दर्शाइए कि कोई भी धनात्मक विषम पूर्णांक 6q+1, 6q+3, 6q+5 के रूप का होता है | class 10 ex 1.1 q2

class 10 maths chapter 1 exercise 1.1 question 2 in hindi | वास्तविक संख्याएं प्रश्नावली 1.1 प्रश्न 2
यूक्लिड विभाजन एल्गोरिथ्म से 135 और 225 का HCF निकलना |
• यूक्लिड विभाजन एल्गोरि...
Doston aaj humne ncert maths class 10th exercise 1.1 question 2 solution and concepts ko explain kiya he jisme aap euclid division lemma se questions ko solve krte he. is prashn me humne ye darshaiye ki koi bhi dhanatmak visham purnank 6q+1 6q+3 6q+5 ke rup ka hota he. ise bahut aasan tarike se solve kiya he. sath hi humne Sam sakhya kise kahte he or visham sankhya kise kahte he is baare me bhi explain kiya or prashnavali 1.1 me euclid vibhajan prameyika ko bhi samjhaya he wo bhi bahut aasan tarike se. I hope aapko video achcha laga hoga agar aapko video achcha laga to like kijiye or aaise hi maths ke videos dekhne ke liye hamare channel explain 4u ko subscribe kijiye hum aaise hi maths class 10 exercises ke solutions aapke liye late he.
About this video :-
1) दर्शाइए कि कोई भी धनात्मक विषम पूर्णांक 6q+1, 6q+3,6q+5 के रूप का होता है
2) show that any positive odd integer 6q+1 6q+3 6q+5
3) class 10th maths chepter 1 important question
4) class 10 NCERT maths chepter 1 ex. 1.1 question 2 solution
5) class 10th 1.1 q 2 solution in hindi
6) darshaiye ki koi bhi dhanatmak visham purnank 6q+1 6q+3 6q+5 ke roop ka hota hai
7) धनात्मक विषम पूर्णांक किसे कहते हैं
8) class 10 live
9) what is positive odd integers
10) Class 10th mathematics exercise 1.1 Q 2
Time Stamps:-
00:00 Introduction
01:17 धनात्मक संख्या
02:05 सम संख्याएं किसे कहते हैं
02:36 विषम संख्याएं किसे कहते हैं
03:18 पूर्णांक क्या होता है
04:16 सम पूर्णांक और विषम पूर्णांक
07:09 Solution Part 1
08:12 यूक्लिड विभाजन प्रमेयिका
10:53 Solution Part 2
21:47 Conclusion
#Explain4u
#Class10live
#positive_odd_integer
#class10thmaths #vastaviksankhya #realnumbers #class10 #ncertmathsclass10

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