PYQS on Liouville's and Identity Theorem | Fully Short Cut Tricks | CSIR NET 2011 to 2023

[@binanda1268]

THANK YOU SIR.....VIDEOS ARE VERY VERY HELPFUL

[@Strugglelife729]

We wait for your video....

[@SOHAM53]

8:23 option d is correct...as the set contains limit points.

[@Harish-Dhar-Deewan]

Limit point (-1,1) ka [-1,1]. Aayega jo ki 1 usk domain me nhi h isliye wrong hua

[@mayachetri2959]

Option b ka limit point 0 kaise hua​@@Harish-Dhar-Deewan

[@Harish-Dhar-Deewan]

​@@mayachetri2959b me f(z) me ,z=1/2 radius ka circle bnakr limit point nikalte to usk domain me aayeg isliye 0 hua

[@kawsarali1128]

@@Harish-Dhar-Deewan
but sir if I am not wrong Theorem says " if one limit point is there means it will works,"

[@danesurrahaman2746]

Sir your video is really helpful.. ♥️

[@sourabhchoudhary9497]

Apke approach se lgta hi nhi hai ki ye sb csir net ke ques hai very simple explain i love it ❤

[@ChandanKumar-dn9lz]

Most helpful video for net and GATE exam ❤

[@masterkapil6214]

Thank you sir your video very helpful and amazing

[@kmathk]

Your videos are very helpful sir

[@kmathk]

Your tips is very useful sir

[@mathematics6587]

Useful 🙏

[@pravinkamble2757]

Really awesome❤❤❤

[@seshansahoo7913]

Sir please upload video on pyq of several variables calculus of csir specially

[@mohdjuned1987]

Sir your explanation is very good. Thankyou sir.

[@dkinstituteofmathematics]

Videos are very helpful

[@thibakarrasu1786]

Thank you very well sir

[@niteshbhoi3804]

Osm....🙏🙏

[@yashrajtripathi4832]

Very useful lecture

[@nabilafathima3223]

Very clearly explained sir

[@shrawankumarpatel2148]

Thank you so much sir🙏🌷🌷🌷🙏☀️☀️☀️

[@ASHISHKumar-zu7xo]

Your vedio is help full for us

[@prasenjitroy_1792]

Please re discuss options b &d of question 1. 🙏

[@jayprajapat2016]

Thank you sir

[@RanjangamingYT7477]

1:09:2 sinz kayse polynomial hoga polynomial ka degree finite hota ha to sinz ka degree e define nhi hoga to why sinz polynomial function

[@kawsarali1128]

@8:16 could u plz check the 4th option ,,, I think its a correct option .
Thank you

[@NikitaRathee-ml6qn]

Thank you sir ...very helpful video

[@ronneysaini7763]

Thanks Sir❤❤

[@RanjangamingYT7477]

Sir 55:18 me function f ka range C-{-infinity,0} de rakha ha to (0, infinity) point skip karega na to function constant ho jayega by pickerd theorem

[@AbhishekKumar-hr3cb]

Yes, you are right...
We can't take f(z)=z^4...
Try it by taking f(z)=e^z or f(z)=(z-1)^2

[@professorragavan9783]

Sir. I have one doubt in 33:56. In option 3, 3 does not belong to the domain, |z| less than 1. Then how can we choose the given function? Can we take any value for z??

[@Realknowledge001]

Thank you so much sir 🙏

[@kmathk]

Upload more videos for csir net Dec 2023 sir

[@RanjangamingYT7477]

Thank you sir ❤❤
There some doubt please sir reply 👍👍

[@SayaranaSafar123]

48.10 ....tell us the valiid reason... function is boundes and entire they why it's not bounded ...the theorem says that entire and bounded function are constant

[@kenchappab1548]

Because in option 3 entire function is bounded on proper subset of complex plane not on complex plane this implies 3 wrong

[@is_math_hard]

Sir in the gate question in time stamp 39:55 , how limit point of Zn is 1, it is zero for all. Isn't we find limit point of images in co-domain??!!
Kindly please take a look and reply, otherwise it gets confusing

[@is_math_hard]

Continuing...
And in December '12 question in the time stamp 56:00, range of f cannot take 0, but f(z)=z^2 will take 0 as 0 belongs to the region D

[@sheemanitinsan7235]

Thank you so much sir

[@wespritual]

32:40 Sir please solve my doubt if function is f( z)=2/(3+z) then how we can say -3 is pole of f while -3 is not in the domain, and second 3 is also does not belong the domain D then how we calculate value of f(3) . By identiy theorem, if we take g(z)= 2 /(3+z) then f(z)= g(z) but g(z) have no singularity in domain, neither pole nor removebale so how -3 is pole of f(z). Kya identity theorem me function exist karne ke bad codomain se singularity check ki jati hai ya domain se , yadi domain se check hoti hai to -3 is not pole , and 3 is also does not belong the domain D fir se only option a is wright aa rha hai . Kya kare?

[@ankitathakur576]

Same doubt, plz explain

[@Siyagupta52]

Only (a) is correct

[@positivethoughts6419]

Sir in first question option d is also correct because you have given open interval.... And at 34:00 time only option a is correct and b and c option is wrong because f(3)= 1/3 is true but 3 doesn't belong in the domain D.. similar for simple pole -3 does not belong in domain D....... Please correct sir.. i am confused..

[@preetiyadav-k9i]

this men has not enough knowlege to correct this

[@AbhishekKumar-hr3cb]

Yes, only option a is correct..

[@anuproychowdhury9170]

in question( 22 minutes) , z=2 is not a simple pole cause doimain is unit disc here & domain doesnt contain 2

[@komalkapoor3488]

Sir after csir net please upload video on whole pyqs for IIT jam MA. 🙏🙏🙏🙏it's a request sir plz.

[@memansamishra8427]

Sir dec 2017 1:03 par sir n=2 lene par only a correct h baki discard ho rhe sir

[@mubashirrazaq2838]

Thankyou sir ❤

[@danesurrahaman2746]

1:09:00 csir net june 2018 ans ,I think all options are not correct 2,4

[@pubgfanblmvirat8135]

33:50 in option 3
Z not belong to domain

[@mapping2470]

Great

[@anupamsamanta6690]

Sir numerical ek sath pless 🙏

[@Ayoknyising]

Sir plz pyq of Algebra ka bhi aradonaa

[@RohitKumarYadav0516]

At 22:13 ,he ask which of the following is not correct!!

[@kmathk]

20:23 Next problem of June 2012
Question is asked only not correct sir
But you say correct options sir

[@is_math_hard]

Trigonometric functions are not polynomial!!!!!

[@ASHISHKumar-zu7xo]

Please hindi m question explain kiya kro sir

[@Wonderfullfoods]

Maximum likelihood estimate podunga sir

[@masadaprasanthkumar3858]

Grean bord please. White board is not cleared sir

[@selvarasu2314]

f(z) =sinz or cosz are entire function also it's bounded.

[@mr.rajukumar4493]

june 2011 ka solution galat hai sir answer bhi gal;at hai apka

[@professorragavan9783]

Thank you sir