I did not get the "re-label where we call zero" part. It looked like you made Hbar = 0, but then you took the square root of it n the slope term, making it result in -a/4A. It looks mathematically inconsistent, to consider Hbar to be zero only at one part. Could you explain? (Or someone that got this)
(Answering 1 year after, but I hope it helps someone) Yes, looks inconsistent, but you can interpret it as: You re-label what you consider zero in another variable, an auxiliary variable, not exactly the same as considering Hbar = 0. The operating point is still at the original H = 4, a point where there's no discontinuity. The value of the slope is calculated at H = 4 and fixed (The slope is still -a/4A). Only then you re-label it. But I agree with you that maybe another variable should be used, an auxiliary variable, to represent this re-labelling.
Hello. Thanks for interesting video. Can you give more detail process about step: x-xbar->x in state space equation and how simulink model and controller connect with it will look like. Thanks you so much.
Hello Brian! in the final equation you have gotten and when I tried to substitute in value of the operating point(H_bar, V_bar), does the left side (H_dot) has to equal to zero? I tired to substitute but I have gotten nonzero value, why?
Every time he says tech talk i hear "TED talk", thanks Brian.
Hello Brian. Very well taught. Thanks a million times.
great video, really helped me out
Two of the links link to AEM pages within MathWorks. Please edit those. Thanks
Samvith V Rao I asked Mathworks to update the links (I don’t post these so I can’t do it myself). Thanks for pointing it out!
Hi Samvith, thanks for catching that. Links are updated now.
I did not get the "re-label where we call zero" part. It looked like you made Hbar = 0, but then you took the square root of it n the slope term, making it result in -a/4A.
It looks mathematically inconsistent, to consider Hbar to be zero only at one part. Could you explain? (Or someone that got this)
(Answering 1 year after, but I hope it helps someone) Yes, looks inconsistent, but you can interpret it as: You re-label what you consider zero in another variable, an auxiliary variable, not exactly the same as considering Hbar = 0. The operating point is still at the original H = 4, a point where there's no discontinuity. The value of the slope is calculated at H = 4 and fixed (The slope is still -a/4A). Only then you re-label it. But I agree with you that maybe another variable should be used, an auxiliary variable, to represent this re-labelling.
Thanks Brian !!
Hello, Brian if you are linearizing at H(bar) = 4 then how does H-H(bar) = H? is not H(bar) at 0
Hello. Thanks for interesting video. Can you give more detail process about step: x-xbar->x in state space equation and how simulink model and controller connect with it will look like. Thanks you so much.
thank you
Thank you!
Hello Brian! in the final equation you have gotten and when I tried to substitute in value of the operating point(H_bar, V_bar), does the left side (H_dot) has to equal to zero? I tired to substitute but I have gotten nonzero value, why?
Fantastic
how pendulum will be at equilibrium pointing straight up ?
With friction forces helping/triming a a bit? Hahaha
can someone explain this please?
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