Knapsack Problem using Dynamic Programming Simple Approach | Dynamic Programming | Lec 67 | DAA
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- Опубліковано 1 лип 2023
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mujhe starting me laga nhi tha ki mam itna acche se explain karengi , Thank you mam
easy method to solve this problem.Tq but this problem very much big problem in DAA so you have to explain using the formula
U made it easy mam❤
It was a clean and simple explanation, thanks for sharing this valuable video, ma'am.
Very well explained mam....and thank you for making us understood ❤️
Thankyou so much maam , I have an exam tomorrow and this was a relief 👍👍
Easily understood ❤❤
Thanks, just saved me
thanks a lot ! ma'am
If we get same optimal values at the end in profit table, which we have to consider?
When j value is 2 then y can’t we take item 4 which has 15$ profit
Thank you
can we write only this in exam or we have to use formula?
Mam solve for this w(7,3,4,5) p(42,12,40,25) plz slove this
It's very helpfull
Easy
What if capacity is 20 ...then in table how to take i values
Same doubt
In that case you will be adding all elements to maximize profit . So no two vertical entries will be same ig
Thnks mam tomorrow is my exam
jai VTU
Not understood😢