2 is the magnitude...... Positions depend on phase angle... First of all look at the phase angle... Graph going to start from - 180 degree phase angle.. And its magnitude is 2
sir which angle is greater -100 or -185 degree? in an polar plot, one point is -100 and other point is -185 . Which is greater than -180? Angles are rotating anti clock wise in polar plot. so all angles are minus.
In complex numbers, why do we add 180 degrees to our answer in angle theta=arctan (b/a)? I have seen 2 problems that the first, it didn't add 180 degrees while in the second prob you need to. How will you know when to add and when to not add? It depends on the quadrant the numbers a and b are in and it depends if you want the result to be in the range 0-360 degrees or -180 to +180 degrees. If a >= 0 and b >= 0 you are in first quadrant and you do not add 180 degrees. The result should be in the range 0-90 degrees. if a < 0 and b >= 0 you are in second quadrant and you want a result in the 90-180 degrees range and unless your arctan gives you a result in that range you should add 180 degrees. Specifically if the result from arctan is negative you add 180 degrees. if a < 0 and b < 0 you are in third quadrant and you either want the range to be 180-270 or -180 to -90 range and you add or subtract 180 degrees to get in the desired range. if a >= 0 and b < 0 you are in fourth quadrant and you either want the range to be 270-360 or -90 to 0 range and you should add or subtract 180 degrees to get in that range. The point is that tan(angle) = tan(angle + 180) so you can add and subtract 180 degrees to get the same tangent but depending on which quadrant the point a,b is in that might be the wrong angle. For example if both a and b are negative you do b / a and negative divided by negative gives a positive result which returns an angle in the first quadrant in the 0-90 range but your a and b isn’t there but in the exact opposite angle in the third quadrant.
In complex numbers, why do we add 180 degrees to our answer in angle theta=arctan (b/a)? I have seen 2 problems that the first, it didn't add 180 degrees while in the second prob you need to. How will you know when to add and when to not add? It depends on the quadrant the numbers a and b are in and it depends if you want the result to be in the range 0-360 degrees or -180 to +180 degrees. If a >= 0 and b >= 0 you are in first quadrant and you do not add 180 degrees. The result should be in the range 0-90 degrees. if a < 0 and b >= 0 you are in second quadrant and you want a result in the 90-180 degrees range and unless your arctan gives you a result in that range you should add 180 degrees. Specifically if the result from arctan is negative you add 180 degrees. if a < 0 and b < 0 you are in third quadrant and you either want the range to be 180-270 or -180 to -90 range and you add or subtract 180 degrees to get in the desired range. if a >= 0 and b < 0 you are in fourth quadrant and you either want the range to be 270-360 or -90 to 0 range and you should add or subtract 180 degrees to get in that range. The point is that tan(angle) = tan(angle + 180) so you can add and subtract 180 degrees to get the same tangent but depending on which quadrant the point a,b is in that might be the wrong angle. For example if both a and b are negative you do b / a and negative divided by negative gives a positive result which returns an angle in the first quadrant in the 0-90 range but your a and b isn’t there but in the exact opposite angle in the third quadrant.
5 hours b4 exam Bro. ...TYSM
All the best for your exams 🤗
Us
8 hrs lol
@@nobinkb367 1 hour
Did it work
I have suggested u r UA-cam channel to all my friends.. TQ so muchhhh.and we r thankful to u bhayyaa
Thank you😁
thanks for this! my prof is not good at explaining and i have been going at it for a while! this vid helps so much!
L
(-1 + s ) is not in (1 + sT) form. It is -1( 1 + s(-1)), here T = -1.
Yh
Watching 1hr before exam😂
same
sir in phase angle your not taken the 2 value ......?
yes
Very nice explanation , relevant and to the point 👌👍
Omaga equal to zero to infinity. We got 2magnitude and phase angle-180.why you plotted graph left side it would be in right side time10:45
If Phase angle - 180 means on left side......
Look at the angle graph... - 180 is on left side of the graph...
But 2is on right hand side
2 is the magnitude...... Positions depend on phase angle...
First of all look at the phase angle... Graph going to start from - 180 degree phase angle.. And its magnitude is 2
@@smartEngineerShinton here we need to consider phase Angles frist is that what you are saying?
sir which angle is greater -100 or -185 degree? in an polar plot, one point is -100 and other point is -185 . Which is greater than -180? Angles are rotating anti clock wise in polar plot. so all angles are minus.
185 i greater than 100 only difference is it is anti clockwise direction
Excellent explanation, thank you!
Nice way of explaining 👍👍👍👍
good mehandi arts in videos😎😎
Sir can you plz improve the sound quality and re upload
Thank you this video is very useful
It helped me a lot bro, tysm
Share to your class group 🤗
tan^-1(-x) is -tan^-1x and if we take that we cant draw the graph can u tell how to draw
In complex numbers, why do we add 180 degrees to our answer in angle theta=arctan (b/a)? I have seen 2 problems that the first, it didn't add 180 degrees while in the second prob you need to. How will you know when to add and when to not add?
It depends on the quadrant the numbers a and b are in and it depends if you want the result to be in the range 0-360 degrees or -180 to +180 degrees.
If a >= 0 and b >= 0 you are in first quadrant and you do not add 180 degrees. The result should be in the range 0-90 degrees.
if a < 0 and b >= 0 you are in second quadrant and you want a result in the 90-180 degrees range and unless your arctan gives you a result in that range you should add 180 degrees. Specifically if the result from arctan is negative you add 180 degrees.
if a < 0 and b < 0 you are in third quadrant and you either want the range to be 180-270 or -180 to -90 range and you add or subtract 180 degrees to get in the desired range.
if a >= 0 and b < 0 you are in fourth quadrant and you either want the range to be 270-360 or -90 to 0 range and you should add or subtract 180 degrees to get in that range.
The point is that tan(angle) = tan(angle + 180) so you can add and subtract 180 degrees to get the same tangent but depending on which quadrant the point a,b is in that might be the wrong angle. For example if both a and b are negative you do b / a and negative divided by negative gives a positive result which returns an angle in the first quadrant in the 0-90 range but your a and b isn’t there but in the exact opposite angle in the third quadrant.
15 min before exam thanks a lot
One hour before exam bro 😂
Sir you have notes of control system then snd me the link of notes.
Love dada love 😭❤️one night before exam, chandan chinal 😭❤️
why did you replace that with 180
sorry i am a slow learner
sir in phase angel in -180 - 2tan inverse (0.5w) ,but your not taking 2 ,video (8:56)
Please make your explain your thoughts clearly and bit slow please
Tan inverse-x is -tan inverse x
In complex numbers, why do we add 180 degrees to our answer in angle theta=arctan (b/a)? I have seen 2 problems that the first, it didn't add 180 degrees while in the second prob you need to. How will you know when to add and when to not add?
It depends on the quadrant the numbers a and b are in and it depends if you want the result to be in the range 0-360 degrees or -180 to +180 degrees.
If a >= 0 and b >= 0 you are in first quadrant and you do not add 180 degrees. The result should be in the range 0-90 degrees.
if a < 0 and b >= 0 you are in second quadrant and you want a result in the 90-180 degrees range and unless your arctan gives you a result in that range you should add 180 degrees. Specifically if the result from arctan is negative you add 180 degrees.
if a < 0 and b < 0 you are in third quadrant and you either want the range to be 180-270 or -180 to -90 range and you add or subtract 180 degrees to get in the desired range.
if a >= 0 and b < 0 you are in fourth quadrant and you either want the range to be 270-360 or -90 to 0 range and you should add or subtract 180 degrees to get in that range.
The point is that tan(angle) = tan(angle + 180) so you can add and subtract 180 degrees to get the same tangent but depending on which quadrant the point a,b is in that might be the wrong angle. For example if both a and b are negative you do b / a and negative divided by negative gives a positive result which returns an angle in the first quadrant in the 0-90 range but your a and b isn’t there but in the exact opposite angle in the third quadrant.
@@yogeshkumar7931 thanks, i was searching for this explanation
Watch right before my exam if I pass in CS i owes u a thanks 🤞
Super explanation sir ❤
tan inverse why taken 7:51
Can u plz explain reduction technique method
Video will be there in the playlist
Control System: ua-cam.com/play/PLzzmKH7SOicES_kXBGIARAPoR12nkbMDb.html
@@smartEngineerShinton tqq sir
In phase angle u didn't write 2 ? Explain..in question it there
Please mention the time in video
At 7:44 phase angle
If there is any S term or jw term you need to take angle. 2 is a constant
@@smartEngineerShinton in some textbooks they stated z as a zeros of a closed loop sysytem
bro from your accent I think ur South Indian , by the way I am too a South Indian ...
Yes i am an INDIAN 🇮🇳
@@smartEngineerShinton South Indian?
why is tan inverse of -w equal to 180-tan inverse of w
Why we did take 2in angle of omega
Which part you have doubt, tell me the time in video
Thanks bro
Thank you!!
Answer is not same with EC Academy channel , same question .Now IDK which one is correct😂
Bro u found which one is correct? I have exams tommorow 😂
While finding phase angle why we didn't we take -90-tan-1(0.5w) as we did in polar plot
There in no single s in denominator i mean if it is 1/s(s+1) we can take -90-tan^-1(w)
@@ALL-wo8qt ohkk...thnqqq😀
@@bhagyashreesahoo9023 it's oka😊
whats ur ##?
@3:40 you have mentioned wrong directions
This system is unstable bcz we have one pole and last answer was about zeros , pls explain ?
Why there is not break point
In this problem the w= infinity the value will be 1
i thought that too
thanks
THANK YOU SIR
Welcome 🤗
Thomas Ruth Clark Sarah Jones James
Ur teaching is very fast apart from that way explanation is nice but teach slowly
👍
How can take starting 's plane graph
Sir
You should explain it in hindi
why is tan inverse of -w equal to 180+ tan inverse of w
same question here