How to find a string in an array of strings in C

Source code can be found here:
code-vault.net/lesson/qwc2wv1...
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[@MuksEmmaN]

Really appreciate this video.
Your way of teaching is so powerful

[@aatishlanghee]

Hi, Thank you for this amazing video.
Can you please create complete C language tutorials playlist from beginner to advance in a practical hands on way. It would be good for us to get some hands on experience on the industry based problems.

[@CodeVault]

I'll look into it. Thanks for the recommendation!

[@kapellimestari0078]

very good

[@pcuser80]

You can also use strcasecmp does the same as strcmp but ignores the case.

[@CodeVault]

Oh cool! I didn''t even know about the strcasecmp function. Thanks!
I'm still on the fence about covering non-standard functions on the channel though (same reason why I didn't use strlwr in this video)
What do you think? Should I start covering all these non-standard yet popular functions?

[@pcuser80]

@@CodeVault Yes Please

[@bushraw66]

Thank you so much for this video.
I have a question tho, at 6:27
can't we just use else{} instead whar you wrote in line 20?

[@CodeVault]

Else for the if in the for loop you mean?

[@bushraw66]

@@CodeVault yes , instead of writing that i>=3 does it work with just an else ?

[@CodeVault]

Not really, since the message would be printed for every element that is not equal to the one you're searching

[@NoNameAtAll2]

can you repeat please the need for `input[strlen(input)-1]=0` line?
since there is already a null character, why overwrite last input char with 2nd one?

[@0llie_K]

A new line character: '
' is read as the last input char when the return key is pressed, In this instance it is not wanted and is therefore removed by replacing it with a null terminator.

[@CodeVault]

Take a look at the video I pointed to: code-vault.net/lesson/yxllgxvfmb:1603733521595
It explains this and why we use fgets instead of scanf

[@pcuser80]

@@CodeVault I use this always for removing end of line , works for windows and linux input[strcspn(input, "
")] = 0;

[@GillesHenrard]

Would a "do...while" loop with a flag variable not be cleaner than a full-fledged for loop with a break instruction?

[@CodeVault]

A bit maybe. You'd still need to have the definition of i, increment and the condition somewhere in that loop.
int i = 0;
do {
// ...
} while (i < 3 && strcmp(arr[i], input) != 0);
I could be biased but reading a for loop with a break is much easier to understand than a do...while loop that looks like this
You can use whichever you feel is right for you though!

[@GillesHenrard]

@@CodeVault I was more thinking about something like :
int i = 0, notfound = 0;
do {
notfound = strcmp(arr[i], input);
i++;
} while (i < 3 && notfound);
But as you said, except for memory or execution time constraints, only the dev's taste differs :)

[@soufianeamimi]

Can u explain about the oriented objects in c++

[@CodeVault]

Yes! I plan on making a large series about OOP

[@soufianeamimi]

@@CodeVault oooh that would be awsome

[@saurabhatre2158]

Sir video is helpful but I want to search( 4 ft × 15 inch ,0.9 21) as a whole string to be found can you help me please ( I want to use data structure too but it says _parameter error
The current program finds only till
4 ft only 4 digits i want whole string to be searched at once with data structure please see to it and send source code to improve it

[@CodeVault]

There are two options: You can either manually iterate over the string and check if the string is what you're searching for or, use a regex library (if you need to find any number in the string)

[@saurabhatre2158]

@@CodeVault
Sir, thanks for info
But please share source code
Array a={(4 ft x 15 inch, 0.93,21),(4ft x 15 inch ,0.93,21),(4ft x 12 inch),0.93,21)}
Output: (4 ft x 15 inch, 0.93,21) =>2
(4ft x 12 inch),0.93,21) =>1

[@k_ushagra]

and this is how we know you favourite fruit or colour is Orange.. 😛😜

[@shivagthegamer4933]

Thanks, but I want function of it

[@CodeVault]

You could copy everything in a function and set the array of strings as parameter and the result as a return