b²-4ac is set to zero because, The value 2x²n+72x+17+n² is obtained from the square of (x²+n). Since the value arises from the square of an expression the roots will be real and equal. I can't figure out a better way to explain you, hope this is useful
All the steps are explained in very detailed manner, thanks
Very well explained
Nice explanation
Superb
❤❤❤❤
Good teaching method
its very nice to watch this problem
4:08 not sure why b^2 - 4 a c is set to 0? That will simplify the quadratic formula, but not sure why we can assume this is true?
b²-4ac is set to zero because,
The value 2x²n+72x+17+n² is obtained from the square of (x²+n). Since the value arises from the square of an expression the roots will be real and equal. I can't figure out a better way to explain you, hope this is useful
It's genuine one b trusted on solution
nice question here
All steps are correct
Simplification is correctly done
❤(x^4)^2 ➖ (72)^2 ➖ 17 {x^16 ➖51 82} ➖ 17=5166 ➖( 17)^2={5166 ➖ 289}= 4877 6^8000^77 6^877^1 6^8^1^1 3^2^2^3 3^1^1^1^2 32(x ➖ 3x+2).