Algorithms Explained: Computational Complexity

[@rampravesh4065]

the best explanation of computational complexity. Thank you very much.

[@RyanAndersonTechnical]

Great summary and refresh - Thanks for posting. 🙏

[@ivannuzhyn4668]

The best explanation I found on youtube. Thanks a lot, finally understand it:)

[@femloh]

Short and Excellent. I finally get this now. Very straightforward. Thank You.

[@Vartierer]

Really well explained, thank you

[@salimdellali1814]

very helpful, you helped me refresh my knowledge about comlexity, clearly explained, to the point, short and concise. You have my like

[@felipeazevedo2279]

Very helpful content! Easy to understand, right to the point! Thank you so much for posting this, +1 sub!

[@peters5171]

Very helpful! Thank you very much

[@muratseker6406]

thank you for the series !

[@juliosguido1992]

incredible video, thanks

[@proterotype]

Another home run. I'm finding Data Daft is my go-to if there's a choice between content creators

[@Swangorapofficial]

Thanks for the video!

[@marclennardcolina6033]

Very well-explained! Kudos!

[@Kokurorokuko]

You didn't mention O(sqrt(2)) which is rare but also important. It grows faster than O(log(n)) but slower than O(n)

[@codeZarathustra]

Great video, thank very much!

[@theoryofmind_music]

Awesome video! Thank you

[@shashikantdivekar7839]

Very useful and well explained. Thank you.

[@jacklee6106]

Great stuff. Please do more leetcode contents. Keep it up! thanks :D

[@yesyas5972]

Nice video

[@eva42sh]

great explanation

[@shahbajsingh4228]

Great explanations

[@tomaspiskule3048]

useful explanation, thanks

[@mareksmidrkal9754]

Best explanation ever. Thanks ! @.@

[@jas.moreira]

Thank you!

[@SkielCast]

Isn't traveling salesman a O(n!) problem? I think the backpack problem was O(2^n)

[@DataDaft]

I believe brute force solutions to it are O(n!) but better solutions that use methods like dynamic programming are exponential times a polynomial factor ~O(2^n * n²) which is usually just described as being in the class of exponential. You can find various articles on this: medium.com/basecs/speeding-up-the-traveling-salesman-using-dynamic-programming-b76d7552e8dd

[@SkielCast]

@@DataDaft Thank you so much for your answer and for the article! The video was awesome

[@MatthewGDunlap]

Thanks.

[@eva42sh]

great explanation