Position/Velocity/Acceleration Part 1: Definitions
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- Опубліковано 23 лип 2024
- If we are going to study the motion of objects, we are going to have to learn about the concepts of position, velocity, and acceleration. More scalars and vectors! Once we get this stuff out of the way, we can really get cooking.
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I've binged all of your kinematic videos, after feeling lost in physics 11 for ages. I can't thank you enough. I feel like it's starting to make a little more sense now.
sgutup
@@eddieflores7779 The way you're illiterate
@@tiactus haha lol
update i failed that class
You probably dont care at all but does someone know of a way to get back into an instagram account?
I stupidly lost my password. I love any tips you can offer me
Honestly, you will save my academic life - I'm doing Biomechanics this semester and in week one, my head is spinning! How do you know so much Professor Dave?!
3:32 "If they are quick little devils"
LOL
some fun in science
lol
lmao he kept the straight face perfectly
The theme song is such a meme lol
I agree
Lol
lmao
smh
When my teacher played the video the whole class started laughing at the intro
currently cramming for my upcoming college admission exams and ur videos had been SAVING me. thank u so much professor
Hey
Back off bro, or
5:01 because if it wasn't your favorite animal you would just go ahead and run it over
Lmaoo
Read this comment just as he was saying it...i am ROFL
if you find the acceleration/deceleration confusing, you're not alone. A lot of education places only use acceleration and the direction is indicated by positive or negative. They do this to avoid confusion and even though people are used to the colloquial "deceleration" once you get used to the idea of "there is only acceleration" and the direction is indicated by positive or negative, it can make it a lot easier to keep the directions straight in your head.
I am confused of why they halved acceleration when looking for the origin of x. I might need to consider changing my perspective of acceleration to understand.
Its like acceleration doesn't take effect immediately
Your explanation of understanding motion using a graph (grid) to show the starting and ending positions in order to observe the changing (+- or -) of the vector's displacement, velocity and acceleration now allows me to understand physics of motion. I hope to now pursue basic calculus.
I've got you covered for calculus too! Please check out my calculus content, it's got everything you need!
Thank you professor Dave, your explanation are more helpful in our daily life, you make us understand better what was so difficult to understand ✍️♥️
I have been searching for a proper explanation to this since long but ultimately I got it. I am highly obliged to you sir😊.
respectfully you deserve absolute toe-curling, aneurysm-inducing, eye-rolling, spiritual awakening, mind-boggling head. Thank you professor Dave.
hahhahhahahaha wtf dude😂
What the fuck bruh 😂
WHAT
bro 😭
Thank you thankyou thankyouuhh very muchh, I have a final physics exam tomorrow and u explained me a whole chapter thankuu you’re literally saving my life
I am watching all this vids for my test at 2pm today , pliz wish me luck
same time
How did it go ?
Your friend walks up the driveway like a normal person lol...I love your subtle humor
Easy, precise, and brief. Nice video, worth a year of knowledge
hey professor, could you please do a video on symmetry operations?
thanks
Thank you very much, this video really helps me with my studies
Great video, my teacher will give me extra points all thanks for this video !!
Thank's Dave for science and more, it helps the viewer comprehend the world around us.
sir i have a doubt,
if a horse pulls a cart by a certain force then according to newton 2nd law cart should also pull him with same force so how does a cart move.
check out my tutorial on newton's third law! will clear this right up.
I'm Brazilian and I love your Channel, because I study English and sciences at the same time. :)
Jonathan Augusto no one cares
Evan_ Armo shutup bro
No one cares about your comment either even armo!
Guys it’s his opinion
tbm
Very well explained!! Keep it up sir ❤
Professor coming thru with the clutch save once again
Hai.i have small doubt.i have time vs deceleration graph.i need to find speed?how to find out.please help me.
Amazing explanation!
Love your channel
Love your work, professor.
Vivid explanations ,I really admire that ,you are good at it ,....but would you give explanation for the comprehension part specially I am having trouble in the determination of the direction of the quantities displacement ,velocity and acceleration in some cases .
hi prof dave .. how can the displacement in the reverse deceleration is pointing forward and decreasing in the question in tne end of the video
Prof. Dave . in the comprehension check .. with the last motion of reverse (ac/de)celeration, should't the displacement be backward? .. please explain
How can anybody dislike this video....its great keep it up
In the comprehension questions why is reverse deceleration magnitude decreasing?
Son of a Physician
Doc ?
@M A Abhijith Did you meant to say "You're Welcome"?
Yeah, You are welcome
Cha
hands down the best videos!!! Thank you so much!!!!!!
awesome teacher thanks sir ur videos help me alot
Thank you for these videos professor
Thank you, sir!
This was really useful. Got a physics exam for grade 10, wish me luck!
Thank you very much for your work 😁😁😁
Nice man. Your small effort made a big difference in my mind❤
Hello! I'm hoping someone can help me to figure this out. How can I determine speed MPH of a pendulum that's swinging (swinging for/aft.) but independent from the moving object it's fixed on? For example, if there is a shiny compact CD hung with fishing line from an automobiles rearview mirror. Also, would a radar beam signal be more apt to bounce off the shiny CD (pendulum) than other items on the round shaped front clip of a 2003 Ford Taurus? If a car is going 30mph .....would the pendulums' forward motion combined with the actual vehicle speed being 30mph, then give a false speed reading (showing faster speed 30)? Please advise. I'd greatly appreciate any/all help. I'm very interested making this determination, but lack the means, equipment, and a good place in which to test.
Thanks a million!!!
R.L. Buddi
A pendulum hanging in a car cannot tell you speed. At best, it is an accelerometer. And it is only accurate when your acceleration is steady.
Changes in your acceleration will cause it to swing back and forth, and not give an accurate readout to the details of how acceleration changes. Actual accelerometers have a micro-electro mechanical system that is a tiny mass on a spring that is critically damped, so it minimizes as much error due to the changing acceleration as possible.
this explained it way better than my science teacher last year
You are great awesome and brilliant teacher. You already helped me and thank you from Sweden.
The best explanation video ever
Terimakasih untuk Professor Dave dan untuk orang yang menerjemahkan subtitlenya ke dalam Bahasa Indonesia. Salam dari Indonesia.
wonderful work!!
I have this written in my book, can someone explain it to me.
"when brakes are applied then the direction of velocity and acceleration are opposite to each other"
well so if you are moving in the forward direction you have a positive velocity, and if you hit the brakes the acceleration will be in the negative direction, so until you stop completely you'll have a decreasing but positive velocity and a negative acceleration, opposite directions.
@@ProfessorDaveExplains thank you so much
@@maryamzaheer2202 jazakAllahu khayr, thanky you asking this type of informative question. Via dave's explanation I remembered. Thanks.
watching all of these the night before my physics 11 final. its so easy to understand
I WISH I FOUND THIS SOONER OMFG ❤❤
This is amazing!!!
Excellent teaching method 👏
Thank you for sharing this teaching us about physics ❤❤❤❤
Get this man to a million
I understood more after watching your video.
thankyouu
Great explaining
Hi Professor 😊 I’d like to ask, for the Checking Comprehension part, how is the acceleration for Initial Decelaration “backward” and for reverse deceleration “forward”? Kindly enlighten me, Sir. Thank you so much and apologies for the inconvenience. 😊
Reverse deccelaration means the car has changed its initial direction means Velocity vector become backward and as we have to deccelarate it accelration vector become forward(so that velocity vector in forward direction opposes velocity vector in backward direction)
wouldn't displacement be backwards for c and d is the car is travelling in the opposite direction?
you explained very well brother
I have a question.
In the answers of the check your comprehension, the answer for reverse deceleration and reverse acceleration states that the Displacement is moving forward and the magnitude is decreasing.
Shouldn't the displacement be moving backwards, and the magnitude decreasing too? Since we're reversing back towards our starting location, I thought the displacement's vector would be backwards to where its original starting point was.
so don't forget that displacement will always begin from your starting point, so the only way for it to become negative is for you to go past where you started and begin traveling in the opposite direction from there. so it's not that displacement is moving forward, it's just that it's always pointing forward, until you get back to your starting point, where displacement is zero.
Oscar Lim I was thinking the same thing
@@ProfessorDaveExplains
In reverse acceleration and reverse deacceleration displacement is in forward and velocity is in backward directions
How can it be?
The direction of velocity will be in the direction of displacement isn't it?
when something is slowing down but still moving in the forward direction, only the acceleration is negative
@@ydhanusree4126 because by 'displacement' here he meant 'overall displacement (ie.from displacement from the starting position). So if you look at the position of body even during reverse acceleration/deceleration, the position (ie. the overall displacement) of the body is forward to the starting point.
Though the instantenous displacemnt will be in the backward direction therefor the instantenous velocity is also in the backward direction.
The catch here is that here according to Prof
Displacement = Overall displacement;
Velocity = Instantenous Velocity
I guess he should've been just a bit more clear about that. Nevertheless a sweet and simple way of explaining by him.
Thank you...executive explanation!!!!!!
👍👍great ..finaly i get it right
Thanks you for your clearly explanation
now i got the proper difference between acceleration and velocity 👍👍👍👍👍
Thank you very much for the amazing explanation!
But may someone explain why for stage c and d(reverse acceleration and reverse deceleration)
For D (Displacement Vector) the direction is Forward instead of backward?
Because I thought you are going back to the original starting point that's why should be backward instead？ Thank you
^^^^ yes
It still begins from your starting point.
Man, you need some serious cramming.
good video for learning
Why i found a formula of average velocity in my cbse book : v + u / 2. And i found another formula of average velocity displace / time taken.. Can u tell me which one satisfy all the examples that u have given ??
average velocity = (u+v)/2
(Where 'u' here is the initial velocity and 'v' is the final velocity) if and only if velocity is constant.
average velocity = displacement/(change in time)
is always true, whether or not your velocity is constant.
why is displacement vector positiv for revers path, when the cars is going back?
Because displacement is a measure of how far the car has moved in a particular direction, in this case forwards. As the car reverses, its forward displacement from its original position gradually decreases until it is back where it started. If it continued reversing from here, then the direction would change to backwards.
Can we know the distance needed for a car to reach a certain speed from knowing how much time it needs to reach that speed ( for example bugatti the fastest car in the world need 3 seconds to reach 100km/h so i want to know the distance traveled in this 3 seconds by the car ?
what is the Solving motion problem in the video ?
Wow I really impressed
I have a question will direction of displacement change in uniform velocity. Also velocity means rate of change of displacement does it mean that both direction and magnitude of displacement change
Yes , direction of displacement can be changed in uniform velocity. Suppose a body is moving in uniform velocity on x-axis from negative x-axis to positive x-axis. Till is crosses the origin , its displacement is negative and after crossing the origin its displacement is positive.
Not necessarily. Velocity is vector quantity having magnitude and direction. It is defined as rate of change of position with respect of time. If body position and direction , or any of both changes , we can say body has velocity. For details watch Path Length and Displacement, Average Velocity on PhysicsNama.
Wow sir it cleared my doubts 😀
I have a question with regards to c and d where now we are reversing
Why is it that The displacement vector is forward and not backward
Because the displacement in the problem is measured relative to your original starting point, rather than relative to the starting point of the interval. You never touch the negative x-positions in this example, so your displacement is never negative.
For the last question, the velocity vector isn't backwards, it is decreasing, until the car is reversing right?
well the last question is talking about the part where the car is already going the other way so the velocity vector is negative that whole time
This single video taught me more than the public school system
Now I know, because in computation, I was confused about the difference since velocity and acceleration are both speeds, something like that.
You are my hero!!!!! Thank you so much!!
Can someone explain why motion is defined as change in position with respect to time and not space?
You should be in charge of a government agency somewhere and/or someday. This is sort of kind of like the re-beginning of an Italian Renaissance. It comprises the acculumation of and review of all ascertained scientific fundamentals, put in a more visible and comprehensive form. Added details is the success to these videos.
ooh neo-italian renaissance! i like the sound of that.
Thanks a lot man!
Got an IGCSE exam tomorrow wish me luck
did u passs?
Naveen Sundar Thanks for asking, I actually got full mark ^_^
@@goldensmith9954 bro I wanna ask something ,can l?
excellent explain.
Very Clear! Very Well Done :)
Never understood why you put the square in s^2 in that equation. But when you put it in English the light just turned on. Thanks.
English was my best subject in school and math was my worst, so I felt this.
Reverse acceleration has a forward direction displacement does not make much sense. So does this mean the direction of the object itself is the direction of the arrow, not the direction of the velocity? 6:58
and of course same question applies to reverse deceleration forward arrow
Thank you for making it less complicated than it was explained back then in school😂
Very good ✌️
it was so helpful
Thank you so much
thank you sir you are a god gifted
Thank you thank you so much!!!
WHERE CAN I DOWNLOAD THIS VIDEO
Why S=vt and S= Ut+1/2 at2 dont get same distance when acceleration 9.8
Kmaal I understand goodly everything bt have some confusion in acceleration
Is Low of acceleration same thing as acceleration?
What if I dont like skunks? Should I run it off?
If we need to calculate the speed of free fall object ,,how .......!!!!!
very helpful :D
I'm watching this for my final exam today. Wish me good luck, guys!
Prof. Dave, in Checking Comprehension section, why are the acceleration always constant?
Same question....
@@zarishiftikhar5520 See my response
There isn't enough information to know for sure that acceleration is constant, in the given problem. To keep it simple, introductory kinematics assumes constant acceleration unless otherwise specified.
The end questions were outclass
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I have a question can the acceleration be constant such that it only affects the direction of velocity but not its magnitude.
Depends on whether you just mean magnitude of acceleration, or acceleration in its full vector form. Because it is only when acceleration is perpendicular to velocity, that it exclusively causes a change in direction of velocity. This is called centripetal acceleration.
One example of a constant acceleration vector, is projectile motion in a uniform gravitational field. Throw a ball in a direction that is perfectly horizontal. Initially, the acceleration is perpendicular to the velocity, and only causes a change in direction. But once you let the effects of that acceleration accumulate, the ball starts descending, and the velocity is no longer perfectly horizontal. Due to the fact that part of velocity now aligns with the acceleration, acceleration causes a change in speed in addition to a change in direction. There is only an instantaneous point, where the acceleration is purely centripetal, without also being tangential.
In uniform circular motion, the acceleration is constant in magnitude, and so is the speed. But both the acceleration and speed have to change direction constantly, so that acceleration is always perpendicular to velocity. These two kinematics quantities remain constant in magnitude, but not constant in direction. Because they are vector quantities, it is incorrect to call them constant if direction is changing.
A big yes
This was a great video but it did kind of leave me asking myself what displacement actually is. For those also confused it's the position in reference to the origin, so if I travel 4 meters to the right from the bus stop and one meter to the left, the distance traveled would be 5 meters but the displacement would be three meters to the right since that is where you are relative the bus stop (regardless of how you got there).
Yeah I thank that's what displacement is
this was really helpful thanksss