A very subtle omission here is to also prove that points g,a and c and a, h,b respectively lie on the same line, according to proposition 1.14, anyway you did a great job :)
Thanks for watching. I hope the video was helpful. This one is arguably the most famous, but a bit difficult to prove using Euclid. Over 100 different proofs have been created around this theorem through the centuries since Euclid and many are much easier and simpler.
Since angles GAB and BAC are two right angles, GA is straight on to AC [I. 14], and GA is parallel to FB by construction. Then, BG and FBC are a parallelogram and a triangle between the same parallels. So BG is double FBC [I. 41].
If you learned the first 46 propositions this is very straightforward. Too many people try to skim through or skip over propositions then get confused when a proposition uses those propositions in the proof.
Don, You're Italian and I'm Danish. How could it ever work? Leondardo DA VINCI/SHIVA/SHIVA/LEONARDO DA VINCI.. Since when did that EVER matter, when it comes to brotherhood?
![Pythagoras Would Be Proud: High School Students' New Proof of the Pythagorean Theorem [TRIGONOMETRY]](/img/n.gif)
I missed the part where it makes sense
Thank you for this video! Really simplified things for me!
This is one of the most important theorem. Widely used. Great video.
Great channel! One of my classes is on Euclid’s elements and this really simplified things for me!
A very subtle omission here is to also prove that points g,a and c and a, h,b respectively lie on the same line, according to proposition 1.14, anyway you did a great job :)
Thank you for watching. I'm glad you enjoyed the video. I appreciate the correction. I will take a closer look at this soon.
you know it’s a hard prop when the video is almost 10 minutes 😭🙏
maya💀💀
Thanks for watching. I hope the video was helpful. This one is arguably the most famous, but a bit difficult to prove using Euclid. Over 100 different proofs have been created around this theorem through the centuries since Euclid and many are much easier and simpler.
Since angles GAB and BAC are two right angles, GA is straight on to AC [I. 14], and GA is parallel to FB by construction. Then, BG and FBC are a parallelogram and a triangle between the same parallels. So BG is double FBC [I. 41].
Thank you so much. If it weren’t for this I would be a failing student lol.
Thank you for the kind words. I'm glad to hear that the videos are helping.
Lord help me
If you learned the first 46 propositions this is very straightforward. Too many people try to skim through or skip over propositions then get confused when a proposition uses those propositions in the proof.
Why do you need to show the triangles are parallel?
big brain euclid
Thanks for watching
ha angle fba
Listen to all of the 47 codes during the presidential debate
666
@Infamous Grizzly 888
@@patricktan3723 999
101010
22
33
Don, You're Italian and I'm Danish. How could it ever work?
Leondardo DA VINCI/SHIVA/SHIVA/LEONARDO DA VINCI..
Since when did that EVER matter, when it comes to brotherhood?