary number and know?

    • @aditichatterjee3353
      @aditichatterjee3353 4 роки тому

      If the first bit of the said binary number is 1 it is a negative number, and if it's 0 then it's a positive number.

  • @laudarikailash9244
    @laudarikailash9244 6 років тому

    How to perform restoring and non restoring division for the following
    11/4
    17/8

    • @MrBabaaldar
      @MrBabaaldar  6 років тому +2

      Dividend =11 =1011= Q
      Divisor= 4=00100 =B

    • @laudarikailash9244
      @laudarikailash9244 6 років тому

      If u don't mine can u solve an send me no need to send algorithm only process

    • @MrBabaaldar
      @MrBabaaldar  6 років тому +4

      I m out of station...I will solve it as early as possible and send u.

  • @awarenessentertainment5252
    @awarenessentertainment5252 2 роки тому

    Good 👍😂👍😂👍😂👍😂👍😂👍😊😊👍

  • @BTS-in6xc
    @BTS-in6xc Рік тому

    Sir please Hindi ma video bano
    I know your English is very good

  • @shrutisamal
    @shrutisamal 6 років тому +2

    how to divide 9/9?

  • @shashankshankar4021
    @shashankshankar4021 6 років тому +1

    Thank you ;)

  • @ICONICCORNER-h8q
    @ICONICCORNER-h8q 6 років тому

    Thanku sir

  • @DwayneClinton-w3f
    @DwayneClinton-w3f Рік тому

    R.I.P Audio

  • @sandeepswami7156
    @sandeepswami7156 9 місяців тому

    Bhai subtraction bol ke addition kyu Kiya