Dude, you failed math at 03:00. In general, log(a) - log(b) ≠ log(a)/log(b) . Discard that line, and continue with log(a) - log(b) = log(a/b) . This is the 2nd video in which you failed miserably.
Using the base conversion rule, we have: log(27)/log(a) + log(4)/log(b) = 5; a, b > 0; a, b ≠ 1 log(3³)/log(a) + log(2²)/log(b) = 5 3*log(3)/log(a) + 2*log(2)/log(b) = 5 There's an infinite number of solutions. An obvious integer solution is a = 3, b = 2. But I can find many others, such as: a = 1/3, b = ⁴√2 a = √3, b = 1/4; a = 27, b = √2; b = 4, a = ⁴√27; ... If a = b, we have log(27*4) = log(a⁵), or a = b = ⁵√108 .
You are the best teacher ever I like your teachings Mr sichamba
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Wonderful, Sir, Salaams from Zanzibar
❤❤ Namibia 🇳🇦
You helped me a lot God bless you
I passed G12 because of your teaching and here am at a certain college again watching you
Good work
A best teacher with clear explanation may God bless your profession
very nce explaination
I've been watching your videos and they're really helpful 🤗
Sir i ❤thr way you teach
God bless you 🙏 i need advice on how to study mathematics since i am at home Mr sichamba
Nice 👍
Sir you should do more of this we have it in college foundation of mathematics
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Thank you teacher godblessyou
Thank you very much sir
hello sir its Deborah from Dream Chalom .. ive been following you and i watch your videos , they are really helpful
Thanks so much Deborah, call me on 0969175701
@jacobsichambaonlinemath5090 iam in Tanzania
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Same here sir
Go😂d job
My first time to see such a question😢😢
My first time seeing this topic
Me too
God bless you sir, where do you live?
Kenya🇰🇪
Ok sir this topic even if it can come in my Gce exam I can fail 😂😂😂😂
How and why
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2*x + 1 = 9*(3*x - 1), x > 1/3
10 = 25*x
x = 2/5 = 0.4
Dude, you failed math at 03:00. In general, log(a) - log(b) ≠ log(a)/log(b) . Discard that line, and continue with log(a) - log(b) = log(a/b) . This is the 2nd video in which you failed miserably.
This topic is new to me
The same here
@@blackwellmumbi3547me Matilda too
The second red line on your first progress is wrong.. log a - log b is not equal to (log a)/(log b). It's log(a/b)
You erased it then
Why does the positive sign changes to negative
What is this topic??
Pls sir slove loga 27+ logb 4 = 5
Ans 5
Using the base conversion rule, we have:
log(27)/log(a) + log(4)/log(b) = 5; a, b > 0; a, b ≠ 1
log(3³)/log(a) + log(2²)/log(b) = 5
3*log(3)/log(a) + 2*log(2)/log(b) = 5
There's an infinite number of solutions. An obvious integer solution is a = 3, b = 2. But I can find many others, such as:
a = 1/3, b = ⁴√2
a = √3, b = 1/4;
a = 27, b = √2;
b = 4, a = ⁴√27;
...
If a = b, we have log(27*4) = log(a⁵), or a = b = ⁵√108 .
My way of solution ▶
log₃(2x+1)= 2+ log₃(3x-1)
log₃(2x+1) - log₃(3x-1) = 2
log₃ [(2x+1)/(3x-1)] = 2
3ˡᵒᵍ₃ [⁽²ˣ⁺¹⁾/⁽³ˣ⁻¹⁾] = 3²
(2x+1)/(3x-1)= 9
27x-9= 2x+1
25x= 9+1
25x= 10
x= 10/25
x= 2/5
why repeat same line?
Sir this is under which topic?
Logarithmic equation
Am very confused sir which topic is this
Logarithms
Correction examination for 2024
O .k
O.K.
=>2x+1/(3x-1)=9=>27x-9=2x+1=>25x=10=>x=10/25=0.4 ans
Too long
Fanya fupi
That's what she said!