For the last question, Answer is, Since, tan A = 1/√3 then, A=30 Therefore C=60 (∠A + ∠B + ∠C = 180) So, Sin A = 1/2 Cos C = 1/2 Sin C = √3/4 Cos A = √3/4 Therefore, (1/2 * 1/2) + (√3/4 *√3/4) = 1/4 + 3/4 = 4/4 = 1
hello sir I have a doubt. We write the ratio as A: B so in your video at 29:06 minutes u told us how to find the trigonometric ratio using an example. my doubt is can't we write that like this sin=3:5 cos=4:5 Tan=3:4.
A great question Wkt, A/B = A:B Both means the same So, in trigonometry ratios, you can better use A/B format because in our textbook we use this method. We must follow NCERT na....
Shimon sir my name is Roshan and I will watch ur videos from 3 to 4 accounts so I will adress when iam in the class and the H.W question's answer is ,AC=2 and the total solved answer is 1
hello sir. first time seeing your video. amazed by your teaching.................... answer: Sin A - 1/2 Cos A - √3/2 Sin C - 1/2 Cos C - √3/2 SinACosC+CosASinC : 1 Is It Correct Sir ????
Sir syllabus eppa mudipinga sir 😫 kashtama iruku sir Previous year paper maths la discuss pannuvingla sir please 🥺 Your sessions are superb Waiting for more sessions sir please do more sessions sir 🙏
Found answers Let ΔABC be a right-angled triangle such that tan A = 1/√3  tan A = side opposite to ∠A / side adjacent to ∠A = BC/AB = 1/√3 Let BC = k and AB = √3 k, where k is a positive integer. By applying Pythagoras theorem in ΔABC, we have AC2 = AB2 + BC2 = (√3 k)2 + (k)2 = 3k2 + k2 = 4k2 AC = 2k Therefore, sin A = side opposite to ∠A / hypotenuse = BC/AC = 1/2 cos A = side adjacent to ∠A / hypotenuse = AB/AC = √3/2 sin C = side opposite to ∠C / hypotenuse = AB/AC = √3/2 cos C = side adjacent to ∠C / hypotenuse = BC/AC = 1/2 (i) sin A cos C + cos A sin C By substituting the values of the trigonometric functions in the above equation we get, sin A cos C + cos A sin C = (1/2)(1/2) + (√3/2)(√3/2) = 1/4 + 3/4 = (1 + 3)/4 = 4/4 = 1
For the last question, Answer is,
Since, tan A = 1/√3
then, A=30
Therefore C=60 (∠A + ∠B + ∠C = 180)
So, Sin A = 1/2
Cos C = 1/2
Sin C = √3/4
Cos A = √3/4
Therefore, (1/2 * 1/2) + (√3/4 *√3/4)
= 1/4 + 3/4
= 4/4
= 1
Bro hyp is 2
👍👍👍🤟
Correct bro
I score 99 marks in my math pre board exam by your teaching ☺
Thank you for your helpful and supportive mind though sir 🔥
ME too
@@praneashbalasubramaniyan6217 can u u give tips
hello sir I have a doubt. We write the ratio as A: B so in your video at 29:06 minutes u told us how to find the trigonometric ratio using an example. my doubt is can't we write that like this
sin=3:5
cos=4:5
Tan=3:4.
A great question
Wkt,
A/B = A:B
Both means the same
So, in trigonometry ratios, you can better use A/B format because in our textbook we use this method. We must follow NCERT na....
Guy I have an doubt in last question anybody tell I found that sin A cos C +cos A sin C=(1/4)(√3/4)(1/4)what is the answer how it cam 1:00:38
sir vera level class sir
Shimon sir my name is Roshan and I will watch ur videos from 3 to 4 accounts so I will adress when iam in the class and the H.W question's answer is ,AC=2 and the total solved answer is 1
hello sir. first time seeing your video. amazed by your teaching....................
answer:
Sin A - 1/2
Cos A - √3/2
Sin C - 1/2
Cos C - √3/2
SinACosC+CosASinC : 1
Is It Correct Sir ????
@yellow-flash007 your wrong it is correct
Your mathematics session is piece of cake bro
of course
Total score throughout the session - 9/9
Athu -9/9 elna =9/9
@@lucifermanonElna illa ela
@@Imgoodnot2goodela illa illa
Me too I am in class 8
So useful sir😊
ENJOYED THE SESSION 😄🥳ADAD! 10TH SESSIONS ARE ALWAYS AMAZING🤓
My shortcut method to remember the trigonometric ratios formulas is :-
O/H , A/H , O/A , A/O ,H/A H/O.
Sin , cos , tan , cot , sec , cosec.
Numerator = O , A , O ,A ,H ,H.
Denominator = H ,H ,A ,O ,A ,O.
Vanakam sir 😊
H.w problem answer is= AC=2, sir
And answer is 1 sir ☺️
💥💥💥
Vera level sir
Awesome session sir
One of the best teacher
sir really i enjoyed this session.thankyou for your lovable session.
h/w answer AC is 2 and ans is 1
Vera lvl teaching sir ❤️🤩
sir, with your guidance i understood trigonometry very well.. Thank you so much shimon sir 🙏😇☺
🔥🔥🔥🔥
Superb
Sir syllabus eppa mudipinga sir 😫 kashtama iruku sir
Previous year paper maths la discuss pannuvingla sir please 🥺
Your sessions are superb
Waiting for more sessions sir please do more sessions sir 🙏
41:00
🙌🏻🙌🏻
Yes sir.... sample paper solve pannunga sir....
I got 9/9 sir❤thank u sir🎉very useful❤🎉
the best and friendly teacher who makes maths as a fun subject and make it more easier ❤🔥
Just luv your teaching sirrrrrrrrrrrrrr🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉🎉
Great teacher❤❤❤🎉
Me barath pls replay sir
🎉
Answer of the homework question is 1
Thank you so much sir you make maths enjoyable .
yes sir we need session on sample question paper,if possible also make session on previous year question paper also sir
Enjoyed the session sir
Homework question ans:1 sir.
23:07 Rolex moment🔥😂
Hey super ya
😂
Excellent teaching !!! Very helpful
My total pre board mark is 499/500 by your teaching sir😀😀
Eppudi bro na 400 tha
I am only 325
@@rafeeq37769 athu vandhu neriya practise panneen bro from 9th standard
@@raistararmy9342 thug bro
The best 🎉
yes sir
make more class sirrr
Answer: 1 sir
AdAd🔥🔥🔥🔥🔥🔥🔥
Super Sir
Sir your teaching one best teacher who teach which you reached I thought my friend he and me got in this chapter 16marks for 16 Thank you sir 😊❤
❤
G.O.A.T SHIMON SIR 🐐
🔥🔥🔥🔥🔥🔥🔥
Fireeeee❤️❤️❤️❤️❤️❤️
Amazing
AC is hypotenous, BC is adjacent, and A is opposite
Mass🔥🔥🔥🔥🔥
Hi sir
Found answers Let ΔABC be a right-angled triangle such that tan A = 1/√3

tan A = side opposite to ∠A / side adjacent to ∠A = BC/AB = 1/√3
Let BC = k and AB = √3 k, where k is a positive integer.
By applying Pythagoras theorem in ΔABC, we have
AC2 = AB2 + BC2
= (√3 k)2 + (k)2
= 3k2 + k2
= 4k2
AC = 2k
Therefore, sin A = side opposite to ∠A / hypotenuse = BC/AC = 1/2
cos A = side adjacent to ∠A / hypotenuse = AB/AC = √3/2
sin C = side opposite to ∠C / hypotenuse = AB/AC = √3/2
cos C = side adjacent to ∠C / hypotenuse = BC/AC = 1/2
(i) sin A cos C + cos A sin C
By substituting the values of the trigonometric functions in the above equation we get,
sin A cos C + cos A sin C = (1/2)(1/2) + (√3/2)(√3/2)
= 1/4 + 3/4
= (1 + 3)/4
= 4/4
= 1
Sir u deserve more semma teaching
fire 🔥 🔥
.
Sir answer is 1sir 🔥🔥🔥🔥
Answer by shimon sir students
Teaching 100 % understanding 200 %
Super sir
for the last question, I got 1+√3 . Am I correct or wrong?
no
@@ranjanisharvesh6446 then what is the answer
Best session sir also the formula SOH CAH TOA is best one in this lecture sir ❤
AC
yes sir
Adad🔥🔥🔥🔥🔥
Sir 2 nd sum cos = adj by hyp so 24 by 25 sir how 7 by 25 ??
Hai sir
Pranav 15:29
4:27
Fire.....
FIRE SIR
42:55
Amazing 12:55
Sir last question answers: 1
Sir
❤
1 is the answer sir.
Thanks sir
Sir , please discuss sample paper
AD^2
Sir could you please create videos for class 10 icse subjects
27:55 27:57
AC=2,Ans=1
39:55
howework ans = 1
Yes we want sample paper sir
sir please tell where we should take sample paper (official)
@prasancreations... Sample paper in Noida app and cbse official website
🎉🎉🎉
Answer 1
18:00
1/3
Sample paper discuss pannuga sir
Tan teta equal to a) 5/12
Ad^2
HW = Answer is 1
Vera level sie
H.w answer AC = 2 final answer is 1
59:44 sir joke thana pandringa 😂😂😂
❤
36:45 sah coh toa sounds like sapoata
Ad2🔥🔥🔥🔥🔥
Thanks sir 🥲
1is the answer for last question
AC is a hypotenuse
Sir circles please 🥺
Yeah... enakum venu
Good evening sir iam kayal
Answer for home work question is 1
🔥
Last question answer 1 sir