This was a really enjoyable video, I've always been interested in this effect but not quite enough to dig into it. I think this pushed me to want to explore this concept a bit more. Thanks!
@@DrBenYelverton but nice job nonetheless! I would love if you try to answer a doubt I have :) What if someone from the northern hemisphere tries to watch some clouds or winds in the southern hemisphere? Will he find the winds turn to the right or the left?
@@aniketdhumal2692 The Coriolis force only depends on the angular velocity vector of the Earth and on the velocity vector of the clouds - not on the position of the observer. So, the clouds are always going to deflect towards their own left. This means that if the clouds are moving towards the equator, the deflection will be towards the observer's right, while if they're moving towards the South pole, the deflection will be towards the observer's left.
@@DrBenYelverton Again thanks for the reply. Oh okay that's clears stuff up!! I thought (like the example you gave) the observer is the person itself. Again thanks
In the second video of your channel, you were saying that, for a particle moving around a circle( which will have velocity, in tangential direction at each point), there should be a force towards the center acting on it( which in turn turns the velocity vector as it proceeds forward and makes the path circular ), aka centripetal force. Now, similar to the proportionality eqn you wrote in this video(F_cor ~ v x w), we can say that this centripetal force is also perpendicular to velocity, and it also will be perpendicular to angular velocity w. So, for centripetal force too, we can write Fc ~ V x w. Would that be fine ?
oh yes! if Fc = mv^2/r, we could also write it as Fc = m * v * v/r. but v/r is w, so Fc = m * v * w, or Fc ~ v * w, and since v and w are perpendicular, V x w = V * w. So, everything is fine, thank you ... !!
Good question! The moving object in the video is in fact experiencing both the centrifugal and Coriolis forces in the rotating frame - I didn’t mention this as I wanted to focus qualitatively on the effect of the Coriolis force and keep things intuitive. The centrifugal force always points radially outwards, but the Coriolis force will in general have both radial and tangential components (since it’s always perpendicular to the velocity, which changes direction over time). I think what’s happening here is that the inward radial component of the Coriolis force is balancing the centrifugal force, so that the radial distance increases at a constant rate, and the spiral shape of the trajectory is due to the tangential component of the Coriolis force. I haven’t worked through all the maths but maybe it would be worth going through the process of solving the equation of motion in the rotating frame, showing that the expected trajectory is reproduced only if both fictitious forces are taken into account.
@@AK56fire We can prove it as follows: since it’s moving at a constant speed, the object’s radius is given by r = vt, where v is speed and t is time. Then, since the observer is moving at a constant angular speed ω, the angle θ from the line of sight is given by θ = ωt. Thus, r = v*θ/ω, i.e. the trajectory is r = (v/ω) θ and r is proportional to θ.
Thanks. Yes, absolutely - I used matplotlib to make the thumbnail but the focus of the video is on the Physics. Maybe in the future I can do another video showing how I made the figure, if there's enough interest.
I was searching for a good video explaining this force step by step, being precise and simple at the same time. Thanks indeed.
I'm glad it helped - thanks for watching.
Yu actually explained intuitively even without using animation
Happy to hear that it was intuitive!
This was a really enjoyable video, I've always been interested in this effect but not quite enough to dig into it. I think this pushed me to want to explore this concept a bit more. Thanks!
Good to hear! Hope you enjoy your exploration of fictitious forces.
Well explained.. Keep bringing such good explanations..
Thanks!
Good job dude!!
Just a suggestion: try using the cursor to show stuff you are saying simultaneously
Thanks! That's a fair point, I do try to do this but probably forget sometimes.
@@DrBenYelverton but nice job nonetheless! I would love if you try to answer a doubt I have :)
What if someone from the northern hemisphere tries to watch some clouds or winds in the southern hemisphere?
Will he find the winds turn to the right or the left?
@@aniketdhumal2692 The Coriolis force only depends on the angular velocity vector of the Earth and on the velocity vector of the clouds - not on the position of the observer. So, the clouds are always going to deflect towards their own left. This means that if the clouds are moving towards the equator, the deflection will be towards the observer's right, while if they're moving towards the South pole, the deflection will be towards the observer's left.
@@DrBenYelverton Again thanks for the reply. Oh okay that's clears stuff up!! I thought (like the example you gave) the observer is the person itself. Again thanks
In the second video of your channel, you were saying that, for a particle moving around a circle( which will have velocity, in tangential direction at each point), there should be a force towards the center acting on it( which in turn turns the velocity vector as it proceeds forward and makes the path circular ), aka centripetal force. Now, similar to the proportionality eqn you wrote in this video(F_cor ~ v x w), we can say that this centripetal force is also perpendicular to velocity, and it also will be perpendicular to angular velocity w. So, for centripetal force too, we can write Fc ~ V x w. Would that be fine ?
oh yes! if Fc = mv^2/r, we could also write it as Fc = m * v * v/r. but v/r is w, so Fc = m * v * w, or Fc ~ v * w, and since v and w are perpendicular, V x w = V * w. So, everything is fine, thank you ... !!
By the way, here you only showed the effect of coriolis force, right? What if we consider both centripetal and coriolis force together?
Good question! The moving object in the video is in fact experiencing both the centrifugal and Coriolis forces in the rotating frame - I didn’t mention this as I wanted to focus qualitatively on the effect of the Coriolis force and keep things intuitive. The centrifugal force always points radially outwards, but the Coriolis force will in general have both radial and tangential components (since it’s always perpendicular to the velocity, which changes direction over time). I think what’s happening here is that the inward radial component of the Coriolis force is balancing the centrifugal force, so that the radial distance increases at a constant rate, and the spiral shape of the trajectory is due to the tangential component of the Coriolis force. I haven’t worked through all the maths but maybe it would be worth going through the process of solving the equation of motion in the rotating frame, showing that the expected trajectory is reproduced only if both fictitious forces are taken into account.
What is the curve traced out by the moving particle in non-inertial frame. Is it a logarithmic spiral..?
The radius and the angle from the line of sight are both increasing linearly with time, so it's actually an Archimedean spiral.
@@DrBenYelverton Can you kindly give reference from where I may study about how this trajectory is proved to be an archimedian spiral ?
@@AK56fire We can prove it as follows: since it’s moving at a constant speed, the object’s radius is given by r = vt, where v is speed and t is time. Then, since the observer is moving at a constant angular speed ω, the angle θ from the line of sight is given by θ = ωt. Thus, r = v*θ/ω, i.e. the trajectory is r = (v/ω) θ and r is proportional to θ.
@@DrBenYelverton Thank you.. Appreciate it very much.
If a ball is spinning with table which is connected with string,if string is cut how ball will move with respect to observer in rotating frame?
Did you ever do things for Issac physics, your voice sounds familiar.
Interesting - no, I've never done anything for Isaac Physics!
good explanation - but not much of matplotlib action to see here, or?
Thanks. Yes, absolutely - I used matplotlib to make the thumbnail but the focus of the video is on the Physics. Maybe in the future I can do another video showing how I made the figure, if there's enough interest.