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In the FINISH - ARRAY , all the COMPLETED PROCESSES has been recorded , hence it mould be a 1D ARRAY or HORIZONTAL VECTOR of size 'm', where m denotes the number of simultaneously running processes on the " SINGLE PROCESSOR " instead of size'n' that only denotes the number of AVAILABLE RESOURCES connected to the SYSTEM.
I think there's a small mistake there in homework ques. The allocation for D to P4 is 4, whereas the max it wants 2. I looked this question up and found that its a typo. Actually, the allocation of D to P2 is 2 only.
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safe sequence - p1,p3,p2,p4,p5
6:26
Gem of Unacademy
@Sonu Dixit 2M better than you
p1,p3,p2,p4,p5 safe sequence
In the FINISH - ARRAY , all the COMPLETED PROCESSES has been recorded , hence it mould be a 1D ARRAY or HORIZONTAL VECTOR of size 'm', where m denotes the number of simultaneously running processes on the " SINGLE PROCESSOR " instead of size'n' that only denotes the number of AVAILABLE RESOURCES connected to the SYSTEM.
Safe sequence= p1,p4,p2,p3,p5
good and extraordinary session of the solutions of the deadlock .
thank you sir.
sir in last homework question:
IN process P4 allocation of D is greater than max.. How is that possible?
bro then kesay solve hua ye ?
That's what 😅
Yes bro I'm also confused... 🤔
Safe sequence -> p1,p3,p2,p4,p5
p1,p3,p4,p5,p2 hoga ?
57:00 "snapshot lete ho expr ession , ulte siddhe hote hai, accha Nhi lgta hai"🤣🤣🤣🤣🤣🤣
Sir : Dil sa bura lagta hai bhai
best teacher i have ever studied.❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🔥🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎😎
I think there's a small mistake there in homework ques. The allocation for D to P4 is 4, whereas the max it wants 2.
I looked this question up and found that its a typo. Actually, the allocation of D to P2 is 2 only.
thankssss
30:20-30:21 HARSH REALITY has been revealed.
56:31
p4 allocation D=4 and max D=2
Change there max D=6
then
yes sir
correct
Sir ,preparation in deadlock !
Thankyou sir
Love from igdtuw
❤❤❤❤❤
Sir how to download class pdf sir
done
Yes
3,14,12,14
33:37
6:42